For a given two 200.0L tanks with the gases helium and hydrogen, the mass of each gas is needed to be determined to produce a pressure of 2.70 atm in its respective tank at 24°C . Concept introduction: By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law . According to ideal gas law, PV=nRT Where, P = pressure in atmospheres V= volumes in liters n = number of moles R =universal gas constant ( 0.08206 L ⋅ a t m / K ⋅ m o l ) T = temperature in kelvins By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation. The mass of a given substance can be calculated by, M a s s i n g r a m = n u m b e r o f m o l e s × g r a m m o l e c u l a r m a s s
For a given two 200.0L tanks with the gases helium and hydrogen, the mass of each gas is needed to be determined to produce a pressure of 2.70 atm in its respective tank at 24°C . Concept introduction: By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law . According to ideal gas law, PV=nRT Where, P = pressure in atmospheres V= volumes in liters n = number of moles R =universal gas constant ( 0.08206 L ⋅ a t m / K ⋅ m o l ) T = temperature in kelvins By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation. The mass of a given substance can be calculated by, M a s s i n g r a m = n u m b e r o f m o l e s × g r a m m o l e c u l a r m a s s
Definition Definition Number of atoms/molecules present in one mole of any substance. Avogadro's number is a constant. Its value is 6.02214076 × 10 23 per mole.
Chapter 5, Problem 53E
Interpretation Introduction
Interpretation: For a given two 200.0L tanks with the gases helium and hydrogen, the mass of each gas is needed to be determined to produce a pressure of 2.70 atm in its respective tank at
24°C.
Concept introduction:
By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law.
According to ideal gas law,
PV=nRT
Where,
P = pressure in atmospheres
V= volumes in liters
n = number of moles
R =universal gas constant (
0.08206L⋅atm/K⋅mol)
T = temperature in kelvins
By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation.
The mass of a given substance can be calculated by,
(f) SO:
Best Lewis Structure
3
e group geometry:_
shape/molecular geometry:,
(g) CF2CF2
Best Lewis Structure
polarity:
e group arrangement:_
shape/molecular geometry:
(h) (NH4)2SO4
Best Lewis Structure
polarity:
e group arrangement:
shape/molecular geometry:
polarity:
Sketch (with angles):
Sketch (with angles):
Sketch (with angles):
1.
Problem Set 3b
Chem 141
For each of the following compounds draw the BEST Lewis Structure then sketch the molecule (showing
bond angles). Identify (i) electron group geometry (ii) shape around EACH central atom (iii) whether the
molecule is polar or non-polar (iv)
(a) SeF4
Best Lewis Structure
e group arrangement:_
shape/molecular geometry:
polarity:
(b) AsOBr3
Best Lewis Structure
e group arrangement:_
shape/molecular geometry:
polarity:
Sketch (with angles):
Sketch (with angles):
(c) SOCI
Best Lewis Structure
2
e group arrangement:
shape/molecular geometry:_
(d) PCls
Best Lewis Structure
polarity:
e group geometry:_
shape/molecular geometry:_
(e) Ba(BrO2):
Best Lewis Structure
polarity:
e group arrangement:
shape/molecular geometry:
polarity:
Sketch (with angles):
Sketch (with angles):
Sketch (with angles):
Chapter 5 Solutions
Lab Manual for Zumdahl/Zumdahl/DeCoste¿s Chemistry, 10th Edition
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