Chapter 5, Problem 5.111AP

Interpretation Introduction

Interpretation: The amount of liquid ${\text{CF}}_{\text{2}}{\text{Cl}}_{\text{2}}$ required to cool $200\text{g}$ of water from $50.0°\text{C}$ to $40.0°\text{C}$ is to be calculated.

Concept introduction: The quantity of liquid ${\text{CF}}_{\text{2}}{\text{Cl}}_{\text{2}}$ required to cool the given amount of water calculated by the formula,

$q_{\text{water}}=n_{\text{CFC}}\times \Delta H_{\text{vap}}^{\text{ο}}\text{of}\text{CFC}$

To determine: The amount of liquid ${\text{CF}}_{\text{2}}{\text{Cl}}_{\text{2}}$ required to cool $200\text{g}$ of water from $50.0°\text{C}$ to $40.0°\text{C}$.