Chapter 5, Problem 5.90EP

An open-cycle gas turbine plant will exhaust into a waste heat boiler which receives 66 0C feedwater. The gas turbine plant produces 2611 kW. Air flow rate is 37 kg/kW-hr. Fuel rate, rf/a = 0.014 kg fuel/kg air. Actual exhaust gas temperature = 483 0C. Average exhaust gas Cp = 1.082 kJ/kg.K. Compute the saturated steam at 0.450 MPa that can be produced per hour, assuming that the final gas temperature is 38 0C above the saturation temperature. Show the necessary diagrams.

An open-cycle gas turbine plant will exhaust into a waste heat boiler which receives 66 0C feedwater. The gas turbine plant produces 2611 kW. Air flow rate is 37 kg/kW-hr. Fuel rate, rf/a = 0.014 kg fuel/kg air. Actual exhaust gas temperature = 483 0C. Average exhaust gas Cp = 1.082 kJ/kg.K. Compute the saturated steam at 0.450 MPa that can be produced per hour, assuming that the final gas temperature is 38 0C above the saturation temperature.

A simple vapor - compression cycle develops 13 tons ofrefrigeration. Using ammonia as refrigerant and operating at acondensing temperature of 24 °C and evaporating temperature of-18°C and assuming that the compression are isentropic and thatthe gas leaving the condenser is saturated. Find the followinga). Draw the p-h diagramb.) Refrigerating effect in kJ/kgc.) Circulation flow in kg/mind.) Power requiremente.) Volume flow in cubic meter per minute per tonf.) Coefficient of performanceg.) Power per ton

A steam boller plant consists of an economiser, evaporator and a superheate r and steam Is generated at a rate of 9600 kg/hr at a pressure of 1,8 MPa and 260°C. The feed water enters the eco- nomiser at 36,2°C and the boiler at 86 C. The steam leaves the evaporator 0,89 dry. Ihe plant uses 13,5 kg coal/minute vith a calorific value of 36 MJ/kg. Calculata the heat transfer In the economiser, evaporator and the suporhe ater per kgl. Also calcu- late the plant elficiency and the equivalent evaporation from and at 100°C.

i need the answer quickly

Q.6 A vapor compression cycle uses R134a as the refrigerant . The vapor condenses at 40 degrees * C and is subcooled to 35 degrees * C before entering the expansion valve . The evaporating temperature is - 5 degrees * C . The vapor leaving the evaporator is superheated to 5 degrees * C at entry to the compressor . The heat absorption rate is 13 kW and the compression process is isentropic . Calculate (i) the refrigerant flow rate, (ii ) the work input , and ( iii ) the COP . Answers: () 0.0837kg * s ^ - 1 , (ii) 2.63 kW , (iii) 4.95

3. In a gas turbine power plant, the air is preheated by the exhaust gases in a heat exchanger called a regenerator. Air enters at 1 MPa, 550 K, and the mass flow rate of 900 kg / min. Heat is transferred to the air with a rate of 3500 kJ / s. While the exhaust gas enters the regenerator at 150 kPa, 800 K and leaves at 130 kPa and 600 K. Assuming the air and the exhaust gases are ignoring kinetic and potential energy effects, determine the a) the air temperature at the outlet b) the exhaust gas flow rate [Assuming that air and exhaust gas has the same Cp = 1.005 kJ/kg.K]

Example 2/ vapor compression refrigeration cycle has 3 TR used R717 as working fluid with evaporator pressure 5 bar and condenser pressure 70 bar. This cycle working with liquid suction heat exchanger. Where the refrigerant leave the heat exchanger with degree of super heating of 10°C.find 1-mass flow rate of cycle. 2-power consumption; and 4-COP of the cycle. p 8:23 /

Problem 4.9. Estimate the maximum possible COP of a household air conditioner. use any reasonable values for the reservior temperatures