For a projectile launched from ground level at an angle of elevation θ with an initial velocity v 0 , the maximum horizontal range is given by x max = v 0 2 sin 2 θ g , where g is the acceleration due to gravity g = 32 f t / sec 2 or g = 9.8 m / s e c 2 . If a toy rocket is launched from the ground with an initial velocity of 50 f t / sec and lands 73 ft from the launch point, find the angle of elevation of the rocket at launch. Round to the nearest tenth of a degree.
For a projectile launched from ground level at an angle of elevation θ with an initial velocity v 0 , the maximum horizontal range is given by x max = v 0 2 sin 2 θ g , where g is the acceleration due to gravity g = 32 f t / sec 2 or g = 9.8 m / s e c 2 . If a toy rocket is launched from the ground with an initial velocity of 50 f t / sec and lands 73 ft from the launch point, find the angle of elevation of the rocket at launch. Round to the nearest tenth of a degree.
Solution Summary: The author calculates the angle of elevation of the rocket if a toy rocket is launched from the ground with an initial velocity of 50ft/sec and lands at theta
For a projectile launched from ground level at an angle of elevation
θ
with an initial velocity
v
0
,the maximum horizontal range is given by
x
max
=
v
0
2
sin
2
θ
g
, where
g
is the acceleration due to gravity
g
=
32
f
t
/
sec
2
or
g
=
9.8
m
/
s
e
c
2
. If a toy rocket is launched from the ground with an initial velocity of
50
f
t
/
sec
and lands 73 ft from the launch point, find the angle of elevation of the rocket at launch. Round to the nearest tenth of a degree.
For each given function f(x) find f'(x) using the rules learned in section 9.5.
1. f(x)=x32
32x
2. f(x)=7x+13
3. f(x) =
x4
4. f(x) = √√x³
5. f(x) = 3x²+
3
x2
Find:
lim x →-6 f (x)
limx-4 f (x)
lim x-1 f (x)
lim x →4 f (x)
(-6,3) •
(-1,5)
-8
-7
(-6,-2)
4+
(4,5)
(4,2) •
(-1,1)
-6
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