Explanation Given Information: The provided inequalities are − 3 x + 2 y ≤ 5 , 3 x − 2 y ≤ 6 , x ≤ 2 y , x ≥ 0 and y ≥ 0 Graph: Consider the provided inequalities are, − 3 x + 2 y ≤ 5 , 3 x − 2 y ≤ 6 , x ≤ 2 y , x ≥ 0 and y ≥ 0 , Consider the inequality − 3 x + 2 y ≤ 5 Assume the equation as, − 3 x + 2 y = 5 Now, substitute the values of x in order to get the corresponding values of y and sketch the graph of the line. For x = 0 − 3 ( 0 ) + 2 y = 5 2 y = 5 y = 5 2 Therefore, the point is ( 0 , 5 2 ) For x = − 5 3 − 3 ( − 5 3 ) + 2 y = 5 2 y = 0 y = 0 Therefore, the point is ( − 5 3 , 0 ) For x = 1 − 3 ( 1 ) + 2 y = 5 2 y = 8 y = 4 Therefore, the point is ( 1 , 4 ) . The points for the equation − 3 x + 2 y = 5 are as follows: x y ( x , y ) 0 5 2 ( 0 , 5 2 ) − 5 3 0 ( − 5 3 , 0 ) 1 4 ( 1 , 4 ) The graph of the inequality is as follows: Hence, the boundary points for the equation are ( − 1.66 , 0 ) and ( 0 , 2.5 ) . Consider the inequality, 3 x − 2 y ≤ 6 Assume the equation as, 3 x − 2 y = 6 Now, substitute the values of x in order to get the corresponding values of y and sketch the graph of the line. For x = 0 3 ( 0 ) − 2 y = 6 − 2 y = 6 y = − 3 Therefore, the point is ( 0 , − 3 ) . For x = 2 3 ( 2 ) − 2 y = 6 − 2 y = 0 y = 0 Therefore, the point is ( 2 , 0 ) . For x = 1 , 3 ( 1 ) − 2 y = 6 − 2 y = 3 y = − 3 2 Therefore, the point is ( 1 , − 3 2 ) . The points for the equation 3 x − 2 y = 6 are as follows: x y ( x , y ) 0 − 3 ( 0 , − 3 ) 2 0 ( 2 , 0 ) 1 − 3 2 ( 1 , − 3 2 ) The graph of the inequality is as follows:

Bundle: Finite Mathematics, 7th + WebAssign Printed Access Card for Waner/Costenoble's Finite Mathematics, 7th Edition, Single-Term

7th Edition

ISBN: 9781337604956

Author: Waner

Publisher: CENGAGE L

See similar textbooks

Videos

Question

Chapter 5.1, Problem 23E

To determine

To graph: The inequalities $−3x+2y≤5, 3x−2y≤6, x≤2y, x≥0 and y≥0$ and also check whether the region of the inequalities are bounded or unbounded and find the coordinates of all the corner points if possible.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 5.1, Problem 22E

Chapter 5.1, Problem 24E

Students have asked these similar questions

11:48 SS retry this question below lll 43% A communications tower is located at the top of a steep hill, as shown. The angle of inclination of the hill is 77°. A guy wire is to be attached to the top of the tower and to the ground, 102 ft downhill from the base of the tower. The angle formed by the guy wire is 9°. Find the length of the cable required for the guy wire. 9° 102 ft 77° NOTE: The picture is NOT drawn to scale. length of guy-wire = ft Enter your answer as a number; your answer should be accurate to 2 decimal places. Question Help: Video Submit Question Jump to Answer |||

How come that I marked ?

Under certain conditions, the number of diseased cells N(t) at time t increases at a rate N'(t) = Aekt, where A is the rate of increase at time 0 (in cells per day) and k is a constant. (a) Suppose A = 60, and at 3 days, the cells are growing at a rate of 180 per day. Find a formula for the number of cells after t days, given that 200 cells are present at t = 0. (b) Use your answer from part (a) to find the number of cells present after 8 days. (a) Find a formula for the number of cells, N(t), after t days. N(t) = (Round any numbers in exponents to five decimal places. Round all other numbers to the nearest tenth.)

Chapter 5 Solutions

Bundle: Finite Mathematics, 7th + WebAssign Printed Access Card for Waner/Costenoble's Finite Mathematics, 7th Edition, Single-Term

Ch. 5.1 - In Exercises 1-26, sketch the region that...Ch. 5.1 - In Exercises 1-26, sketch the region that...Ch. 5.1 - In Exercises 1-26, sketch the region that...Ch. 5.1 - In Exercises 1-26, sketch the region that...Ch. 5.1 - In Exercises 1-26, sketch the region that...Ch. 5.1 - Prob. 6E Ch. 5.1 - In Exercises 1-26, sketch the region that...Ch. 5.1 - In Exercises 1-26, sketch the region that...Ch. 5.1 - Prob. 9E Ch. 5.1 - In Exercises 1-26, sketch the region that...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.

To graph: The inequalities − 3 x + 2 y ≤ 5 , 3 x − 2 y ≤ 6 , x ≤ 2 y , x ≥ 0 and y ≥ 0 and also check whether the region of the inequalities are bounded or unbounded and find the coordinates of all the corner points if possible.

Solution Summary: The author analyzes the inequality -3x+2yle 5,3x-2y

Videos

To graph: The inequalities $−3x+2y≤5, 3x−2y≤6, x≤2y, x≥0 and y≥0$ and also check whether the region of the inequalities are bounded or unbounded and find the coordinates of all the corner points if possible.

Want to see the full answer?

Chapter 5 Solutions