Statistics, Books a la Carte Edition Plus MyLab Statistics with Pearson eText -- Access Card Package (4th Edition)
4th Edition
ISBN: 9780134435855
Author: Alan Agresti, Christine A. Franklin, Bernhard Klingenberg
Publisher: PEARSON
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Chapter 5, Problem 81CP
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3. [15] The joint PDF of RVS X and Y is given by
fx.x(x,y) = {
x) = { c(x +
{
c(x+y³),
0,
0≤x≤ 1,0≤ y ≤1
otherwise
where c is a constant.
(a) Find the value of c.
(b) Find P(0 ≤ X ≤,
Need help please
7. [10] Suppose that Xi, i = 1,..., 5, are independent normal random variables, where
X1, X2 and X3 have the same distribution N(1, 2) and X4 and X5 have the same
distribution N(-1, 1). Let
(a) Find V(X5 - X3).
1
= √(x1 + x2) — — (Xx3 + x4 + X5).
(b) Find the distribution of Y.
(c) Find Cov(X2 - X1, Y).
-
Chapter 5 Solutions
Statistics, Books a la Carte Edition Plus MyLab Statistics with Pearson eText -- Access Card Package (4th Edition)
Ch. 5.1 - Probability Explain what is meant by the long-run...Ch. 5.1 - Testing a coin Your friend decides to flip a coin...Ch. 5.1 - Vegetarianism You randomly sample 10 people in...Ch. 5.1 - Airline accident deaths Airplane safety has been...Ch. 5.1 - World Cup 2014 The powerrank.com website...Ch. 5.1 - Random digits Consider a random number generator...Ch. 5.1 - Polls and sample size A pollster agency wants to...Ch. 5.1 - Heart transplant Before the first human heart...Ch. 5.1 - Nuclear war You are asked to use your best...Ch. 5.1 - Simulate coin flips Use the web app Random Numbers...
Ch. 5.1 - Unannounced pop quiz A teacher announces a pop...Ch. 5.2 - Student union poll Part of a student opinion poll...Ch. 5.2 - Random digit A single random digit (from 09) is...Ch. 5.2 - Pop quiz A teacher gives a four-question...Ch. 5.2 - More true-false questions Your teacher gives a...Ch. 5.2 - Rolling two dice Some friends are playing a game...Ch. 5.2 - Two girls A couple plans to have two children....Ch. 5.2 - Three children A couple plans to have three...Ch. 5.2 - Wrong sample space A couple plans to have four...Ch. 5.2 - Insurance Every year the insurance industry spends...Ch. 5.2 - Cell phone and case At the local cell phone store,...Ch. 5.2 - Seat belt use and auto accidents Based on records...Ch. 5.2 - Protecting the environment When the General Social...Ch. 5.2 - Prob. 25PBCh. 5.2 - Newspaper sales You are the director of newspaper...Ch. 5.2 - Prob. 27PBCh. 5.3 - Recidivism rates A 2014 article from Business...Ch. 5.3 - Prob. 29PBCh. 5.3 - Audit and low income Table 5.3 on audit status and...Ch. 5.3 - Religious affiliation The 2012 Statistical...Ch. 5.3 - Prob. 32PBCh. 5.3 - Prob. 33PBCh. 5.3 - Go Celtics! Larry Bird, who played pro basketball...Ch. 5.3 - Prob. 35PBCh. 5.3 - Homeland security According to an article in The...Ch. 5.3 - Down syndrome again Example 8 discussed the Triple...Ch. 5.3 - Prob. 38PBCh. 5.3 - Happiness in relationship Are people happy in...Ch. 5.3 - Prob. 40PBCh. 5.3 - Prob. 41PBCh. 5.3 - Prob. 42PBCh. 5.3 - Prob. 43PBCh. 5.3 - Prob. 44PBCh. 5.3 - Family with two children For a family with two...Ch. 5.3 - Prob. 46PBCh. 5.4 - Birthdays of presidents Of the first 44 presidents...Ch. 5.4 - Prob. 48PBCh. 5.4 - Lots of pairs Show that with 25 students, there...Ch. 5.4 - Prob. 50PBCh. 5.4 - Prob. 51PBCh. 5.4 - Prob. 52PBCh. 5.4 - Coincidence in your life State an event that has...Ch. 5.4 - Monkeys typing Shakespeare Since events of low...Ch. 5.4 - A true coincidence at DisneyWorld Wisconsin has...Ch. 5.4 - Prob. 56PBCh. 5.4 - Mammogram diagnostics Breast cancer is the most...Ch. 5.4 - Prob. 58PBCh. 5.4 - Prob. 59PBCh. 5.4 - Convicted by mistake In criminal trials (e.g.,...Ch. 5.4 - DNA evidence compelling? DNA evidence can be...Ch. 5.4 - Prob. 62PBCh. 5.4 - Simulating donations to local blood bank The...Ch. 5.4 - Probability of winning In Example 16, we estimated...Ch. 5 - Peyton Manning completions As of the end of the...Ch. 5 - Due for a boy? A couple has five children, all...Ch. 5 - Prob. 68CPCh. 5 - Choices for lunch For the set lunch at Amelias...Ch. 5 - Caught doctoring the books After the major...Ch. 5 - Life after death In a General Social Survey, in...Ch. 5 - Death penalty jury In arguing against the death...Ch. 5 - Drivers exam Three 15-year-old friends with no...Ch. 5 - Prob. 74CPCh. 5 - Health insurance According to a 2006 census bureau...Ch. 5 - Prob. 76CPCh. 5 - Prob. 77CPCh. 5 - Prob. 78CPCh. 5 - Prob. 79CPCh. 5 - Roll two more dice Refer to the previous exercise....Ch. 5 - Prob. 81CPCh. 5 - Waste dump sites A federal agency is deciding...Ch. 5 - Prob. 83CPCh. 5 - Prob. 84CPCh. 5 - Prob. 85CPCh. 5 - Death penalty and false positives For the decision...Ch. 5 - Prob. 87CPCh. 5 - Screening for heart attacks Biochemical markers...Ch. 5 - Prob. 89CPCh. 5 - Color blindness For genetic reasons, color...Ch. 5 - Prob. 91CPCh. 5 - Prostate cancer A study of the PSA blood test for...Ch. 5 - Prob. 95CPCh. 5 - Illustrate probability terms with scenarios a....Ch. 5 - Short term versus long run Short-term aberrations...Ch. 5 - Prob. 98CPCh. 5 - Mrs. Test Mrs. Test (see www.mrstest.com) sells...Ch. 5 - Prob. 100CPCh. 5 - Prob. 101CPCh. 5 - Prob. 102CPCh. 5 - Protective bomb Before the days of high security...Ch. 5 - Streak shooter Sportscaster Maria Coselli claims...Ch. 5 - Multiple choice Choose ALL correct responses. For...Ch. 5 - Prob. 106CPCh. 5 - Prob. 107CPCh. 5 - Multiple choice: Dream come true You have a dream...Ch. 5 - Prob. 109CPCh. 5 - True or false Answer true of false for each part....Ch. 5 - True or false When you flip a balanced coin twice,...Ch. 5 - Prob. 112CPCh. 5 - Prob. 113CPCh. 5 - Prob. 114CPCh. 5 - Prob. 115CPCh. 5 - Prob. 116CP
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- 1. [10] Suppose that X ~N(-2, 4). Let Y = 3X-1. (a) Find the distribution of Y. Show your work. (b) Find P(-8< Y < 15) by using the CDF, (2), of the standard normal distribu- tion. (c) Find the 0.05th right-tail percentage point (i.e., the 0.95th quantile) of the distri- bution of Y.arrow_forward6. [10] Let X, Y and Z be random variables. Suppose that E(X) = E(Y) = 1, E(Z) = 2, V(X) = 1, V(Y) = V(Z) = 4, Cov(X,Y) = -1, Cov(X, Z) = 0.5, and Cov(Y, Z) = -2. 2 (a) Find V(XY+2Z). (b) Find Cov(-x+2Y+Z, -Y-2Z).arrow_forward1. [10] Suppose that X ~N(-2, 4). Let Y = 3X-1. (a) Find the distribution of Y. Show your work. (b) Find P(-8< Y < 15) by using the CDF, (2), of the standard normal distribu- tion. (c) Find the 0.05th right-tail percentage point (i.e., the 0.95th quantile) of the distri- bution of Y.arrow_forward
- == 4. [10] Let X be a RV. Suppose that E[X(X-1)] = 3 and E(X) = 2. (a) Find E[(4-2X)²]. (b) Find V(-3x+1).arrow_forward2. [15] Let X and Y be two discrete RVs whose joint PMF is given by the following table: y Px,y(x, y) -1 1 3 0 0.1 0.04 0.02 I 2 0.08 0.2 0.06 4 0.06 0.14 0.30 (a) Find P(X ≥ 2, Y < 1). (b) Find P(X ≤Y - 1). (c) Find the marginal PMFs of X and Y. (d) Are X and Y independent? Explain (e) Find E(XY) and Cov(X, Y).arrow_forward32. Consider a normally distributed population with mean μ = 80 and standard deviation σ = 14. a. Construct the centerline and the upper and lower control limits for the chart if samples of size 5 are used. b. Repeat the analysis with samples of size 10. 2080 101 c. Discuss the effect of the sample size on the control limits.arrow_forward
- Consider the following hypothesis test. The following results are for two independent samples taken from the two populations. Sample 1 Sample 2 n 1 = 80 n 2 = 70 x 1 = 104 x 2 = 106 σ 1 = 8.4 σ 2 = 7.6 What is the value of the test statistic? If required enter negative values as negative numbers (to 2 decimals). What is the p-value (to 4 decimals)? Use z-table. With = .05, what is your hypothesis testing conclusion?arrow_forwardPeriodically, Merrill Lynch customers are asked to evaluate Merrill Lynch financial consultants and services (2000 Merrill Lynch Client Satisfaction Survey). Higher ratings on the client satisfaction survey indicate better service with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use = .05 and test to see whether the consultant with more experience has the higher population mean service rating. Consultant A Consultant B = 16 = 10 = 6.82 = 6.25 = .64 = .75 State the null and alternative hypotheses.H0: 1 - 2 Ha: 1 - 2 Compute the value of the test statistic (to 2 decimals). What is the p-value?The p-value is What is your conclusion?arrow_forwardA firm paid its first annual dividend yesterday in the amount of $.15 per share. The company plans to double the dividend in each of the next 3 years. Starting in Year 4, the firm plans to pay $1.50 per share indefinitely. What is one share of this stock worth today if the market rate of return on similar securities is 13.8 percent? Multiple Choice $11.79 $8.92 $10.77 $11.02 $10.26arrow_forward
- Suppose the random variable X is normally distributed with mean 80 and standard deviation 16. Find following probabilities. Find ‘b’ such that P(X ≥ b) = 0.975. Find the probability using a normal distribution table AND using ti-83 calculator. SHOW ALL STEPS PLEASE.arrow_forwardSuppose the random variable X is normally distributed with mean 80 and standard deviation 16. Find following probabilities. Equation: P(85 ≤ X ≤ 102). Find the probability using a normal distribution table AND using ti-83 calculator. SHOW ALL STEPS PLEASE.arrow_forwardData set is Bachelor Degree's Conferred by Race and Ethnicity.arrow_forward
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