Explanation Given info: The combined mass of basket and the people is 1220 kg , the mass of hot air is 5980 kg and the downward acceleration of balloon after late arrival climbs up into the basket is 0.10 m / s 2 . Explanation: The net force acts on the balloon is zero. The buoyant force on the balloon acts vertically upwards and the weight of the hot air and the people acts vertically downwards. Therefore the net force acts on the balloon is, F net = F B − m 1 g − m 0 g = F B − ( m 1 + m 0 ) g Here, F net is the net force acts on the balloon. F B is the buoyant force. m 1 is the combined mass of the basket and the people. m 0 is the mass of the hot air. g is the acceleration due to gravity. F B = ( 0 N ) + [ ( 1220 kg ) + ( 5980 kg ) ] Rearrange the above expression for F B . F B = F net + ( m 1 + m 0 ) g Substitute 0 N for F net , 9.8 m / s 2 for g 1220 kg for m 1 and 5980 kg for m 0 in the above equation to find the value of F B . F B = ( 0 N ) + [ ( 1220 kg ) + ( 5980 kg ) ] ( 9.81 m / s 2 ) × ( 1 N 1 kg ⋅ m / s 2 ) = 7.0632 × 10 4 N Thus, the buoyant force is 7.0632 × 10 4 N . When the late arrival climbs up, the net force acts on the balloon is, F net = ( m 0 + m 1 + m 2 ) a Here, F net is the net force acts on the balloon after the late arrival climbs up

Physics, Books a la Carte Plus Mastering Physics with Pearson eText -- Access Card Package (5th Edition)

5th Edition

ISBN: 9780134032610

Author: James S. Walker

Publisher: PEARSON

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Density of Solids

The density of a substance refers to how much matter is present in a given amount of space. It is expressed as the ratio of the mass of the substance to its volume.

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Chapter 5, Problem 83GP

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The mass of the last person to climb aboard.

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Chapter 5, Problem 82GP

Chapter 5, Problem 84GP

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Physics, Books a la Carte Plus Mastering Physics with Pearson eText -- Access Card Package (5th Edition)

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