Chapter 5, Problem 45E

(a)

Interpretation Introduction

Interpretation:Flask with greater initial pressure and extent of greater pressure should to be identified.

Concept introduction: The expression to calculate partial pressure due to mole fraction is as follows:

  $P=\chi \cdot P_{\text{Total}}$

Where,

• $P_{\text{Total}}$ denotes total pressure of mixture of gases.
• $P$ denotes the partial pressure.
• $\chi$ denotes mole fraction.

(b)

Interpretation Introduction

Interpretation:Diagram after the stopcock between the two flasks is opened should to be drawn.

Concept introduction: The expression to calculate partial pressure due to mole fraction is as follows:

  $P=\chi \cdot P_{\text{Total}}$

Where,

• $P_{\text{Total}}$ denotes total pressure of mixture of gases.
• $P$ denotes the partial pressure.
• $\chi$ denotes mole fraction.

(c)

Interpretation Introduction

Interpretation:Final pressure in terms of original pressure of helium and neon has to be calculated.

Concept introduction: The expression to calculate partial pressure due to mole fraction is as follows:

  $P=\chi \cdot P_{\text{Total}}$

Where,

• $P_{\text{Total}}$ denotes total pressure of mixture of gases.
• $P$ denotes the partial pressure.
• $\chi$ denotes mole fraction.

(d)

Interpretation Introduction

Interpretation: Final pressure of helium and neon flask in terms of original pressure has to be calculated.

Concept introduction: The expression to calculate partial pressure due to mole fraction is as follows:

  $P=\chi \cdot P_{\text{Total}}$

Where,

• $P_{\text{Total}}$ denotes total pressure of mixture of gases.
• $P$ denotes the partial pressure.
• $\chi$ denotes mole fraction.