a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora . Introduction: In Neurospora , after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Question

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Answer 1

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

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After you feel comfortable with your counting method and identifying cells in the various stages of mitosis, use the four images below of whitefish blastula to count the cells in each stage until you reach 100 total cells, recording your data below in Data Table 1. (You may not need to use all four images. Stop counting when you reach 100 total cells.) After totaling the cells in each stage, calculate the percent of cells in each stage. (Divide total of stage by overall total of 100 and then multiply by 100 to obtain percentage.) Data Table 1Stage Totals PercentInterphase Mitosis: Prophase Metaphase Anaphase Telophase Cytokinesis Totals 100 100% To find the length of time whitefish blastula cells spend in each stage, multiply the percent (recorded as a decimal, in other words take the percent number and divide by 100) by 24 hours. (Example: If percent is 20%, then Time in Hours = .2 * 24 = 4.8) Record your data in Data…

Answer 2

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Expert Solution & Answer

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See solution

Answer 3

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Expert Solution & Answer

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Answer 4

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Answer 6

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Answer 7

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Answer 8

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Answer 9

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Answer 10

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Answer 11

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Answer 12

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Answer 13

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Answer 14

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Answer 15

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Answer 16

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Answer 17

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Answer 18

Expert Solution & Answer

Answer 19

Expert Solution & Answer

Answer 20

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Answer 21

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a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora . Introduction: In Neurospora , after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Solution Summary: The author analyzes the results obtained from mating mutant strains with wild-type Neurospora. One mutant gene is responsible for trp - phenotype.

Concept explainers

Videos

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Want to see the full answer?

Chapter 5 Solutions

a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora . Introduction: In Neurospora , after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Solution Summary: The author analyzes the results obtained from mating mutant strains with wild-type Neurospora. One mutant gene is responsible for trp - phenotype.

Concept explainers

Videos

a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora. Introduction: In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

b. To determine: The conclusions that can be drawn by the results obtained from mating mutant strains. Introduction: Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp- phenotype results from one mutant gene.

d. To draw: The genetic map that can provide a suitable explaination for the given data. Introduction: The cross between trp1 and trp2 can be represented as follows: trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

e. To determine: The reason that the given case does not present the mating in the table as ordered octads. Introduction: First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

f. To determine: The reason that the distance between gene and centromere can be observed from crosses given in the table. Introduction: SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Want to see the full answer?

Chapter 5 Solutions

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.