Chapter 5, Problem 5.14P

(a)

Interpretation Introduction

Interpretation:

The pressure in $\text{atm}$ at the peak Everest of the atmospheric pressure is to be calculated.

Concept introduction:

The pressure can be defined as the force per unit area. The atmospheric pressure is also called barometric pressure.

The relation between $\text{atm}$ and $\text{mmHg}$ is as follows:

$760\text{ mmHg}=1\text{ atm}$

The relation between $\text{atm}$ and $\text{torr}$ is as follows:

$760\text{ torr}=1\text{ atm}$

The relation between $\text{atm}$ and $\text{kPa}$ is as follows:

$1\text{ atm}=101.325\text{ kPa}$

The relation between $\text{kPa}$ and $\text{mmHg}$ is as follows:

$1\text{ kPa}=7.500617\text{ mmHg}$

(b)

Interpretation Introduction

Interpretation:

The pressure in $\text{atm}$ in the bike tires is to be calculated.

Concept introduction:

The pressure can be defined as the force per unit area. The atmospheric pressure is also called barometric pressure.

The relation between $\text{atm}$ and $\text{mmHg}$ is as follows:

$760\text{ mmHg}=1\text{ atm}$

The relation between $\text{atm}$ and $\text{torr}$ is as follows:

$760\text{ torr}=1\text{ atm}$

The relation between $\text{atm}$ and $\text{kPa}$ is as follows:

$1\text{ atm}=101.325\text{ kPa}$

The relation between $\text{kPa}$ and $\text{mmHg}$ is as follows:

$1\text{ kPa}=7.500617\text{ mmHg}$

(c)

Interpretation Introduction

Interpretation:

The pressure in $\text{atm}$ at the surface of Venus is to be calculated.

Concept introduction:

The pressure can be defined as the force per unit area. The atmospheric pressure is also called barometric pressure.

The relation between $\text{atm}$ and $\text{mmHg}$ is as follows:

$760\text{ mmHg}=1\text{ atm}$

The relation between $\text{atm}$ and $\text{torr}$ is as follows:

$760\text{ torr}=1\text{ atm}$

The relation between $\text{atm}$ and $\text{kPa}$ is as follows:

$1\text{ atm}=101.325\text{ kPa}$

The relation between $\text{kPa}$ and $\text{mmHg}$ is as follows:

$1\text{ kPa}=7.500617\text{ mmHg}$

(d)

Interpretation Introduction

Interpretation:

The pressure in $\text{atm}$ at the sea level is to be calculated.

Concept introduction:

The pressure can be defined as the force per unit area. The atmospheric pressure is also called barometric pressure.

The relation between $\text{atm}$ and $\text{mmHg}$ is as follows:

$760\text{ mmHg}=1\text{ atm}$

The relation between $\text{atm}$ and $\text{torr}$ is as follows:

$760\text{ torr}=1\text{ atm}$

The relation between $\text{atm}$ and $\text{kPa}$ is as follows:

$1\text{ atm}=101.325\text{ kPa}$

The relation between $\text{kPa}$ and $\text{mmHg}$ is as follows:

$1\text{ kPa}=7.500617\text{ mmHg}$