Explanation Given data: Refer to the Figure P5.51 in the textbook for the velocity graph of the 2.0 kg object at various time instants. Mass of the object ( m ) is 2.0 kg. Formula used: Write the expression for net force of the object in terms of mass and acceleration as follows. F net = m a x (1) Here, m is the mass of the object, and a x is the acceleration of the object in the x -direction (horizontal direction). Write the expression to find the acceleration as follows. a x = v f − v i t f − t i (2) Here, v i is the initial velocity of the object, v f is the final velocity of the object, t i is the initial time, and t f is the final time. Explanation: From the figure P5.51 in the textbook, the acceleration is in three segments. The increasing velocity from 0 to 3 s, constant velocity (zero acceleration segment) from 3 s to 6 s, and the decreasing velocity from 6 s to 8 s. The downward acceleration from 6.0 s to 8 s is considered with negative sign. Calculation of acceleration from 0 s to 3 s: From the figure, the initial velocity is 0 m s , final velocity is 12 m s , initial time is 0 s, and the final time is 3 s. Substitute 0 m s for v i , 12 m s for v f , 0 s for t i , and 3 s for t f in equation (2), a x = 12 m s − 0 m s 3 s − 0 s = 12 m s 3 s = 4 m s 2 As the acceleration of the object from 0 s to 3 s is 4 m s 2 , the acceleration at t = 1 s is 4 m s 2 . Calculation of net force of the object at t = 1 s : Substitute 2.0 kg for m , and 4 m s 2 for a x in equation (1), F net = ( 2.0 kg ) ( 4 m s 2 ) = 8 kg ⋅ m s 2 = 8 N { ∵ 1 kg ⋅ m s 2 = 1 N } Therefore, the net force of the object at t = 1 s is 8 N . Calculation of acceleration from 3 s to 6 s: From the figure, the initial velocity is 12 m s , final velocity is 12 m s , initial time is 3 s, and the final time is 6 s. Substitute 12 m s for v i , 12 m s for v f , 3 s for t i , and 6 s for t f in equation (2), a x = 12 m s − 12 m s 6 s − 3 s = 0 m s 3 s = 0 m s 2 As the acceleration of the object from 3 s to 6 s is 0 m s 2 , the acceleration at t = 4 s is 0 m s 2

4th Edition

ISBN: 9780137574728

Author: Knight

Publisher: PEARSON

See similar textbooks

Question

Chapter 5, Problem 51GP

To determine

To find: The net force acting on the object at t=1 s, at t=4 s, and at t=7 s.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 5, Problem 50GP

Chapter 5, Problem 52GP

Students have asked these similar questions

The drawing in the image attached shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Side 1 has an area of 1.90 m^2, Side 2 has an area of 3.90 m^2, the electric field in magnitude is around 215 N/C. Please find the electric flux magnitude through side 1 and 2 combined if the angle (theta) made between the electric field with side 2 is 30.0 degrees. Thank you.

The drawing in the image attached shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 1.90 m^2, while Surface (2) has an area of 3.90 m^2. The electric field in magnitude of 215 N/C. Please find the magnitude of the electric flux through surface (with both 1 and 2 combined) if the angle (theta) made between the electric field with surface (2) is 30.0 degrees. Thank you.

Chapter 5 Solutions

COLLEGE PHYSICS:STRATEGIC APPR.AP ED.

Ch. 5 - An object is subject to two forces that do not...Ch. 5 - Are the objects described here in static...Ch. 5 - Prob. 3CQ Ch. 5 - Prob. 4CQ Ch. 5 - An astronaut takes his bathroom scale to the moon...Ch. 5 - A light block of mass m and a heavy block of mass...Ch. 5 - a. Can the normal force on an object be directed...Ch. 5 - A ball is thrown straight up. Taking the drag...Ch. 5 - You are going sledding with your friends, sliding...Ch. 5 - Suppose you are holding a box in front of you and...

Ch. 5 - You are walking up an icy slope. Suddenly your...Ch. 5 - Three objects move through the air as shown in...Ch. 5 - Prob. 13CQ Ch. 5 - Raindrops can fall at different speeds; some fall...Ch. 5 - An airplane moves through the air at a constant...Ch. 5 - Is it possible for an object to travel in air...Ch. 5 - For Questions 17 through 20, determine the tension...Ch. 5 - For Questions 17 through 20, determine the tension...Ch. 5 - For Questions 17 through 20, determine the tension...Ch. 5 - For Questions 17 through 20, determine the tension...Ch. 5 - In Figure Q5.21, block 2 is moving to the right....Ch. 5 - The wood block in Figure Q5.22 is at rest on a...Ch. 5 - Prob. 23MCQ Ch. 5 - Prob. 24MCQ Ch. 5 - Prob. 25MCQ Ch. 5 - While standing in a low tunnel, you raise your...Ch. 5 - A 5.0 kg dog sits on the floor of an elevator that...Ch. 5 - A 3.0 kg puck slides due east on a horizontal...Ch. 5 - Eric has a mass of 60 kg. He is standing on a...Ch. 5 - Prob. 30MCQ Ch. 5 - A football player at practice pushes a 60 kg...Ch. 5 - Two football players are pushing a 60 kg blocking...Ch. 5 - Land Rover ads used to claim that their vehicles...Ch. 5 - A truck is traveling at 30 m/s on a slippery road....Ch. 5 - The three ropes in Figure P5.1 are tied to a...Ch. 5 - Prob. 2P Ch. 5 - Prob. 3P Ch. 5 - A construction crew would like to support a 1000...Ch. 5 - When you bend your knee, the quadriceps muscle is...Ch. 5 - An early submersible craft for deep-sea...Ch. 5 - Prob. 7P Ch. 5 - A 65 kg student is walking on a slackline, a...Ch. 5 - Prob. 9P Ch. 5 - The forces in Figure P5.10 are acting on a 2.0 kg...Ch. 5 - The forces in Figure P5.11 are acting on a 2.0 kg...Ch. 5 - A horizontal rope is tied to a 50 kg box on...Ch. 5 - Prob. 13P Ch. 5 - In a head-on collision, a car stops in 0.10 s from...Ch. 5 - An astronauts weight on earth is 800 N. What is...Ch. 5 - A woman has a mass of 55.0 kg. a. What is her...Ch. 5 - Prob. 17P Ch. 5 - a. How much force does an 80 kg astronaut exert on...Ch. 5 - It takes the elevator in a skyscraper 4.0 s to...Ch. 5 - Riders on the Power Tower are launched skyward...Ch. 5 - Zach, whose mass is 80 kg, is in an elevator...Ch. 5 - Prob. 22P Ch. 5 - Figure P5.23 shows the velocity graph of a 75 kg...Ch. 5 - Prob. 24P Ch. 5 - A 23 kg child goes down a straight slide inclined...Ch. 5 - Prob. 26P Ch. 5 - Two workers are sliding a 300 kg crate across the...Ch. 5 - A 4000 kg truck is parked on a 7.0 slope. How big...Ch. 5 - A 1000 kg car traveling at a speed of 40 m/s skids...Ch. 5 - It is friction that provides the force for a car...Ch. 5 - The rolling resistance for steel on steel is quite...Ch. 5 - Prob. 34P Ch. 5 - Prob. 35P Ch. 5 - Prob. 36P Ch. 5 - Prob. 38P Ch. 5 - Prob. 40P Ch. 5 - A 1000 kg car pushes a 2000 kg truck that has a...Ch. 5 - A 2200 kg truck has put its front bumper against...Ch. 5 - Blocks with masses of 1.0 kg, 2.0 kg, and 3.0 kg...Ch. 5 - Prob. 44P Ch. 5 - Prob. 45P Ch. 5 - Prob. 46P Ch. 5 - Each of 100 identical blocks sitting on a...Ch. 5 - A 500 kg piano is being lowered into position by a...Ch. 5 - Dana has a sports medal suspended by a long ribbon...Ch. 5 - Prob. 51GP Ch. 5 - Your forehead can withstand a force of about 6.0...Ch. 5 - A 50 kg box hangs from a rope. What is the tension...Ch. 5 - Prob. 54GP Ch. 5 - A 50 kg box hangs from a rope. What is the tension...Ch. 5 - A fisherman has caught a very large, 5.0 kg fish...Ch. 5 - Riders on the Tower of Doom, an amusement park...Ch. 5 - Prob. 58GP Ch. 5 - Seat belts and air bags save lives by reducing the...Ch. 5 - Prob. 60GP Ch. 5 - A 20,000 kg rocket has a rocket motor that...Ch. 5 - Youve always wondered about the acceleration of...Ch. 5 - Prob. 63GP Ch. 5 - An impala is an African antelope capable of a...Ch. 5 - Josh starts his sled at the top of a 3.0-m-high...Ch. 5 - Prob. 67GP Ch. 5 - Prob. 68GP Ch. 5 - Prob. 69GP Ch. 5 - Prob. 70GP Ch. 5 - Prob. 71GP Ch. 5 - Prob. 72GP Ch. 5 - Prob. 73GP Ch. 5 - Its possible for a determined group of people to...Ch. 5 - Prob. 75GP Ch. 5 - Prob. 77GP Ch. 5 - Prob. 79GP Ch. 5 - Prob. 80GP Ch. 5 - Prob. 82GP Ch. 5 - Prob. 83GP Ch. 5 - Prob. 84GP Ch. 5 - MCAT-Style Passage Problems Sliding on the Ice In...Ch. 5 - MCAT-Style Passage Problems Sliding on the Ice In...Ch. 5 - MCAT-Style Passage Problems Sliding on the Ice In...Ch. 5 - MCAT-Style Passage Problems Sliding on the Ice In...

Knowledge Booster

The net force acting on the object at t = 1 s , at t = 4 s , and at t = 7 s .

To find: The net force acting on the object at t=1 s, at t=4 s, and at t=7 s.

Want to see the full answer?

Chapter 5 Solutions