Chapter 5, Problem 5.130MP

Interpretation Introduction

Interpretation:

Thenumber of photons emitted by the light bulb each second needs to be determined, if for a 75 W light bulb, 5.0 % of the energy output is visible light with the average wavelength of the light 550 nm.

Concept introduction:

Electromagnetic radiation can be defined as the waves of the electromagnetic field which can propagate through space and carries the electromagnetic radiant energy. Radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays are some common example of electromagnetic radiations. The relation between the wavelength, energy and frequency of the electromagnetic radiations is as given below:

$\begin{array}{l}\text{E = hν = }\frac{\text{hc}}{\text{λ}}\\ \text{Here:}\\ \text{ν = frequency}\\ \text{c = speed of light }\\ \text{λ = wavelength}\\ \text{h= Planck's constant }\\ \text{E = energy}\end{array}$