The explanations have to be given for the following statements. Concept Introduction: The square root of u 2 is called as the root mean square velocity and can be represented as u rms . Here, u 2 is the average of the square of the particles velocities. Root mean square velocity can be given by the equation, u rms = 3RT M Where, R=gas constant T=temperature M= Product of mass
The explanations have to be given for the following statements. Concept Introduction: The square root of u 2 is called as the root mean square velocity and can be represented as u rms . Here, u 2 is the average of the square of the particles velocities. Root mean square velocity can be given by the equation, u rms = 3RT M Where, R=gas constant T=temperature M= Product of mass
Solution Summary: The author explains that the root mean square velocity is the average of the square of particles velocities. The smaller He moves at a faster average velocity.
Interpretation: The explanations have to be given for the following statements.
Concept Introduction:
The square root of
u2 is called as the root mean square velocity and can be represented as
urms . Here,
u2 is the average of the square of the particles velocities.
Root mean square velocity can be given by the equation,
urms=3RTM
Where, R=gas constant
T=temperature
M= Product of mass
b)
Interpretation Introduction
Interpretation: The explanations have to be given for the following statements.
Concept Introduction:
The square root of
u2 is called as the root mean square velocity and can be represented as
urms . Here,
u2 is the average of the square of the particles velocities.
Root mean square velocity can be given by the equation,
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Question 59 of 70
The volume of
1
unit of plasma is 200.0 mL
If the recommended dosage
for adult patients is 10.0 mL per kg of body mass, how many units are needed for
a patient with a body mass of 80.0
kg ?
80.0
kg
10.0
DAL
1
units
X
X
4.00
units
1
1
Jeg
200.0
DAL
L
1 units
X
200.0 mL
= 4.00 units
ADD FACTOR
*( )
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ANSWER
RESET
D
200.0
2.00
1.60 × 10³
80.0
4.00
0.0400
0.250
10.0
8.00
&
mL
mL/kg
kg
units/mL
L
unit
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19
Identify the starting material in the following reaction. Click the "draw structure" button to launch the
drawing utility.
draw structure ...
[1] 0 3
C10H18
[2] CH3SCH3
H
In an equilibrium mixture of the formation of ammonia from nitrogen and hydrogen, it is found that
PNH3 = 0.147 atm, PN2 = 1.41 atm and Pн2 = 6.00 atm. Evaluate Kp and Kc at 500 °C.
2 NH3 (g) N2 (g) + 3 H₂ (g)
K₂ = (PN2)(PH2)³ = (1.41) (6.00)³ = 1.41 x 104
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell