
(a)
Interpretation:
To determine the incorrect formula name pair. The name pair is Ag(NO3 )2 - Silver nitrate.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named incorrect according to the formula of the compound given.
Explanation of Solution
The Ag(NO3 )2 is named incorrcetly. When one Silver and one nitrate ion combines together to form silver nitrate and balanced the overall charge. So, It is named correctly.
(b)
Interpretation:
To determine the incorrect formula name pair. The name pair is Fe2 Cl−Ferrous chloride.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named incorrect according to the formula of the compound given.
Explanation of Solution
The Fe2 Cl is named as ferrous chloride is incorrect. When one Fe and two Cl ion combines together to form FeCl2 and balanced the overall charge then it is named as ferrous chloride.
(c)
Interpretation:
To determine the incorrect formula name pair. The name pair is NaH2 PO4 −Sodium hydrogen phosphate.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named incorrect according to the formula of the compound given.
Explanation of Solution
The NaH2 PO4 is named incorrectly. When two sodium and one HPO4 2 - is combine and balanced the overall charge then it is name as Sodium hydrogen phosphate.
(d)
Interpretation:
To determine the incorrect formula name pair. The name pair is NH4 S−Ammonium sulfide.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named incorrectly according to the formula of the compound given.
Explanation of Solution
The NH4 S is named incorrcetly. When twoNH4 and one sulfide ion combines together to form ammonium sulfide and balanced the overall charge. So, It is named correctly.
(e)
Interpretation:
To determine the incorrect formula name pair. The name pair is KC2 H3 O2 - Potassium acetate.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named incorrect according to the formula of the compound given.
Explanation of Solution
TheKC2 H3 O2 is named as Potassium acetate. When twopotassium and one acetate ion combines together to form potassium acetate and balanced the overall charge. So, It is named correctly.
(f)
Interpretation:
To determine the incorrect formula name pair. The name pair is Ca(ClO4 )2 −Calcium perchlorate.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named correctly according to the formula of the compound given.
Explanation of Solution
The Ca(ClO4 )2 is named as Calcium perchlorate. When one Ca and two Perchlorate ion combines together to form Calcium perchlorate and balanced the overall charge. So, It is named correctly.
(g)
Interpretation:
To determine the incorrect formula name pair. The name pair is K2 Cr2 O7 −Potassium dichromate.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named correctly according to the formula of the compound given.
Explanation of Solution
The K2 Cr2 O7 is named as Potassium dichromate. When twopotassium and one dichromate ion combines together to form potassium dichromate and balanced the overall charge. So, It is named correctly.
(h)
Interpretation:
To determine the incorrect formula name pair. The name pair is BaOH−Barium hydroxide.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named incorrect according to the formula of the compound given.
Explanation of Solution
The BaOH is named as Barium hydroxide. When one Barium and two hydroxide ion combines together to form barium hydroxide and balanced the overall charge. So, It is named correctlyBa(OH)2.
(i)
Interpretation:
To determine the incorrect formula name pair. The name pair is Na2O2 − Sodium peroxide.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named correctly according to the formula of the compound given.
Explanation of Solution
The Na2O2 is named as Sodium peroxide. When two sodiumion and two oxide ion combines together to form Sodium oxide and balanced the overall charge. So, It is named correctly.
(j)
Interpretation:
To determine the incorrect formula name pair. The name pair is Ca(CO3 )2 - Silver nitrate.
Concept Introduction:
The compound formed by cationic and anionic species is named as first cation name and then secondly the name of anion. The compound formed by ions may have high or less ionic character because it can be formed by metal or may be by nonmetal or the combination of metal and nonmetal both.
So, to check the correct formulation of ionic compound and its naming we must have to balance the charge present on the ionic species.

Answer to Problem 27CR
The given pair is named incorrect according to the formula of the compound given.
Explanation of Solution
The Ca(CO3 )2 is named as Calcium carbonate. When one Calcium and onecarbonate ion combines together to form calcium carbonate and balanced the overall charge. So, It is named correctly as Ca(CO3 )2.
Want to see more full solutions like this?
Chapter 5 Solutions
Introductory Chemistry >IC<
- How many particles does a face-centered cubic (fcc) unit cell contain? Group of answer choices 2 14 8 4arrow_forwardV Highlight all of the carbon atoms that have at least one beta (B) hydrogen, using red for one ẞ hydrogen, blue for two ẞ hydrogens, and green for three ẞ hydrogens. If none of the carbon atoms have ẞ hydrogens, check the box underneath the molecule. ED X None of the carbon atoms have ẞ hydrogens. Explanation esc 2 Check * F1 F2 1 2 80 # 3 Q W tab A caps lock shift fn control F3 N S option O 694 $ F4 F5 F6 005 % E R D F LL 6 olo 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility A DII F7 F8 87 & * 8 T Y U G H 4 F9 F10 ( 9 0 E F11 F12 உ J K L + || X C V B N M H H command option commandarrow_forwardConsider the reaction below and answer the following questions. Part 1 of 4 Br NaOCH2CH3 Identify the mechanisms involved. Check all that apply. SN 1 SN 2 E1 E2 None of the above Part 2 of 4 Skip Part Check esc F1 F2 lock 1 2 Q W A S #3 80 F3 F4 F5 F6 Save For © 2025 McGraw Hill LLC. All Rights Reserved. Terms ˇˇ % & 4 5 6 89 7 IK A 分 བ F7 F8 F9 F * E R T Y U 8 9 D F G H K V B N M 0 Oarrow_forward
- What kind of holes are not generated when solid-state particles adopt a close packing pattern? Group of answer choices tetrahedral cubic octahedral None of the other choices are correctarrow_forwardFor the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. 田 Major Product: Check ☐ + I Na OH esc F1 F2 2 1 @ 2 Q W tab A caps lock S #3 80 F3 69 4 σ F4 % 95 S Click and drag to sta drawing a structure mm Save For Later 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use GO DII F5 F6 F7 F8 F9 F10 6 CO 89 & 7 LU E R T Y U 8* 9 0 D F G H J K L Z X C V B N M 36arrow_forwardProblem 7 of 10 Draw the major product of this reaction. Ignore inorganic byproducts. S' S 1. BuLi 2. ethylene oxide (C2H4O) Select to Draw a Submitarrow_forward
- Feedback (4/10) 30% Retry Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the reactant and missing intermediates involved in this reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. Incorrect, 6 attempts remaining :0: Draw the Reactant H H3CO H- HIO: Ö-CH3 CH3OH2* protonation H. a H (+) H Ο CH3OH2 O: H3C protonation CH3OH deprotonation > CH3OH nucleophilic addition H. HO 0:0 Draw Intermediate a Xarrow_forwardCan I please get the blank spaces answered/answers?arrow_forward1. Identify the following alkenes as E or Z NH₂ Br 2. Draw the structures based on the IUPAC names (3R,4R)-3-bromo-4-fluoro- 1-hexene (Z)-4-bromo-2-iodo-3-ethyl- 3-heptene تر 3. For the following, predict all possible elimination product(s) and circle the major product. HO H₂SO4 Heat 80 F4 OH H2SO4 Heat 어요 F5 F6 1 A DII 4 F7 F8 F9 % & 5 6 7 * ∞ 8 BAB 3 E R T Y U 9 F D G H J K O A F11 F10arrow_forward
- Draw the major product of this reaction. Ignore inorganic byproducts. ○ O 1. H₂O, pyridine 2. neutralizing work-up a N W X 人 Parrow_forward✓ Check the box under each molecule that has a total of five ẞ hydrogens. If none of the molecules fit this description, check the box underneath the table. tab OH CI 0 Br xx Br None of these molecules have a total of five ẞ hydrogens. esc Explanation Check caps lock shift 1 fn control 02 F2 W Q A N #3 S 80 F3 E $ t 01 205 % 5 F5 & 7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility FT * 8 R T Y U כ F6 9 FIG F11 F D G H J K L C X V B < N M H option command P H + F12 commandarrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts and the carboxylic acid side product. O 1. CHзMgBr (excess) 2. H₂O ✓ W X 人arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning





