EBK WATER RESOURCES ENGINEERING
3rd Edition
ISBN: 9781119493167
Author: Mays
Publisher: VST
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Chapter 5, Problem 5.1.4P
To determine
The uniform flow depth in the trapezoidalchannel.
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A. Design a trapezoidal channel to carry a discharge of 10.5 m^3/s. The bottom slop of the channel is 0.0035. Also the flow depth is half of the channel bottom width. Take roughness coefficient as 0.025 and side slop as 1H to 4V.
B. Based on the given information and your results in part A, compute the state of flow
2.1. A trapezoidal channel conveys 15 m³/s of water on a bed slope of 1 in 300. The base
width of the channel is 5 m and the side slope is 2 m. Assume a Manning's roughness
coefficient (n) of 0.018.
Calculate:
(a) Calculate the normal flow depth and discharge.
(b) Calculate Reynold's and Froude Numbers.
(c) Comment on the applicability of Manning's Equation.
A rectangular concrete channel (n = 0.014) has a bottom width
of 5.05 m and a longitudinal slope of 0.002. Compute the
discharge rate and velocity for a water depth of 2.34 m.
Compute normal depth, critical depth, and critical slope for a
discharge of 6.67 m³/s.
Chapter 5 Solutions
EBK WATER RESOURCES ENGINEERING
Ch. 5 - Prob. 5.1.1PCh. 5 - Prob. 5.1.2PCh. 5 - Prob. 5.1.3PCh. 5 - Prob. 5.1.4PCh. 5 - Prob. 5.1.5PCh. 5 - Prob. 5.1.6PCh. 5 - Prob. 5.1.7PCh. 5 - Prob. 5.1.8PCh. 5 - Prob. 5.1.9PCh. 5 - Prob. 5.2.1P
Ch. 5 - Prob. 5.2.2PCh. 5 - Prob. 5.3.1PCh. 5 - Prob. 5.3.2PCh. 5 - Prob. 5.3.3PCh. 5 - Prob. 5.3.4PCh. 5 - Prob. 5.3.5PCh. 5 - Prob. 5.3.6PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3PCh. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- (a) A trapezoidal channel has a bottom width of Bw = 10 m and 1 vertical to z=2m horizontal. The channel has a slope of 0.0001 and a Manning's roughness of n = 0.0501. If the uniform flow depth is yn = 7m what is the discharge in the channel? (b) Compute the critical depth (yc) for this trapezoidal channel given discharge from (a)arrow_forwardThe bottom width and bed slope of a long rectangular channel are 4.0 m and 0 0008, respectively. The volumetric steady-state discharge is 1.50 m/s. The flow depth at a specific location is 0 30 m. Ifn=0.016, determine: (a) The type of water surface profile expected Show all work and state your reasoning in support of your work Pleasell!! (b) Sketch the water surface profile with all necessary information and labels shownarrow_forwardA uniform flow occurs in a 4.3m diameter circular concrete culvert, but the depth changes depending on the weather (due to storms). The Manning coefficient is n = 0.014, and the channel slope is So = 0.0004. What is the discharge in m3/s when the depth of flow is 3.3m?arrow_forward
- c) The channel shown in Figure 1 below is laid at a slope of 0.0018 and has a Manning's roughness of 0.015. i) Calculate the discharge for a normal depth of flow of 2.11 m ii) Determine if this channel is mild or steep for this discharge. 10 m YN 10° 10° Figure 1- Question 1 (c)arrow_forwardA trapezoidal channel having a bottom slope of 0.001 is carrying a flow of 30 m³/s. The bottom width is 10.0 m and the side slopes are 2H to 1V. A control structure is built at the downstream end which raises the water depth at the downstream end to 5.0 m. Compute the water surface profile till 1.20 m. Manning n is 0.013 and a = 1. Select an appropriate Ay for your calculations.arrow_forwardA flow of 30 m3 /s occurs in a trapezoidal channel having a base width of 3 m, side slopes 1 vertical to 2 horizontal. Determine the critical depth, yc.arrow_forward
- A concrete-lined, rectangular channel has to be constructed to carry a discharge of 500 cfs. Design the channel assuming that the following values are fixed based on the design conditions: a. Bed slope = 0.002 b. n = 0.015 c. b/y ratio = 2.0 (i.e., the width, ?, is equal to 2y)arrow_forwardcross-sectional area of the channel. 5. Refer to the following channel cross section. Normal depth is 1.50 feet. (a) What is the cross-sectional area of flow? (b) What is the wetted perimeter? (c) What is the hydraulic radius? -8.5'- 1.50' -2.5' 2.5'- -4.5'- 00ation ntion Normal denth is 3 0 fee O Cengage Learning 2014arrow_forward5. A tar coated (n = 0.014) triangular channel has 45ᵒ sides and slope of 0.0004. Compute the normal depth for a discharge of 140 ft3/s.arrow_forward
- 2) For a rectangular open channel the following information is given: Discharge, Q=125 m³/s, cross-section width, b = 10 m, Manning roughness coefficient n = 0.025, channel bottom slope So = 0.00015. Determine: a) Uniform flow depth, yn. (For the first iteration assume yn = 10 m) b) State of the flow. c) Resistance to the flow, t. 个 yn ↓ IK 3-91arrow_forwardThe incoming flow rate is 200 m3/s on a rectangular channel with: depth = 3 meters width = 4 meters Then, a hydraulic jump occurred along the way. Determine the depth at the hydraulic jump section.arrow_forward5.1.3 Determine the uniform flow depth in a rectangular channel 2.5 ;m wide with a discharge of 3 m³/s. The slope is 0.004 and Manning's roughness factor is 0.015.arrow_forward
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