Halley's Comet Edmond Halley was the first to realize that the comets observed in 1531,1607, and 1682 were really one comet (now called Halley's Comet) that moved around the Sun in an elongated elliptical orbit (see Figure 5.5 ). He predicted that the peanut-shaped comet would reappear in 1757. It appeared in March 1759 (attractions to Jupiter and Saturn delayed its trip by 618 days). More recent appearances of Halley’s Comet were in 1835, 1910, and 1986. It is expected again in 2061. The nucleus of Halley's Comet is relatively small (15 km long. 8 km wide, and 8 km thick). It has a low 2 .2 × 10 14 -kg mass with an average density of about 600 kg /m 3 . (The density of water is 1000 kg /m 3 .) The nucleus rotates once every 52 h. When Halley’s Comet is closest to the Sun, temperatures on the comet can rise to about 77 °C and several tons of gas and dust are emitted each second, producing the long tail that we see each time it passes the Sun. 78 EST Use the velocity change method to estimate the comet's direction of acceleration when passing closest to the Sun (position I in Figure P5.78 ). a. A b B c. C d. D e. The acceleration is zero.
Halley's Comet Edmond Halley was the first to realize that the comets observed in 1531,1607, and 1682 were really one comet (now called Halley's Comet) that moved around the Sun in an elongated elliptical orbit (see Figure 5.5 ). He predicted that the peanut-shaped comet would reappear in 1757. It appeared in March 1759 (attractions to Jupiter and Saturn delayed its trip by 618 days). More recent appearances of Halley’s Comet were in 1835, 1910, and 1986. It is expected again in 2061. The nucleus of Halley's Comet is relatively small (15 km long. 8 km wide, and 8 km thick). It has a low 2 .2 × 10 14 -kg mass with an average density of about 600 kg /m 3 . (The density of water is 1000 kg /m 3 .) The nucleus rotates once every 52 h. When Halley’s Comet is closest to the Sun, temperatures on the comet can rise to about 77 °C and several tons of gas and dust are emitted each second, producing the long tail that we see each time it passes the Sun. 78 EST Use the velocity change method to estimate the comet's direction of acceleration when passing closest to the Sun (position I in Figure P5.78 ). a. A b B c. C d. D e. The acceleration is zero.
Halley's Comet Edmond Halley was the first to realize that the comets observed in 1531,1607, and 1682 were really one comet (now called Halley's Comet) that moved around the Sun in an elongated elliptical orbit (see Figure 5.5). He predicted that the peanut-shaped comet would reappear in 1757. It appeared in March 1759 (attractions to Jupiter and Saturn delayed its trip by 618 days). More recent appearances of Halley’s Comet were in 1835, 1910, and 1986. It is expected again in 2061.
The nucleus of Halley's Comet is relatively small (15 km long. 8 km wide, and 8 km thick). It has a low
2
.2
×
10
14
-kg
mass with an average density of about
600 kg /m
3
. (The density of water is
1000 kg /m
3
.) The nucleus rotates once every 52 h. When Halley’s Comet is closest to the Sun, temperatures on the comet can rise to about
77 °C
and several tons of gas and dust are emitted each second, producing the long tail that we see each time it passes the Sun.
78 EST Use the velocity change method to estimate the comet's direction of acceleration when passing closest to the Sun (position I in Figure P5.78).
For each of the actions depicted below, a magnet and/or metal loop moves with velocity v→ (v→ is constant and has the same magnitude in all parts). Determine whether a current is induced in the metal loop. If so, indicate the direction of the current in the loop, either clockwise or counterclockwise when seen from the right of the loop. The axis of the magnet is lined up with the center of the loop. For the action depicted in (Figure 5), indicate the direction of the induced current in the loop (clockwise, counterclockwise or zero, when seen from the right of the loop). I know that the current is clockwise, I just dont understand why. Please fully explain why it's clockwise, Thank you
A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).
What are the expected readings of the ammeter and voltmeter for the circuit in the figure below? (R = 5.60 Ω, ΔV = 6.30 V)
ammeter
I =
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