Concept explainers
Interpretation:
The total pressure (in atm) of a 15.0-L container at 28°C that contains N2, O2 and Cl2 has to be calculated.
Concept Introduction:
- An ideal gas has is a hypothetical gas that is formed by a few molecules so that, its density is low, and the intermolecular forces are null. The model of gas facilitates mathematical calculations to study gases.
- The
ideal gas law can be expressed in the following way,
Where P is the gas pressure (atm), V is the gas volume (L), T is the gas absolute temperature (K), n is the moles number of the gas and R is the ideal gas constant (
- The ideal gas mixture is a mixture of two or more ideal gases that has the following characteristics,
- Each component of the mixture behaves as ideal gas that occupies all the mixture volume at the mixture temperature.
- Each component exercises a partial pressure. The sum of the partial pressure of the components is equal to the total pressure of the mixture.
- The mole fraction is the ratio between the moles number of the component in the mixture and the total number of moles of gas in the mixture. It can be expressed in the following way,
Where, yi is the molar fraction of component i, ni is the moles number of component i and n total is the total moles number of the mixture.
- The partial pressure is the pressure that a gas of the mixture exercises if it occupies all the volume of the mixture.
- The partial pressure of each component in the mixture is directly proportional to its molar fraction. It can be expressed in the following way,
Where, Pi is the partial pressure of component i, Ptotal is the total pressure of the mixture and yi is the molar fraction of component i.
Trending nowThis is a popular solution!
Chapter 5 Solutions
CHEM FOR ENGNRNG SDNTS (EBOOK) W/ACCES
- Please correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward(a) The following synthesis of the molecule shown in the circle has a major problem. What is this problem? (2 pts) 1) HBr (no peroxides) 2) H- NaNH2 Br 3) NaNH, 4) CH3Br 5) H2, Pd (b) Starting with the molecule shown below and any other materials with two carbons or less, write out an alternate synthesis of the circled molecule. More than one step is needed. Indicate the reagent(s) and the major product in all the steps in your synthesis. (5 pts) 2024 Fall Term (1) Organic Chemistry 1 (Lec) CHEM 22204 02[6386] (Hunter College) (c) Using the same starting material as in part (b) and any other materials win two carpons or less, write out syntheses of the circled molecules shown below. More than one step is needed in each case. Indicate the reagent(s) and the major product in all the steps in your synthesis. You may use reactions and products from your synthesis in part (b). (5 pts)arrow_forward
- alt ons for Free Response Questions FRQ 1: 0/5 To spectrophotometrically determine the mass percent of cobalt in an ore containing cobalt and some inert materials, solutions with known [Co?) are prepared and absorbance of each of the solutions is measured at the wavelength of optimum absorbance. The data are used to create a calibration plot, shown below. 0.90- 0.80- 0.70 0.60 0.50 0.40- 0.30 0.20- 0.10- 0.00- 0.005 0.010 Concentration (M) 0.015 A 0.630 g sample of the ore is completely dissolved in concentrated HNO3(aq). The mixture is diluted with water to a final volume of 50.00 ml. Assume that all the cobalt in the ore sample is converted to Co2+(aq). a. What is the [Co2] in the solution if the absorbance of a sample of the solution is 0.74? 13 ✗ b. Calculate the number of moles of Co2+(aq) in the 50.00 mL solution. 0.008 mols Coarrow_forwardPlease correct answer and don't used hand raitingarrow_forwardCloso-boranes and arachno-boranes are structures that exhibit B-B, B-H-B, and B-H bonds. Correct?arrow_forward
- Indicate why boron hydrides cannot form large linear or planar structures.arrow_forwardNido-boranes are structures with the molecular formula BnHn+4 that exhibit B-B, B-H-B and B-H bonds. Correct?arrow_forward8:07 AM Wed Dec 18 Final Exam 2024 copy Home Insert Draw Page Layout Formulas Data Review AA 田 General A G fx Alexis Cozort ☑ ⚫ 61% A B D E F H K M N P R S T U 3+ 10 125 mM that yielded peak heights of Aa = 9 1-(a)A sample solution was examined under XRF to quantify the analyte Ce³+. Find the response factor F, when standardized concentration of analyte [Ce³+]A = concentration of internal standard S i.e. [In³*]s = 151 mM was spiked with standardized 1600 and As = 3015 respectively? 11 12 (i)Define F, F = Aa As [A] [S] + X 13 (*Define with variables) 4000 14 15 (ii)Calculate F, F = numeral (You will use the F value in part 1-(b) below) As 16 (*Calculate with numerals) 17 18 1-(b)To determine the unknown conc of analyte [Ce³+], a volume of 15 mL of internal standard S having a concentration [In³+]s = 0.264 M 19 20 was added to 45 mL of unknown, and the mixture was diluted to 100 mL in a volumetric flask. XRF analysis yielded a spectrum, Figure-1, where peak heights A and As are…arrow_forward
- All structural types of Boron hydrides exhibit B-B, B-H-B and B-H bonds. Correct?arrow_forwardN-nitrosodimethylamine (NDMA) is a suspected carcinogen that can form via reactions between dimethylamine (DMA) and monochloramine (NH2Cl). The relevant elementary reactions and the corresponding rate constants are as shown below. Reaction Rate constant (M¹s¹) DMA + NH2Cl = DMCA + NH3 k =1.4×10-1, kr = 5.83×10-3 1.28×10-3 DMA + NH2Cl → UDMH UDMH + NH2Cl → NDMA -> 1.11×10-1 If the initial concentrations of DMA and NH2Cl are given, you should be able to predict the concentrations of all species at any given reaction time. Please write down the rate equations for DMA, NH2C1, DMCA, UDMH and NDMA.arrow_forwardYou wish to add enough NaOCl (sodium hypochlorite) to a 150 m³ swimming pool to provide a dose of 5.0 mg/L TOTOCI as Cl2. (a) How much NaOCI (kg) should you add? (Note: the equivalent weight of NaOCl is based on the reaction: NaOCl + 2H + 2 e→CI + Na +H₂O.) (10 pts) (atomic weight: Na 23, O 16, C1 35.5) (b) The pH in the pool after the NaOCl addition is 8.67. To improve disinfection, you want at least 90% of the TOTOCI to be in the form of HOCI (pKa 7.53). Assuming that HOCI/OCI is the only weak acid/base group in solution, what volume (L) of 10 N HCl must be added to achieve the goal? (15 pts) Note that part a) is a bonus question for undergraduate students. If you decide not to work on this part of the question, you many assume TOTOCI = 7×10-5 M for part b).arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning