Organic Chemistry (6th Edition)
Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
bartleby

Concept explainers

Question
Book Icon
Chapter 5, Problem 47P
Interpretation Introduction

(a)

Interpretation: The enantiomers (R and S) for the given biologically active compound are to be drawn.

Concept introduction: Enantiomers of a compound are the stereoisomers which are non-super imposable mirror images. A carbon atom bonded to four different groups is known as a chiral carbon. A compound which has a chiral carbon can be resolved into enantiomers.

The naming of chiral center and geometric isomers are based on Cahn-Ingold-Prelog priority rules. If the priority assigned to each group attached to the chirality center in a molecule is in a clockwise direction, then it is the R-stereoisomer, and if this is counter-clockwise, then it is the S-stereoisomer. R and S-stereoisomer are mirror images of each other.

Interpretation Introduction

(b)

Interpretation: The enantiomers (R and S) for the given biologically active compound are to be drawn.

Concept introduction: Enantiomers of a compound are the stereoisomers which are non-super imposable mirror images. A carbon atom bonded to four different groups is known as a chiral carbon. A compound which has a chiral carbon can be resolved into enantiomers.

The naming of chiral center and geometric isomers are based on Cahn-Ingold-Prelog priority rules. If the priority assigned to each group attached to the chirality center in a molecule is in a clockwise direction, then it is the R-stereoisomer, and if this is counter-clockwise, then it is the S-stereoisomer. R and S-stereoisomer are mirror images of each other.

Blurred answer
Students have asked these similar questions
Identifying the stereochemistry of natural Write the complete common (not IUPAC) name of each molecule below. Note: if a molecule is one of a pair of enantiomers, be sure you start its name with D- or L- so we know which enantiomer it is. molecule H O-C-CH2 H3N. HN N H C=O common name (not the IUPAC name) NH3 ☐ H3N H ☐ CH2 X
> Draw the structure of alanine at pH 1.2. Click and drag to start drawing a structure.
Understanding the general acid-base properties of amino acids O Proteins Imagine each of the molecules shown below was found in an aqueous solution. Can you tell whether the solution is acidic, basic, or neutral? molecule The solution is... 010 H3N-CH-C-OH CH HO CH3 O acidic O basic neutral O (unknown) H3N HO 0 O acidic O basic neutral ○ (unknown) H3N-CH-C-O CH2 CH3-CH-CH3 O acidic O basic Oneutral ○ (unknown) O= X H2N-CH-C-O CH3 CH CH3 acidic O basic O neutral ○ (unknown) ? 000
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Text book image
Macroscale and Microscale Organic Experiments
Chemistry
ISBN:9781305577190
Author:Kenneth L. Williamson, Katherine M. Masters
Publisher:Brooks Cole