BIOCHEMISTRY (LOOSELEAF)-W/ACCESS
9th Edition
ISBN: 9781319425784
Author: BERG
Publisher: Macmillan Higher Education
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Chapter 5, Problem 6P
Interpretation Introduction
Interpretation:
A procedure to distinguish between the normal gene and the mutant gene has to be stated. Whether a positive result can prove that the mutant possesses GTG in place of GAG or not has to be stated.
Concept introduction:
DNA stands for deoxyribonucleic acid, is a biological macromolecule. DNA contains double helical strands along with the complementary base pairs. The four complementary bases of DNA are adenine (A), thymine (T), guanine (G) and cytosine (C).
The basic unit of heredity which is made up of DNA segments is known as gene.
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Macmillan Learning
Cholesterol synthesis begins with the formation of mevalonate from acetyl CoA. This
process activates mevalonate and converts it to isopentenyl pyrophosphate.
Identify the atoms in mevalonate and isopentenyl pyrophosphate that will be labeled
from acetyl CoA labeled with 14C in the carbonyl carbon. Place 14C atoms and C atoms
to denote which carbon atoms are labeled and which are not labeled.
H₂C
COA
14C-labeled acetyl-CoA
HHH
[c]
H
H
OH
014C
- OH
H
HH
H
Mevalonate
CH3
H H
14C
H
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H
H
Incorrect Answer
of o
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Isopentenyl pyrophosphate
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Answer Bank
14C
Chapter 5 Solutions
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