ORGANIC CHEMISTRY W/ALEKS
ORGANIC CHEMISTRY W/ALEKS
6th Edition
ISBN: 9781264905430
Author: SMITH
Publisher: MCG CUSTOM
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Chapter 5.1, Problem 1P
Interpretation Introduction

Interpretation: An explanation corresponding to the fact that cellulose is water insoluble by considering its three-dimensional structure is to be stated.

Concept introduction: Carbohydrates are polyhydroxy aldehyde and ketones, with an empirical formula Cm(H2O)n. Glucose is a monosaccharide (or simple sugar) having a molecular formula of C6H12O6.

Cellulose is an insoluble complex carbohydrate i.e. polysaccharide consisting of a large number of glucose units. It is a linear polymer of β-D-glucose and the basic structural component of plant cell walls. It is also an excellent fiber.

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Draw the major organic substitution product or products for (2R,3S)-2-bromo-3-methylpentane reacting with the given nucleophile. Clearly drawn the stereochemistry, including a wedged bond, a dashed bond and two in-plane bonds at each stereogenic center. Omit any byproducts. Bri CH3CH2O- (conc.) Draw the major organic product or products.
Tartaric acid (C4H6O6) is a diprotic weak acid. A sample of 875 mg tartaric acid are dissolved in 100 mL water and titrated with 0.994 M NaOH. How many mL of NaOH are needed to reach the first equivalence point? How many mL of NaOH are needed to reach the second equivalence point?
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