Loose Leaf for Chemistry
13th Edition
ISBN: 9781260162035
Author: Raymond Chang Dr., Jason Overby Professor
Publisher: McGraw-Hill Education
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Question
Chapter 5, Problem 5.131QP
(a)
Interpretation Introduction
Interpretation:
The rate of CO production and it take to build up a lethal concentration of CO have to be calculated.
Concept introduction:
Ideal gas is the most usually used form of the ideal gas equation, which describes the relationship among the four variables P, V, n, and T. An ideal gas is a hypothetical sample of gas whose pressure-volume-temperature behavior is predicted accurately by the ideal gas equation.
PV = nRT
(a)
Expert Solution
Answer to Problem 5.131QP
The rate of CO production is 0.112 mol CO/min
Explanation of Solution
To calculate the rate of CO production
188 g CO1 h × 1 mol CO28.01 g CO × 1 h60 min = 0.112 mol CO/min
The rate of CO production is calculated by plugging in the values of the given weight of the CO, molecular weight of the CO and time. The rate of CO production was found to be 0.112 mol CO/min.
(b)
Interpretation Introduction
Interpretation:
The rate of CO production and it take to build up a lethal concentration of CO have to be calculated.
Concept introduction:
Ideal gas is the most usually used form of the ideal gas equation, which describes the relationship among the four variables P, V, n, and T. An ideal gas is a hypothetical sample of gas whose pressure-volume-temperature behavior is predicted accurately by the ideal gas equation.
PV = nRT
(b)
Expert Solution
Answer to Problem 5.131QP
The rate of CO production per minute time is 2.0 × 101 min
Explanation of Solution
1000 ppm means that there are 1000 particles of gas per 1,000,000 particles of air. The pressure of a gas is directly proportional to the number of particles of gas. We can calculate the partial pressure of CO in atmospheres, assuming that atmospheric pressure is 1 atm.
1000 particles1,000,000 particles × 1 atm = 1.0 × 10-4 3atm
A partial pressure of 1.0×10-3 atm CO is lethal.
The volume of the garage (in L) is:
(6.0m × 4.0 m × 2.2 m)× (1 cm0.01 m) × 1 L1000 cm3 = 5.3 × 104L
From part (a), we know the rate of CO production per minute. In one minute the partial pressure of CO will be:
PV = nRTPCO=nRTV = (0.112 mol) (0.08206L . atm K . mol) (20+273)K5.3 × 104 L =2.0 × 101 min
The rate of CO production per minute time is calculated by plugging in the values of the given moles, volume and temperature. The rate of CO production per minute time was found to be 2.0 × 101 min
How many minutes will it take for the partial pressure of CO to reach the lethal level, 1.0×10-3 atm?
? min = (1.0 × 10-3 atm CO) × 1 min 5.1× 10-5 atm CO = 2.0 × 10 1 min
It takes for the partial pressure of CO to reach the lethal level is calculated by plugging in the values of the given pressure of CO. It takes for the partial pressure of CO to reach the lethal levelwas found to be 2.0 × 101 min
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Chapter 5 Solutions
Loose Leaf for Chemistry
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