A+ Guide To It Technical Support
10th Edition
ISBN: 9780357108291
Author: ANDREWS, Jean.
Publisher: Cengage,
expand_more
expand_more
format_list_bulleted
Expert Solution & Answer
Chapter 5, Problem 8TC
Explanation of Solution
Given: A DVD that has a size of 4.7 GB as marketed by the manufactures, whereas, in explorer, the size is displayed as 4.3 GB.
To find: The reason why manufacturer′s advertisement of the size of the DVD is different than displayed in the explorer...
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
5.Find out how many parts are there in a floppy disk? Suppose a 3.5 inches floppy disk contained 80 tracks, each of which is divided into sectors capable of holding 512 characters. How many characters will the disk hold if each track is divided into 9 sectors? What if each track contains 18 sectors? How does these capacities compare to the size of 400-page novel in which each page contains 3500 characters?
Explain how a DVD manufacturer can advertise that a DVD can hold 4.7 GB, but Explorer reports theDVD capacity as 4,706,074,624 bytes or 4.38 GB.a. Manufacturers are allowed to overadvertise their products.b. The manufacturer measures capacity in decimal and the OS measures capacity in binary.c. The actual capacity is 4.7 GB, but the OS requires overhead to manage the DVD and the overheadis not included in the reported DVD capacity.d. The DVD was formatted to have a capacity of 4.38 GB, but it could have been formatted to have acapacity of 4.7 GB.
A certain moving arm disk storage, with one head, has the following specifications.
Number of tracks/recording surface = 200
Disk rotation speed = 2400 rpm
Track storage capacity = 62,500 bits
The average latency of this device is P msec and the data transfer rate is Q bits/sec.
Write the value of P and Q.
Chapter 5 Solutions
A+ Guide To It Technical Support
Knowledge Booster
Similar questions
- A company that has engaged in a business that requires fast response times has just received a bid for a new system that includes much more storage than was specified in the requirements document. When the company questioned the vendor about the increased storage, the vendor said he was bidding a set of the smallest-capacity disk drives that the company makes. Why didn’t the vendor just bid fewer disks?arrow_forwardAn AVR has 0x3FF as the address of its last byte in the RAM and it has the same value 0x3FF as the address of its last location in the ROM. What are the sizes of the RAM and the ROM? Select one: a. Both 2KB b. RAM 2KB and ROM 4KB c. Both 1KB d. RAM: 1KB and ROM: 2KBarrow_forwardThere are many parameters that could be used to describe disk performance; Which of the following statements is most true? Note: none of the statements may be true exactly, but one will always be much closer to the truth than the other three. Also note: you should assume all dimensions and parameters of the disk are unchanged except for the ones mentioned. a) If you double the number of sectors per block, then you halve the capacity of the disk. b) If you double the rotational speed of the disk, then you halve the average rotational latency. c) If you divide tracks into half as many blocks, then you double the read time for a block. d) If you double the number of bits per track, then you double the average rotational latency.arrow_forward
- Transfer rate of a disk drive can be no faster than the bit density (bits/track) times the rotational speed of the disk. Figure 7.15 gives a data transfer rate of 112GB/sec. Assume that the average track length of the disk is 5.5 inches. What is the average bit density of the disk?arrow_forwardConsider a disk with the following characteristics: block size 512 bytes, number of blocks per track=20, number of tracks per surface=400. A disk pack consists of 15 double sided disks. i) What is the total capacity of a track? ii) How many cylinders are there? iii) What is the total capacity of a cylinder?arrow_forwardFor example, we mentioned in our explanation of the physical elements of disk performance that upgrading from 7,200rpm disks to 10,000rpm disks may result in a performance increase ranging from 10% to 50%. What might possibly cause a 10% increase in performance? Is it possible that there will be no improvement at all? Explain. (Hint: Rotational delay is not the only element that influences the performance of a hard drive.)arrow_forward
- Q .A magnetic Hard disk is operated with 6000 RPM, it has 24 surfaces, 256 tracks, 512 sectors and sector capacity is 1024 Bytes. The average latency in milliseconds is ..Q .A magnetic Hard disk is operated with 6000 RPM, it has 24 surfaces, 256 tracks, 512 sectors and sector capacity is 1024 Bytes. The average latency in milliseconds is ..Q .A magnetic Hard disk is operated with 6000 RPM, it has 24 surfaces, 256 tracks, 512 sectors and sector capacity is 1024 Bytes. The average latency in milliseconds is ..Q .A magnetic Hard disk is operated with 6000 RPM, it has 24 surfaces, 256 tracks, 512 sectors and sector capacity is 1024 Bytes. The average latency in milliseconds is ..Q .A magnetic Hard disk is operated with 6000 RPM, it has 24 surfaces, 256 tracks, 512 sectors and sector capacity is 1024 Bytes. The average latency in milliseconds is ..Q .A magnetic Hard disk is operated with 6000 RPM, it has 24 surfaces, 256 tracks, 512 sectors and sector capacity is 1024 Bytes. The average…arrow_forwardIn Feynman's lecture he wondered "why cannot we write the entire 24 volumes of the Encyclopedia Brittanica on the head of a pin". For a modern hard disk drive the area of a single bit of information on the surface of the disk is roughly 10 x 40 nm² in area. In such a hard drive would the area required to store the data for 24 volumes of the Encyclopedia Brittanica be greater or less than the head of a pin? In Feynman's lecture he estimates the 24 million books as big as the Encyclopedia Brittanica has 10¹5 bits of information.arrow_forwardSuppose that a magnetic disk has an average seek time of 4 ms, a rotation rate of 5400 RPM, a transfer rate of 50 MB/second, a sector size of 512 bytes, and controller overhead of 2 ms. What is the average amount of time to read a single sector?arrow_forward
- A manufacturer wishes to design an array of hard disks in a server a capacity of 512gb or more. If the technology used to manufacture the disk allows 2048-byte sectors, 4096 sectors/track and 8192 tracks/platter. How many disks are required, assuming two platters/disk?arrow_forwardThe terms "digital memory" and "storage device" are often used interchangeably. To what extent would it benefit consumers if there were a single memory standard, similar to how there is just one standard for SSD sizes? Can customers save money and time by adopting a single standard? There are two methods for accessing memory: sequential and direct. For what reason are more and more essential devices adopting direct access? How can we move information from a sequential-access device to a direct-access device?arrow_forward3. A hard disk has 64 sectors/ track, 16 platters, each with 2 regarding surface and 2000 cylinders. The address of a sector is given as corresponds to sector number isarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- A+ Guide To It Technical SupportComputer ScienceISBN:9780357108291Author:ANDREWS, Jean.Publisher:Cengage,
Systems ArchitectureComputer ScienceISBN:9781305080195Author:Stephen D. BurdPublisher:Cengage Learning
Principles of Information Systems (MindTap Course...Computer ScienceISBN:9781305971776Author:Ralph Stair, George ReynoldsPublisher:Cengage Learning
A+ Guide To It Technical Support
Computer Science
ISBN:9780357108291
Author:ANDREWS, Jean.
Publisher:Cengage,
Systems Architecture
Computer Science
ISBN:9781305080195
Author:Stephen D. Burd
Publisher:Cengage Learning
Principles of Information Systems (MindTap Course...
Computer Science
ISBN:9781305971776
Author:Ralph Stair, George Reynolds
Publisher:Cengage Learning