Liquid oxygen was first prepared by heating potassium chlorate, KClO 3, in a closed vessel to obtain oxygen at high pressure. The oxygen was cooled until it liquefied. 2 KClO 3 ( s ) → 2 KCl ( s ) + 3 O 2 ( g ) If 171 g of potassium chlorate reacts in a 2.70-L vessel, which was initially evacuated, what pressure of oxygen will be attained when the temperature is finally cooled to 25°C? Use the preceding chemical equation and ignore the volume of solid product.
Liquid oxygen was first prepared by heating potassium chlorate, KClO 3, in a closed vessel to obtain oxygen at high pressure. The oxygen was cooled until it liquefied. 2 KClO 3 ( s ) → 2 KCl ( s ) + 3 O 2 ( g ) If 171 g of potassium chlorate reacts in a 2.70-L vessel, which was initially evacuated, what pressure of oxygen will be attained when the temperature is finally cooled to 25°C? Use the preceding chemical equation and ignore the volume of solid product.
Solution Summary: The author calculates the pressure of oxygen attained by reaction of 171 g of potassium chlorate in a 2.70 L vessel when the temperature is finally cooled.
Liquid oxygen was first prepared by heating potassium chlorate, KClO3, in a closed vessel to obtain oxygen at high pressure. The oxygen was cooled until it liquefied.
2
KClO
3
(
s
)
→
2
KCl
(
s
)
+
3
O
2
(
g
)
If 171 g of potassium chlorate reacts in a 2.70-L vessel, which was initially evacuated, what pressure of oxygen will be attained when the temperature is finally cooled to 25°C? Use the preceding chemical equation and ignore the volume of solid product.
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H
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CFCI:
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Chapter 5 Solutions
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