Chapter 5, Problem 78AP

Interpretation Introduction

Interpretation:

Thework done, in joules, for the given reaction is to be calculated.

Concept introduction:

The amount of work done by a pressure–volume work process is represented as follows:

$w=-P\Delta V$

Here, P is the external pressure, $w$ is the work done, and $\Delta V$ is the change in volume of the container.

The volume change is calculated as follows:

$\Delta V=V_{\text{final}}-V_{\text{initial}}$

Here, $\Delta V$ is the change in volume, $V_{\text{initial}}$ is the initial volume, and $V_{\text{final}}$ is the final volume.