a. Explanation Given data: A man holds a steel rod vertically in his, exerting a 400 N grip force on the rod. The force exerting on the rod by the man ( F ) is 400 M. Coefficient of static friction between the dry hands and the steel rods ( μ s ) is 0.27. Formula used: Refer to the equation (5.7) in the textbook, and write the expression for static friction force on the rod as follows. f s = μ s n (1) Here, μ s is the coefficient of static friction between the dry hands and the steel rods, and n is the normal force acting on the rod when the man holds the rod. Write the expression for actual weight of the rod as follows. w = m g (2) Here, m is the mass of the rod, which is to be determined, and g is the acceleration due to gravity, which is 9.8 m s 2 . Explanation: In order to hold the rod without slipping it, the friction force should be equal to its weight. From the given data, draw the free body diagram for the given system as shown in Figure 1. From the Figure, write the expression for normal force acting on the rod as follows. n = 400 N (3) Write the expression for static friction force form Figure 1 as follows. f s = w From equation (2), substitute m g for w , f s = m g From equation (1), substitute μ s n for f s , μ s n = m g Rearrange the expression to find the mass of the rod as follows b. To determine To find: The mass of the heaviest rod that the man can hold without slipping when his hands are wet.

4th Edition

ISBN: 9780134779218

Author: Knight

Publisher: PEARSON

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Chapter 5, Problem 71GP

To determine

To find: The mass of the heaviest rod that the man can hold without slipping when his hands are dry.

To determine

To find: The mass of the heaviest rod that the man can hold without slipping when his hands are wet.

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Chapter 5, Problem 70GP

Chapter 5, Problem 72GP

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Chapter 5 Solutions

COLLEGE PHYSICS,AP EDITION >NASTA ED.<

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