FUNDAMENTALS OF THERMODYNAMICS
10th Edition
ISBN: 9781119634928
Author: Borgnakke
Publisher: WILEY
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Air flows steadily through an engine at a constant temperature, 400K. Find the work per kilogram if the exit pressure is one-third the inlet pressure and the inlet pressure is 207 kPa. Assume that the kinetic and potential energy variation is negligible.
(b) Velocity ratio of a machine is 72. The law of machine is P=1/48 W+30 N. Find the
maximum MA, efficiency and state whether machine is reversible.
Q5: A. An engine transfers 1.5 * 103 J of energy from a hot reservoir during a
cycle and transfers 1 * 103 J as exhaust to a cold reservoir.(a) Find the efficiency of
the engine.(b) How much work does this engine do in one cycle?
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- 5.49 Air in a piston/cylinder goes through a Carnot cycle with the P-v diagram shown in Fig. 5.21. The high and low temperatures are 600 K and 300 K, respectively. The heat added at the high temperature is 250 kJ/kg, and the lowest pressure in the cycle is 75 kPa. Find the specific volume and pressure after heat rejection and the net work per unit mass.arrow_forwardIn a turbine, steam enters with an enthalpy of 1275 Btu/lb, and leaves with an enthalpy of 1115 Btu/lbm. The transferred heat is 13 Btu/ibm. Find the turbine work in hp where the steam flow rate is 5 lbm/sec?arrow_forwardHow to solve this question pleasearrow_forward
- Problem 4.01. A carnot refrigerator (carnot cycle heat pump in reverse) operating between Th and Te is used to cool and freeze a bottle of water, volume V, at a temperature To < Th to freezing temperature T (known density Pw, heat capacity cw). (a) Find the work required to cool and freeze the water. (b) Find the change in entropy in the heat baths, and use it to place a limit on the change in entropy of the water (without calculating the entropy change in the water). The C.O.P. of a carnot refrigerator: KR= Qc = W Te Th-Tearrow_forwardDearrow_forwardA: Derive the steady flow energy equation and reduce it for a. A turbine (Reversible Process) b. A pump (Reversible Process) c. A nozzle (Reversible Process) d. A throttling (Irreversible Process)arrow_forward
- A certain SSSF turbine (irreversible and adiabatic) operates on air with the following conditions, Inflow: Ti=1000 K, Pi = 13223.07354 kPa Outflow (actual): Te = 402.3904382 K Find the actual specific work output of the turbine, wt in KJ/kg. (Assume single inflow/outflow, neglect change in KE and PE. Assume constant specific heats in this problem, with Cp0 =1.004 kJ/(K*kg) and k= 1.4. Next if the hypothetical ideal, reversible adiabatic (isentropic) specific work output of the turbine is wt= +800 Kj/kg: Find the isentropic efficiency of the turbine, outflow pressure Pe in kPa and finally what is the ratio of the outflow pressure of the actual turbine to the same pressure for the ideal turbine.arrow_forward.11 The refrigerator (R) shown in Fig. F3.i! is a closed syster: thet oper- ates in cycles while in communication with the cold space (T;) and the building (T). The refrigeration load (QL) reaches the cold space by leak- ing from T to T across the thermal insulation system (I), which is a closed system operating steadily. If the work required by the refrigera- tor is WR, what is the net heat transferred by systems (R) and (I) to the building (Tg)? The net heat transferred by (R) and (I) to the building (QR) is removed by a heat pump (HP) that functions cyclically as a closed system. The heat pump requires the work WHp and rejects heat to the ambient of temperature T, which is warmer than the building. Together, the closed systems (R), (I), (B), and (HP) perform the function of removing the refrigeration load Q, by rejecting heat to the ambient T. T (В) Тв (HP) E WHP WR (R) (I) TL Te, Figure P3.11 38 ENTROPY GENERATION, OR EXERGY DESTRUCTION The total work requirement is WR + WHP, and…arrow_forwardFrom the turbine the heat loss per kg of steam flow rate is 5 kW. Find the power developed in kW by the steam turbine per kg of steam flow rate?arrow_forward
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