Chapter 5, Problem 32T

For a projectile launched from ground level at an angle of elevation $\theta$ with an initial velocity $v_0$ , the maximum horizontal range is given by $x_{\max }=\frac{v_{{}_0}^2\sin 2\theta }{g}$ , where $g$ is the acceleration due to gravity $\left(g=32ft/{\sec }^2\text{or}g=9.8m/se{c}^2\right)$ . If a toy rocket is launched from the ground with an initial velocity of $50ft/\sec$ and lands 73 ft from the launch point, find the angle of elevation of the rocket at launch. Round to the nearest tenth of a degree.