Explanation Given information: The diameter of the cylinder is D = 450 m m = 0.45 m Height of the cylinder is h = 750 m m = 0.75 m Then the submerged height of the cylinder is h s = 600 m m = 0.6 m Cylinder is placed in kerosene at a temperature is T = 25 0 C The relation between weights of the cube is the product of its total volume and specific weight w = γ c V Substitute D = 0.45 m h = 0.75 m in above equation, we get: V = π 4 D 2 h = π 4 ( 0.45 ) 2 ( 0.75 ) = 0.1193 m 3 And then calculate the volume of displaced portion of cylinder by using below equation: V d = π 4 D 2 h = π 4 ( 0.45 ) 2 ( 0.6 ) = 0.0954 m 3 Moment of inertia about its X-X axis is: I = π D 4 64 = π ( 0.45 ) 2 64 = 2.0128 * 10 − 3 m 4 Then, the distance from the center of buoyancy to metacenter is M B = I V d Substitute I = 2

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Chapter 5, Problem 5.52PP

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The above cylinder is stable in the required position.

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Chapter 5, Problem 5.51PP

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Chapter 5 Solutions

EBK APPLIED FLUID MECHANICS

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The above cylinder is stable in the required position.

Solution Summary: The author explains that the cylinder is stable in the required position. The relation between weights of the cube is the product of its total volume and specific weight.

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The above cylinder is stable in the required position.

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Chapter 5 Solutions