FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives
energy QH by heat transfer from a hot reservoir at TH = 1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate
temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by
heat transfer to a reservoir at Tc = 500°R. All energy transfers are positive in the directions of the arrows.
Determine:
Hot reservoir at TH
QH
Reservoir
at T
R1
lo
ali
R2
Qc
Cold reservoir at Te
W.
cycle
W
cycle
(a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles.
(b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R.
respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two
cycles, Wcycle.
As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Weycle: The first cycle receives
energy QH by heat transfer from a hot reservoir at TH = 1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate
temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature Tand rejects energy Qc by
heat transfer to a reservoir at Tc = 450°R. All energy transfers are positive in the directions of the arrows.
Hot reservoir at TH
R1
W cycle
Reservoir
at T
W cycle
R2
Cold reservoir at Te
Determine:
(a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles.
(b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 450°R,
respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two
cycles, Wcycle
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- As shown in the figure below, two reversible cycles arranged in series each produce the same net work, Weycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH = 1500°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by heat transfer to a reservoir at Tc = 500°R. All energy transfers are positive in the directions of the arrows. Hot reservoir at T RI W. cycle Reservoir at T R2 Wcycle Cold reservoir at Te Determine: (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1500°R and 500°R, respectively. Also, determine the ratio of the net work developed by the single cycle to the net work developed by each of the two cycles, Woycle-arrow_forwardA reversible power cycle whose thermal efficiency is 50% operates between a reservoir at 1800 K and a reservoir at a lower temperature T. Determine T, in K.arrow_forwardTwo reversible power cycles are arranged in series. The first cycle receives energy by heat transfer from a reservoir at temperature TH and rejects energy to a reservoir at an intermediate temperature T. The second cycle receives the energy rejected by the first cycle from the reservoir at temperature T and rejects energy to a reservoir at temperature TC lower than T. Derive an expression for the intermediate temperature T in terms of TH and TC when,a. The net works of the two power cycles are equalb. The thermal efficiencies of the two power cycles are equalarrow_forward
- If a closed system undergoes a process for which S2=S1, the process must be internally reversible. - True or False One of the Carnot principles states that all power cycles operating between the same two thermal reservoirs have the same thermal efficiency. - True or False One statement of the second law of thermodynamics recognizes that the extensive property entropy is produced within systems whenever internal irreversibilities are present. - True or Falsearrow_forwardAs shown in the figure below, two reversible cycles arranged in series each produce the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at TH-1000°R and rejects energy Q by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and rejects energy Qc by heat transfer to a reservoir at Te - 500°R. All energy transfers are positive in the directions of the arrows. Determine: Hot reservoir at TH lH R1 Reservoir Q at T 20 R2 lc Cold reservoir at Tc We cycle W Wcycle (a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two power cycles. (b) the thermal efficiency of a single reversible power cycle operating between hot and cold reservoirs at 1000°R and 500°R, respectively. Also, determine the ratio of the network developed by the single cycle to the network developed by each of the two cycles, Wcycle-arrow_forwardA power cycle operating between two reservoirs receives energy Qu by heat transfer from a hot reservoir at TH = 2000 K and rejects energy Qc by heat transfer to a cold reservoir at Tc = 400 K. For the cases below you will be asked to determine the cycle n and whether the cycle operates Reversibly, Irreversibility, or is Impossible. Сycle Сycle Сycle Assume: п — пСarnot n пСarnot 1. The maximum thermal efficiency nCarnot for the cycle is equal to а. 0.2 b. 0.8 с. 1.0 d. none of the above. 2. If QH = 1100 kJ and the Weycle = 900 kJ then the cycle is Reversible b. Irreversible c. Impossible а. d. none of the above. 3. If QH = 1000 kJ and Qc = 200 kJ then the cycle is a. Reversible b. Irreversible c. Impossible d. none of the above. 4. If Wq a. Reversible b. Irreversible c. Impossible d. none of the above. суcle 1400 kJ and Qc= 600 kJ then the cycle is 5. If n = 50% then the cycle is a. Reversible b. Irreversible c. Impossible d. none of the above.arrow_forward
- All reversible heat engines operating between the same two reservoirs have the same efficiency (the second Carnot principle).arrow_forwardSecond-law efficiency is a measure of the performance of a device relative to its performance under reversible conditions.arrow_forwardQ3/ A heat pump cycle operating between two reservoirs receives energy Q2 from a cold reservoir at T2 = 250K and rejects energy Qı to a hot reservoir at T1 = 300K. For each of the following cases determine whether the cycle operates reversibly, irreversibly or is impossible. (a) Q2 =300KJ , W = 400 KJ (b) Q2 = 2000KJ , Q1 = 2200KJ (c) Q1 = 3000KJ , W= 500KJ (d) W = 400 KJ , COP =6 %3Darrow_forward
- A system executes a power cycle while receiving 1000 Btu by heat transfer at a temperature of 900oR and discharging 600 Btu by heat transfer at a temperature of 540oR. There are no other heat transfers.Determine the cycle thermal efficiency. Use the Clausius Inequality to determine σcycle, in Btu/oR. Determine if this cycle is internally reversible, irreversible, or impossible.arrow_forwardA power cycle receives 5000 Btu by heat transfer from a reservoir at 1500°F and discharges energy by heat transfer to a reservoir at 300°F. The thermal efficiency of the cycle is 75% of that for a reversible power cycle operating between the same reservoirs. (a) For the actual cycle, determine the thermal efficiency and the energy discharged to the cold reservoir, in Btu. (b) Repeat for the reversible power cycle.arrow_forwardA system executes a power cycle while receiving 900 Btu by heat transfer at a temperature of 900°R and discharging 800 Btu by heat transfer at a temperature of 540°R. There are no other heat transfers. Determine the cycle thermal efficiency. Use the Clausius Inequality to determine Ocycle, in Btu/°R. Determine if this cycle is internally reversible, irreversible, or impossible. Step 1 Determine the cycle thermal efficiency. n = i %arrow_forward
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