ELECTRIC CIRCUITS-W/MASTERINGENGINEERING
11th Edition
ISBN: 9780134894300
Author: NILSSON
Publisher: PEARSON
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Chapter 5, Problem 6P
To determine
Calculate the value of current
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10.34 Determine the power readings of the two wattmetersshown in the circuit of Fig. P10.34 given that ZY = (15− j5) W
10.29 A 208-V (rms) balanced three-phase source supports twoloads connected in parallel. Each load is itself a balanced threephaseload. Determine the line current, given that load 1 is 12 kVAat pf 1 = 0.7 leading and load 2 is 18 kVA at pf 2 = 0.9 lagging.
Chapter 5 Solutions
ELECTRIC CIRCUITS-W/MASTERINGENGINEERING
Ch. 5.2 - Assume that the op amp in the circuit shown is...Ch. 5.3 - The source voltage vs in the circuit in Assessment...Ch. 5.4 - Find vo in the circuit shown if va = 0.1 V and vb...Ch. 5.5 - Assume that the op amp in the circuit shown is...Ch. 5.6 - In the difference amplifier shown, vb = 4.0 V....Ch. 5.6 - Suppose the 12kΩ resistor Rd in the difference...Ch. 5.7 - The inverting amplifier in the circuit shown has...Ch. 5 - The op amp in the circuit in Fig. P5.1 is ideal....Ch. 5 - Replace the 2.5 V source in the circuit in Fig....Ch. 5 - Find io in the circuit in Fig. P5.3 if the op amp...
Ch. 5 - The op amp in the circuit in Fig. P5.4 is...Ch. 5 - The op amp in the circuit in Fig. P5.5 is ideal....Ch. 5 - Find iL (in milliamperes) in the circuit in Fig....Ch. 5 - Prob. 7PCh. 5 - Design an inverting amplifier with a gain of 2.5,...Ch. 5 - Design an inverting amplifier with a gain of 4....Ch. 5 - The op amp in the circuit in Fig. P5.10 is...Ch. 5 - The op amp in the circuit shown in Fig. P5.11 is...Ch. 5 - The op amp in Fig. P5.12 is ideal.
What circuit...Ch. 5 - Design an inverting-summing amplifier using a 120...Ch. 5 - Prob. 14PCh. 5 - Design an inverting-summing amplifier so...Ch. 5 - The op amp in Fig. P5.16 is ideal. Find vo if va –...Ch. 5 - Prob. 17PCh. 5 - The op amp in the circuit of Fig. P5.18 is...Ch. 5 - Prob. 19PCh. 5 - The op amp in the circuit shown in Fig. P5.20 is...Ch. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - The op amp in the circuit of Fig. P5.23 is...Ch. 5 - The circuit in Fig. P5.24 is a noninverting...Ch. 5 - The op amp in the circuit of Fig. P5.25 is...Ch. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Select the values of Rb and Rf in the circuit in...Ch. 5 - The op amp in the adder-subtracter circuit shown...Ch. 5 - In the difference amplifier shown in Fig. P5.32,...Ch. 5 - Prob. 33PCh. 5 - The op amp in the circuit of Fig. P5.34 is...Ch. 5 - Assume that the ideal op amp in the circuit seen...Ch. 5 - Prob. 37PCh. 5 - Show that when the ideal op amp in Fig. P5.38 is...Ch. 5 - The op amps in the circuit in Fig. P5.39 are...Ch. 5 - The two op amps in the circuit in Fig. P5.40 are...Ch. 5 - The circuit inside the shaded area in Fig. P5.41...Ch. 5 - Assume that the ideal op amp in the circuit in...Ch. 5 - Derive Eq. 5.31.
(5.31)
Ch. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Repeat Problem 5.45 assuming an ideal op...Ch. 5 - Assume the input resistance of the op amp in Fig....Ch. 5 - Prob. 48PCh. 5 - Suppose the strain gages in the bridge in Fig....Ch. 5 - For the circuit shown in Fig. P5.50, show that if...Ch. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53P
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- 10.31 A 240-V (rms), 60-Hz Y-source is connected to a balancedthree-phase Y-load by four wires, one of which is the neutral wire.If the load is 400 kVA at pf old = 0.6 lagging, what size capacitorsshould be added to change the power factor to pf new = 0.95lagging?arrow_forwardCable A Cable A is a coaxial cable of constant cross section. The metal regions are shaded in grey and are made of copper. The solid central wire has radius a = 5mm, the outer tube inner radius b = 20mm and thickness t = 5mm. The dielectric spacer is Teflon, of relative permittivity &r = 2.1 and breakdown strength 350kV/cm. A potential difference of 1kV is applied across the conductors, with centre conductor positive and outer conductor earthed. Before undertaking any COMSOL simulations we'll first perform some theoretical analysis of Cable A based on the EN2076 lectures, to make sense of the simulations. Calculate the radial electric field of cable A at radial positions r b. Also calculate the maximum operating voltage of cable A, assuming a safety margin of ×2, and indicate where on the cable's cross section dielectric breakdown is most likely to occur.arrow_forward: For the gravity concrete dam shown in the figure, the following data are available: The factor of safety against sliding (F.S sliding)=1.2 Unit weight of concrete (Yconc)=24 KN/m³ - Neglect( Wave pressure, silt pressure, ice force and earth quake force) μ=0.65, (Ywater) = 9.81 KN/m³ Find factor of safety against overturning (F.S overturning) 6m3 80m Smarrow_forward
- I need help checking if its correct -E1 + VR1 + VR4 – E2 + VR3 = 0 -------> Loop 1 (a) R1(I1) + R4(I1 – I2) + R3(I1) = E1 + E2 ------> Loop 1 (b) R1(I1) + R4(I1) - R4(I2) + R3(I1) = E1 + E2 ------> Loop 1 (c) (R1 + R3 + R4) (I1) - R4(I2) = E1 + E2 ------> Loop 1 (d) Now that we have loop 1 equation will procced on finding the equation of I2 current loop. However, a reminder that because we are going in a clockwise direction, it goes against the direction of the current. As such we will get an equation for the matrix that will be: E2 – VR4 – VR2 + E3 = 0 ------> Loop 2 (a) -R4(I2 – I1) -R2(I2) = -E2 – E3 ------> Loop 2 (b) -R4(I2) + R4(I1) - R2(I2) = -E2 – E3 -----> Loop 2 (c) R4(I1) – (R4 + R2)(I2) = -E2 – E3 -----> Loop 2 (d) These two equations will be implemented to the matrix formula I = inv(A) * b R11 R12 (R1 + R3 + R4) -R4 -R4 R4 + R2arrow_forward10.2 For each of the following groups of sources, determineif the three sources constitute a balanced source, and if it is,determine if it has a positive or negative phase sequence.(a) va(t) = 169.7cos(377t +15◦) Vvb(t) = 169.7cos(377t −105◦) Vvc(t) = 169.7sin(377t −135◦) V(b) va(t) = 311cos(wt −12◦) Vvb(t) = 311cos(wt +108◦) Vvc(t) = 311cos(wt +228◦) V(c) V1 = 140 −140◦ VV2 = 114 −20◦ VV3 = 124 100◦ Varrow_forwardApply single-phase equivalency to determine the linecurrents in the Y-D network shown in Fig. P10.13. The loadimpedances are Zab = Zbc = Zca = (25+ j5) Warrow_forward
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