CALCULUS EARLY TRANSCENDENTALS W/ACHIEVE
4th Edition
ISBN: 9781319057664
Author: Rogawski
Publisher: MAC HIGHER
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Question
Chapter 5, Problem 96CRE
To determine
(a)
To calculate:
The times when the particle returns to the origin in the first 12 seconds.
To determine
(b)
To calculate:
Theparticle maximum distance from the origin.
To determine
(c)
To calculate:
The particle’s maximum distance to the left of the origin.
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Students have asked these similar questions
A function is defined on the interval (-π/2,π/2) by this multipart rule:
if -π/2 < x < 0
f(x) =
a
if x=0
31-tan x
+31-cot x
if 0 < x < π/2
Here, a and b are constants. Find a and b so that the function f(x) is continuous at x=0.
a=
b= 3
Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a.
f(x) = (x + 4x4) 5,
a = -1
lim f(x)
X--1
=
lim
x+4x
X--1
lim
X-1
4
x+4x
5
))"
5
))
by the power law
by the sum law
lim (x) + lim
X--1
4
4x
X-1
-(0,00+(
Find f(-1).
f(-1)=243
lim (x) +
-1 +4
35
4 ([
)
lim (x4)
5
x-1
Thus, by the definition of continuity, f is continuous at a = -1.
by the multiple constant law
by the direct substitution property
1. Compute
Lo
F⚫dr, where
and C is defined by
F(x, y) = (x² + y)i + (y − x)j
r(t) = (12t)i + (1 − 4t + 4t²)j
from the point (1, 1) to the origin.
Chapter 5 Solutions
CALCULUS EARLY TRANSCENDENTALS W/ACHIEVE
Ch. 5.1 - Prob. 1PQCh. 5.1 - Prob. 2PQCh. 5.1 - Prob. 3PQCh. 5.1 - Prob. 4PQCh. 5.1 - Prob. 5PQCh. 5.1 - Prob. 1ECh. 5.1 - Prob. 2ECh. 5.1 - Prob. 3ECh. 5.1 - Prob. 4ECh. 5.1 - Prob. 5E
Ch. 5.1 - Prob. 6ECh. 5.1 - Prob. 7ECh. 5.1 - Prob. 8ECh. 5.1 - Prob. 9ECh. 5.1 - Prob. 10ECh. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Prob. 16ECh. 5.1 - Prob. 17ECh. 5.1 - Prob. 18ECh. 5.1 - Prob. 19ECh. 5.1 - Prob. 20ECh. 5.1 - Prob. 21ECh. 5.1 - Prob. 22ECh. 5.1 - Prob. 23ECh. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.1 - Prob. 27ECh. 5.1 - Prob. 28ECh. 5.1 - Prob. 29ECh. 5.1 - Prob. 30ECh. 5.1 - Prob. 31ECh. 5.1 - Prob. 32ECh. 5.1 - Prob. 33ECh. 5.1 - Prob. 34ECh. 5.1 - Prob. 35ECh. 5.1 - Prob. 36ECh. 5.1 - Prob. 37ECh. 5.1 - Prob. 38ECh. 5.1 - Prob. 39ECh. 5.1 - Prob. 40ECh. 5.1 - Prob. 41ECh. 5.1 - Prob. 42ECh. 5.1 - Prob. 43ECh. 5.1 - Prob. 44ECh. 5.1 - Prob. 45ECh. 5.1 - Prob. 46ECh. 5.1 - Prob. 47ECh. 5.1 - Prob. 48ECh. 5.1 - Prob. 49ECh. 5.1 - Prob. 50ECh. 5.1 - Prob. 51ECh. 5.1 - Prob. 52ECh. 5.1 - Prob. 53ECh. 5.1 - Prob. 54ECh. 5.1 - Prob. 55ECh. 5.1 - Prob. 56ECh. 5.1 - Prob. 57ECh. 5.1 - Prob. 58ECh. 5.1 - 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Prob. 23ECh. 5.5 - Prob. 24ECh. 5.5 - Prob. 25ECh. 5.5 - Prob. 26ECh. 5.5 - Prob. 27ECh. 5.5 - Prob. 28ECh. 5.5 - Prob. 29ECh. 5.5 - Prob. 30ECh. 5.5 - Prob. 31ECh. 5.5 - Prob. 32ECh. 5.5 - Prob. 33ECh. 5.5 - Prob. 34ECh. 5.5 - Prob. 35ECh. 5.5 - Prob. 36ECh. 5.5 - Prob. 37ECh. 5.5 - Prob. 38ECh. 5.5 - Prob. 39ECh. 5.5 - Prob. 40ECh. 5.5 - Prob. 41ECh. 5.5 - Prob. 42ECh. 5.5 - Prob. 43ECh. 5.5 - Prob. 44ECh. 5.5 - Prob. 45ECh. 5.5 - Prob. 46ECh. 5.5 - Prob. 47ECh. 5.5 - Prob. 48ECh. 5.5 - Prob. 49ECh. 5.5 - Prob. 50ECh. 5.5 - Prob. 51ECh. 5.5 - Prob. 52ECh. 5.5 - Prob. 53ECh. 5.5 - Prob. 54ECh. 5.5 - Prob. 55ECh. 5.5 - Prob. 56ECh. 5.5 - Prob. 57ECh. 5.5 - Prob. 58ECh. 5.6 - Prob. 1PQCh. 5.6 - Prob. 2PQCh. 5.6 - Prob. 3PQCh. 5.6 - Prob. 1ECh. 5.6 - Prob. 2ECh. 5.6 - Prob. 3ECh. 5.6 - Prob. 4ECh. 5.6 - Prob. 5ECh. 5.6 - Prob. 6ECh. 5.6 - Prob. 7ECh. 5.6 - Prob. 8ECh. 5.6 - Prob. 9ECh. 5.6 - Prob. 10ECh. 5.6 - Prob. 11ECh. 5.6 - Prob. 12ECh. 5.6 - Prob. 13ECh. 5.6 - Prob. 14ECh. 5.6 - Prob. 15ECh. 5.6 - Prob. 16ECh. 5.6 - Prob. 17ECh. 5.6 - Prob. 18ECh. 5.6 - Prob. 19ECh. 5.6 - Prob. 20ECh. 5.6 - Prob. 21ECh. 5.6 - Prob. 22ECh. 5.6 - Prob. 23ECh. 5.6 - Prob. 24ECh. 5.6 - Prob. 25ECh. 5.6 - Prob. 26ECh. 5.6 - Prob. 27ECh. 5.6 - Prob. 28ECh. 5.6 - Prob. 29ECh. 5.6 - Prob. 30ECh. 5.6 - Prob. 31ECh. 5.7 - Prob. 1PQCh. 5.7 - Prob. 2PQCh. 5.7 - Prob. 3PQCh. 5.7 - Prob. 1ECh. 5.7 - Prob. 2ECh. 5.7 - Prob. 3ECh. 5.7 - Prob. 4ECh. 5.7 - Prob. 5ECh. 5.7 - Prob. 6ECh. 5.7 - Prob. 7ECh. 5.7 - Prob. 8ECh. 5.7 - Prob. 9ECh. 5.7 - Prob. 10ECh. 5.7 - Prob. 11ECh. 5.7 - Prob. 12ECh. 5.7 - Prob. 13ECh. 5.7 - Prob. 14ECh. 5.7 - Prob. 15ECh. 5.7 - Prob. 16ECh. 5.7 - Prob. 17ECh. 5.7 - Prob. 18ECh. 5.7 - Prob. 19ECh. 5.7 - Prob. 20ECh. 5.7 - Prob. 21ECh. 5.7 - Prob. 22ECh. 5.7 - Prob. 23ECh. 5.7 - Prob. 24ECh. 5.7 - Prob. 25ECh. 5.7 - Prob. 26ECh. 5.7 - Prob. 27ECh. 5.7 - Prob. 28ECh. 5.7 - Prob. 29ECh. 5.7 - Prob. 30ECh. 5.7 - Prob. 31ECh. 5.7 - Prob. 32ECh. 5.7 - Prob. 33ECh. 5.7 - Prob. 34ECh. 5.7 - Prob. 35ECh. 5.7 - Prob. 36ECh. 5.7 - Prob. 37ECh. 5.7 - Prob. 38ECh. 5.7 - Prob. 39ECh. 5.7 - Prob. 40ECh. 5.7 - Prob. 41ECh. 5.7 - Prob. 42ECh. 5.7 - Prob. 43ECh. 5.7 - Prob. 44ECh. 5.7 - Prob. 45ECh. 5.7 - Prob. 46ECh. 5.7 - Prob. 47ECh. 5.7 - Prob. 48ECh. 5.7 - Prob. 49ECh. 5.7 - Prob. 50ECh. 5.7 - Prob. 51ECh. 5.7 - Prob. 52ECh. 5.7 - Prob. 53ECh. 5.7 - Prob. 54ECh. 5.7 - Prob. 55ECh. 5.7 - Prob. 56ECh. 5.7 - Prob. 57ECh. 5.7 - Prob. 58ECh. 5.7 - Prob. 59ECh. 5.7 - Prob. 60ECh. 5.7 - Prob. 61ECh. 5.7 - Prob. 62ECh. 5.7 - Prob. 63ECh. 5.7 - Prob. 64ECh. 5.7 - Prob. 65ECh. 5.7 - Prob. 66ECh. 5.7 - Prob. 67ECh. 5.7 - Prob. 68ECh. 5.7 - Prob. 69ECh. 5.7 - Prob. 70ECh. 5.7 - Prob. 71ECh. 5.7 - Prob. 72ECh. 5.7 - Prob. 73ECh. 5.7 - Prob. 74ECh. 5.7 - Prob. 75ECh. 5.7 - Prob. 76ECh. 5.7 - Prob. 77ECh. 5.7 - Prob. 78ECh. 5.7 - Prob. 79ECh. 5.7 - Prob. 80ECh. 5.7 - Prob. 81ECh. 5.7 - Prob. 82ECh. 5.7 - Prob. 83ECh. 5.7 - Prob. 84ECh. 5.7 - Prob. 85ECh. 5.7 - Prob. 86ECh. 5.7 - Prob. 87ECh. 5.7 - Prob. 88ECh. 5.7 - 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Prob. 78ECh. 5.8 - Prob. 79ECh. 5.8 - Prob. 80ECh. 5.8 - Prob. 81ECh. 5.8 - Prob. 82ECh. 5.8 - Prob. 83ECh. 5.8 - Prob. 84ECh. 5.8 - Prob. 85ECh. 5.8 - Prob. 86ECh. 5.8 - Prob. 87ECh. 5 - Prob. 1CRECh. 5 - Prob. 2CRECh. 5 - Prob. 3CRECh. 5 - Prob. 4CRECh. 5 - Prob. 5CRECh. 5 - Prob. 6CRECh. 5 - Prob. 7CRECh. 5 - Prob. 8CRECh. 5 - Prob. 9CRECh. 5 - Prob. 10CRECh. 5 - Prob. 11CRECh. 5 - Prob. 12CRECh. 5 - Prob. 13CRECh. 5 - Prob. 14CRECh. 5 - Prob. 15CRECh. 5 - Prob. 16CRECh. 5 - Prob. 17CRECh. 5 - Prob. 18CRECh. 5 - Prob. 19CRECh. 5 - Prob. 20CRECh. 5 - Prob. 21CRECh. 5 - Prob. 22CRECh. 5 - Prob. 23CRECh. 5 - Prob. 24CRECh. 5 - Prob. 25CRECh. 5 - Prob. 26CRECh. 5 - Prob. 27CRECh. 5 - Prob. 28CRECh. 5 - Prob. 29CRECh. 5 - Prob. 30CRECh. 5 - Prob. 31CRECh. 5 - Prob. 32CRECh. 5 - Prob. 33CRECh. 5 - Prob. 34CRECh. 5 - Prob. 35CRECh. 5 - Prob. 36CRECh. 5 - Prob. 37CRECh. 5 - Prob. 38CRECh. 5 - Prob. 39CRECh. 5 - Prob. 40CRECh. 5 - Prob. 41CRECh. 5 - Prob. 42CRECh. 5 - Prob. 43CRECh. 5 - Prob. 44CRECh. 5 - Prob. 45CRECh. 5 - Prob. 46CRECh. 5 - Prob. 47CRECh. 5 - Prob. 48CRECh. 5 - Prob. 49CRECh. 5 - Prob. 50CRECh. 5 - Prob. 51CRECh. 5 - Prob. 52CRECh. 5 - Prob. 53CRECh. 5 - Prob. 54CRECh. 5 - Prob. 55CRECh. 5 - Prob. 56CRECh. 5 - Prob. 57CRECh. 5 - Prob. 58CRECh. 5 - Prob. 59CRECh. 5 - Prob. 60CRECh. 5 - Prob. 61CRECh. 5 - Prob. 62CRECh. 5 - Prob. 63CRECh. 5 - Prob. 64CRECh. 5 - Prob. 65CRECh. 5 - Prob. 66CRECh. 5 - Prob. 67CRECh. 5 - Prob. 68CRECh. 5 - Prob. 69CRECh. 5 - Prob. 70CRECh. 5 - Prob. 71CRECh. 5 - Prob. 72CRECh. 5 - Prob. 73CRECh. 5 - Prob. 74CRECh. 5 - Prob. 75CRECh. 5 - Prob. 76CRECh. 5 - Prob. 77CRECh. 5 - Prob. 78CRECh. 5 - Prob. 79CRECh. 5 - Prob. 80CRECh. 5 - Prob. 81CRECh. 5 - Prob. 82CRECh. 5 - Prob. 83CRECh. 5 - Prob. 84CRECh. 5 - Prob. 85CRECh. 5 - Prob. 86CRECh. 5 - Prob. 87CRECh. 5 - Prob. 88CRECh. 5 - Prob. 89CRECh. 5 - Prob. 90CRECh. 5 - Prob. 91CRECh. 5 - Prob. 92CRECh. 5 - Prob. 93CRECh. 5 - Prob. 94CRECh. 5 - Prob. 95CRECh. 5 - Prob. 96CRECh. 5 - Prob. 97CRECh. 5 - Prob. 98CRECh. 5 - Prob. 99CRECh. 5 - Prob. 100CRECh. 5 - Prob. 101CRECh. 5 - Prob. 102CRECh. 5 - Prob. 103CRECh. 5 - Prob. 104CRECh. 5 - Prob. 105CRECh. 5 - Prob. 106CRECh. 5 - Prob. 107CRECh. 5 - Prob. 108CRECh. 5 - Prob. 109CRECh. 5 - Prob. 110CRECh. 5 - Prob. 111CRECh. 5 - Prob. 112CRECh. 5 - Prob. 113CRECh. 5 - Prob. 114CRECh. 5 - Prob. 115CRECh. 5 - Prob. 116CRECh. 5 - Prob. 117CRECh. 5 - Prob. 118CRECh. 5 - Prob. 119CRECh. 5 - Prob. 120CRECh. 5 - Prob. 121CRE
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- 2. Consider the vector force: F(x, y, z) = 2xye²i + (x²e² + y)j + (x²ye² — z)k. (A) [80%] Show that F satisfies the conditions for a conservative vector field, and find a potential function (x, y, z) for F. Remark: To find o, you must use the method explained in the lecture. (B) [20%] Use the Fundamental Theorem for Line Integrals to compute the work done by F on an object moves along any path from (0,1,2) to (2, 1, -8).arrow_forwardhelp pleasearrow_forwardIn each of Problems 1 through 4, draw a direction field for the given differential equation. Based on the direction field, determine the behavior of y as t → ∞. If this behavior depends on the initial value of y at t = 0, describe the dependency.1. y′ = 3 − 2yarrow_forward
- B 2- The figure gives four points and some corresponding rays in the xy-plane. Which of the following is true? A B Angle COB is in standard position with initial ray OB and terminal ray OC. Angle COB is in standard position with initial ray OC and terminal ray OB. C Angle DOB is in standard position with initial ray OB and terminal ray OD. D Angle DOB is in standard position with initial ray OD and terminal ray OB.arrow_forwardtemperature in degrees Fahrenheit, n hours since midnight. 5. The temperature was recorded at several times during the day. Function T gives the Here is a graph for this function. To 29uis a. Describe the overall trend of temperature throughout the day. temperature (Fahrenheit) 40 50 50 60 60 70 5 10 15 20 25 time of day b. Based on the graph, did the temperature change more quickly between 10:00 a.m. and noon, or between 8:00 p.m. and 10:00 p.m.? Explain how you know. (From Unit 4, Lesson 7.) 6. Explain why this graph does not represent a function. (From Unit 4, Lesson 8.)arrow_forwardFind the area of the shaded region. (a) 5- y 3 2- (1,4) (5,0) 1 3 4 5 6 (b) 3 y 2 Decide whether the problem can be solved using precalculus, or whether calculus is required. If the problem can be solved using precalculus, solve it. If the problem seems to require calculus, use a graphical or numerical approach to estimate the solution. STEP 1: Consider the figure in part (a). Since this region is simply a triangle, you may use precalculus methods to solve this part of the problem. First determine the height of the triangle and the length of the triangle's base. height 4 units units base 5 STEP 2: Compute the area of the triangle by employing a formula from precalculus, thus finding the area of the shaded region in part (a). 10 square units STEP 3: Consider the figure in part (b). Since this region is defined by a complicated curve, the problem seems to require calculus. Find an approximation of the shaded region by using a graphical approach. (Hint: Treat the shaded regi as…arrow_forward
- Solve this differential equation: dy 0.05y(900 - y) dt y(0) = 2 y(t) =arrow_forwardSuppose that you are holding your toy submarine under the water. You release it and it begins to ascend. The graph models the depth of the submarine as a function of time. What is the domain and range of the function in the graph? 1- t (time) 1 2 4/5 6 7 8 -2 -3 456700 -4 -5 -6 -7 d (depth) -8 D: 00 t≤ R:arrow_forward0 5 -1 2 1 N = 1 to x = 3 Based on the graph above, estimate to one decimal place the average rate of change from x =arrow_forwardComplete the description of the piecewise function graphed below. Use interval notation to indicate the intervals. -7 -6 -5 -4 30 6 5 4 3 0 2 1 -1 5 6 + -2 -3 -5 456 -6 - { 1 if x Є f(x) = { 1 if x Є { 3 if x Єarrow_forwardComplete the description of the piecewise function graphed below. 6 5 -7-6-5-4-3-2-1 2 3 5 6 -1 -2 -3 -4 -5 { f(x) = { { -6 if -6x-2 if -2< x <1 if 1 < x <6arrow_forwardLet F = V where (x, y, z) x2 1 + sin² 2 +z2 and let A be the line integral of F along the curve x = tcost, y = t sint, z=t, starting on the plane z = 6.14 and ending on the plane z = 4.30. Then sin(3A) is -0.598 -0.649 0.767 0.278 0.502 0.010 -0.548 0.960arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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