Chapter 5, Problem 36P

A monochromatic light that passes through a double slit produces on a screen a diffraction pattern consisting of bright and dark fringes. The intensity of the bright fringes, I, as a function of ? can be calculated by:

$I=I(\cos \beta ){}^2{\left(\frac{\sin \alpha }{\alpha }\right)}^2$ where $\alpha =\frac{\pi a}{\lambda }\sin \theta$ and $\beta =\frac{\pi d}{\lambda }\sin \theta$ , ? is the light wave length, a is the width of the slits, and d is the distance between the slits. Plot (as shown) the relative intensity I/I_max as a function of y (distance to fringes on the screen) for $-4\le y\le 4$ cm given ?= 480 nm, a=0.025 mm, and d=0.09 mm.