Explanation Given information: ( 1 ⋅ 2 3 ⋅ 4 ) ( 4 ⋅ 5 6 ⋅ 7 ) ( 6 ⋅ 7 8 ⋅ 9 ) ⋯ ( m ⋅ ( m + 1 ) ( m + 2 ) ⋅ ( m + 3 ) ) Calculation: We note that the product contains factors of the form ( k ⋅ ( k + 1 ) ( k + 2 ) ⋅ ( k + 3 ) ) for k = 1 , 4 , 6 , … , m ∏ k = 1 , 4 , 6 , … , m ( k ⋅ ( k + 1 ) ( k + 2 ) ⋅ ( k + 3 ) ) In this case m = 1 and thus the sum contains then only the terms k = 1 (as the product is from 1 to m for some integers)

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Author: EPP, Susanna S.

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Chapter 5.1, Problem 36ES

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Evaluate the summations and products in (1⋅23⋅4)(4⋅56⋅7)(6⋅78⋅9)⋯(m⋅( m+1)( m+2)⋅( m+3)).

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Chapter 5.1, Problem 35ES

Chapter 5.1, Problem 37ES

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Chapter 5 Solutions

Discrete Mathematics With Applications

Ch. 5.1 - The notation k=xnnak is read”_________”Ch. 5.1 - The expanded from of k=mnak is _____.Ch. 5.1 - The value of a1+a2+a3x=xn+...+an when n=2 is...Ch. 5.1 - The notation k=mnak is read”______”Ch. 5.1 - If n is a positive integer, then n!=_________Ch. 5.1 - k=nnckck=mnbk=Ch. 5.1 - (k=mnak)(k=mnbk)=Ch. 5.1 - Write the first four terms of the sequences...Ch. 5.1 - Write the first four terms of the sequences...Ch. 5.1 - Write the first four terms of the sequences...

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Evaluate the summations and products in ( 1 ⋅ 2 3 ⋅ 4 ) ( 4 ⋅ 5 6 ⋅ 7 ) ( 6 ⋅ 7 8 ⋅ 9 ) ⋯ ( m ⋅ ( m + 1 ) ( m + 2 ) ⋅ ( m + 3 ) ) .

Solution Summary: The author evaluates the summations and products in (13cdot 4), m, , and

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Evaluate the summations and products in (1⋅23⋅4)(4⋅56⋅7)(6⋅78⋅9)⋯(m⋅( m+1)( m+2)⋅( m+3)).

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Chapter 5 Solutions