To determine Compute the range of R x that yields a CMRR ≥ 1500 in the given difference amplifier. Explanation Given data: Refer to Figure P5.34 in the textbook for difference amplifier. Formula used: By comparing the given figure with the Figure 5.15 in the textbook. Write the expression for the differential mode gain of the difference amplifier. A dm = R d ( R a + R b ) + R b ( R x + R d ) 2 R a ( R x + R d ) (1) Here, R a , R b , R x , and R d are the circuit resistance of the difference amplifier. Write the expression for the common mode gain of the difference amplifier. A cm = R a R d − R b R x R a ( R x + R d ) (2) Write the formula for the CMRR of the difference amplifier. CMRR = | A dm A cm | (3) Calculation: By comparing the given figure with the Figure 5.15 in the textbook, the value of resistance R a , R b , and R d are 3 k Ω , 6 k Ω , and 6 k Ω respectively. Substitute 3 k Ω for R a , 6 k Ω for R b , and 6 k Ω for R d in equation (1) to find A dm . A dm = ( 6000 ) ( 3000 + 6000 ) + ( 6000 ) ( R x + 6000 ) 2 ( 3000 ) ( R x + 6000 ) { ∵ 1 k = 10 3 } A dm = 54000000 + ( 6000 ) ( R x + 6000 ) 6000 ( R x + 6000 ) (4) Substitute 3 k Ω for R a , 6 k Ω for R b , and 6 k Ω for R d in equation (1) to find A cm . A cm = ( 3000 ) ( 6000 ) − ( 6000 ) R x ( 3000 ) ( R x + 6000 ) { ∵ 1 k = 10 3 } A cm = 18000000 − 6000 R x ( 3000 ) ( R x + 6000 ) (5) Substitute equation (4) and (5) in equation (3)

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ISBN: 8220100801792

Author: Riedel

Publisher: YUZU

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Differential amplifier

There are two amplifying stages with common degeneration in a differential amplifier.

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Chapter 5, Problem 34P

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Compute the range of Rx that yields a CMRR≥1500 in the given difference amplifier.

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Chapter 5, Problem 33P

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Chapter 5 Solutions

EBK ELECTRIC CIRCUITS

Ch. 5.2 - Assume that the op amp in the circuit shown is...Ch. 5.3 - The source voltage vs in the circuit in Assessment...Ch. 5.4 - Find vo in the circuit shown if va = 0.1 V and vb...Ch. 5.5 - Assume that the op amp in the circuit shown is...Ch. 5.6 - In the difference amplifier shown, vb = 4.0 V....Ch. 5.7 - The inverting amplifier in the circuit shown has...Ch. 5 - Prob. 1P Ch. 5 - Replace the 2 V source in the circuit in Fig. P5.1...Ch. 5 - Find iL (in milliamperes) in the circuit in Fig....Ch. 5 - The op amp in the circuit in Fig. P5.4 is...

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