
(a)
Definition of File organization.

Explanation of Solution
A file organization is a process of arranging files on the secondary storage devices. It is a technique for arranging the records of a file physically on secondary storage devices.
Objectives of file organization:
- It helps in doing fast Data retrieval.
- It helps in using the disk space properly and effectively.
- It provides data protection.
- Minimizes the need for re-organization of data and files.
- Security from unauthorized access.
For a table or physical file, while choosing a file organization for a
- every file organization must provide Fast data retrieval
- High speed processing of input data and maintenance of transactions.
- Storage space must be use efficiently
- Protection from data redundancy
- Protection from data loss or failure
- It must provide security to data from unauthorized user
(b)
Definition of Heap file organization.

Explanation of Solution
In Heap file organization the data is not stored in any series or sequence. It is an inefficient file organization method for complex database system. It does not provide efficient searching and sorting operations. It is useful only for small file structures. deletions and modification of data is also a major complex task in this file organization as the data is stored without any proper sequencing. Memory requirement for the data is more and this file organization does not provide any memory management technique for memory. Using this file organization is time consuming.
(c)
Definition of Sequential file organization.

Explanation of Solution
Sequential file organization is simple, fast and efficient. In this file organization records are stored in a sequential manner according to the primary key value. Searching a record in this file organization is a time-consuming process. Whole file needs to be scan, in order to find a record. While adding or Updating a record, it requires rewriting of file. During the deletion of record, it creates wasted space or require reorganizing.
(d)
Definition of Indexed file organization

Explanation of Solution
Index file organization is used to store the records in the memory with the index values. Indexed file organization provides fast access to records. It does not waste any memory space but requires extra memory to create an index. Adding and updating the records requires the dynamic allocation of data, and it also requires the maintenance of indexes. Searching and deletion operations are faster. Records can be stored either sequentially or non-sequentially.
(e)
Definition of Hashed file organization.

Explanation of Solution
It is a storage system in which the hashing
(f)
Definition of Denormalization.

Explanation of Solution
Denormalization: A process of Denormalization transforms normalized relations into non-normalized implementation specifications. Denormalization is done to improve the efficiency of input-output operations by specifying the database implementation structure so that data elements that are required together are also accessed together on the physical medium. Partitioning is also considered a form of Denormalization. Horizontal partitioning divides a relation into two or more record by placing different rows into different tables, based on common column values. Vertical partitioning distributes the columns of a relation into separate files, repeating the primary key in each of the files.
(g)
Definition of Composite key.

Explanation of Solution
Composite key: it is an attribute or a combination of attributes that identifies a row in a relation uniquely.
(h)
Definition of Secondary key.

Explanation of Solution
Among those candidate keys which are not opted for as primary key are knows as secondary key.
(h)
Definition of Data type

Explanation of Solution
Data type: DBMS has a defined list of data types. It contains numeric, string, and date/time-type variables etc.Selection of a data type is done based on data values that need to be stored in it. Some examples of the data types are: String, Number, Temporal, Boolean,etc.
(i)
Definition of Join index.

Explanation of Solution
Join index: it is an index of columns from two or more tables that come from the same domain of values.
Want to see more full solutions like this?
Chapter 5 Solutions
Modern Database Management (12th Edition)
- I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardMy code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardI would like to know the main features about the following three concepts: 1. Default forwarded 2. WINS Server 3. IP Security (IPSec).arrow_forward
- map the following ER diagram into a relational database schema diagram. you should take into account all the constraints in the ER diagram. Underline the primary key of each relation, and show each foreign key as a directed arrow from the referencing attributes (s) to the referenced relation. NOTE: Need relational database schema diagramarrow_forwardWhat is business intelligence? Share the Business intelligence (BI) tools you have used and explain what types of decisions you made.arrow_forwardI need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forward
- Task 3. i) Compare your results from Tasks 1 and 2. j) Repeat Tasks 1 and 2 for 500 and 5,000 elements. k) Summarize run-time results in the following table: Time/size n String StringBuilder 50 500 5,000arrow_forwardCan you please solve this without AIarrow_forward1. Create a Vehicle.java file. Implement the public Vehicle and Car classes in Vehicle.java, including all the variables and methods in the UMLS. Vehicle - make: String model: String -year: int + Vehicle(String make, String, model, int, year) + getMake(): String + setMake(String make): void + getModel(): String + setModel(String model): void + getYear(): int + set Year(int year): void +toString(): String Car - numDoors: int + numberOfCar: int + Car(String make, String, model, int, year, int numDoors) + getNumDoors(): int + setNumDoors (int num Doors): void + toString(): String 2. Create a CarTest.java file. Implement a public CarTest class with a main method. In the main method, create one Car object and print the object using System.out.println(). Then, print the numberOfCar. Your printing result must follow the example output: make Toyota, model=Camry, year=2022 numDoors=4 1 Hint: You need to modify the toString methods in the Car class and Vehicle class!arrow_forward
- CHATGPT GAVE ME WRONG ANSWER PLEASE HELParrow_forwardHELP CHAT GPT GAVE ME WRONG ANSWER Consider the following implementation of a container that will be used in a concurrent environment. The container is supposed to be used like an indexed array, but provide thread-safe access to elements. struct concurrent_container { // Assume it’s called for any new instance soon before it’s ever used void concurrent_container() { init_mutex(&lock); } ~concurrent_container() { destroy_mutex(&lock); } // Returns element by its index. int get(int index) { lock.acquire(); if (index < 0 || index >= size) { return -1; } int result = data[index]; lock.release(); return result; } // Sets element by its index. void set(int index, int value) { lock.acquire(); if (index < 0 || index >= size) { resize(size); } data[index] = value; lock.release(); } // Extend maximum capacity of the…arrow_forwardWrite a C program using embedded assembler in which you use your own function to multiply by two without using the product. Tip: Just remember that multiplying by two in binary means shifting the number one place to the left. You can use the sample program from the previous exercise as a basis, which increments a variable. Just replace the INC instruction with SHL.arrow_forward
- Database System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill EducationStarting Out with Python (4th Edition)Computer ScienceISBN:9780134444321Author:Tony GaddisPublisher:PEARSONDigital Fundamentals (11th Edition)Computer ScienceISBN:9780132737968Author:Thomas L. FloydPublisher:PEARSON
- C How to Program (8th Edition)Computer ScienceISBN:9780133976892Author:Paul J. Deitel, Harvey DeitelPublisher:PEARSONDatabase Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781337627900Author:Carlos Coronel, Steven MorrisPublisher:Cengage LearningProgrammable Logic ControllersComputer ScienceISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education





