Chapter 5, Problem 5.6QAP

Interpretation Introduction

Interpretation:

Signal-to-noise ratio for a DC current shown in a figure should be estimated.

Concept introduction:

The mean current is given as $0.9\times {10}^{-15}\text{ A}$.

For a DC current, the signal-to-noise ratio is defined as follows,

$\frac{S}{N}\text{=}\frac{\text{mean}}{\text{standard deviation}}=\frac{\overline{x}}{s}$

If the deviation from the mean value is assumed to be random, the standard deviation of a DC current can be measured as follows,

$\text{standard deviation}=\frac{\text{maximum signal}-\text{ minimum signal}}{5}$