The solution of the provided system of equation by using any method of your choice and determine whether the system with no solution and system with infinitely many solution.

Question

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Answer 1

Question

Chapter 5, Problem 1RE

To determine

The solution of the provided system of equation by using any method of your choice and determine whether the system with no solution and system with infinitely many solution.

Expert Solution & Answer

Answer to Problem 1RE

The solution set is {−1,2}.

Explanation of Solution

Given information:

The provided system of equation is shown below:

{ 3x−y=−5 x+2y=3}(1)(2)

Formula used:

Solving Linear System by Substitution:

Step 1: Solve either of the equations for one variable in terms of the other. (If one of the equations is already in this form, we can skip this step).

Step 2: Substitute the expression found in step 1 into the other equation. This will result in an equation in one variable.

Step 3: Solve the equation containing one variable.

Step 4: Back-substitute the value found in step 3 into one of the original equations. Simplify and find the value of the remaining variable.

Step 5: Check the proposed solution in both of the system’s give equations.

Calculation:

First, solve one of the equation for any of the variable x or y. Since the coefficient of x in equation (2) is 1. So, its easy to solve for x in equation (2).

x=3−2y

Now, substitute the value of x in equation (1), we get

3(3−2y)−y=−59−6y−y=−5 (Distributive Property)9−7y=−59−7y−9=−5−9 (Subtract 9 from both sides)−7y=−14−7y−7=−14−7 (Divide both sides by -7)y=2

Substitute the value of y in equation (2), we get

x+2(2)=3x+4=3x=3−4x=−1

Now, we have to check the above solution.

Substitute the value of x=−1 and y=2 in an equation (1), we get

3(−1)−(2)=?−5−3−2=?−5−5=−5 (True)

Substitute the value of x=−1 and y=2 in an equation (2), we get

(−1)+2(2)=?3−1+4=?33=3 (True)

Therefore, the required solution set is {−1,2}.

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Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution. Remember that: A matrix is in row echelon form if Any row that consists only of zeros is at the bottom of the matrix. The first non-zero entry in each other row is 1. This entry is called aleading 1. The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.

PRIMERA EVALUACIÓN SUMATIVA 10. Determina la medida de los ángulos in- teriores coloreados en cada poligono. ⚫ Octágono regular A 11. Calcula es número de lados qu poligono regular, si la medida quiera de sus ángulos internos • a=156° A= (-2x+80 2 156 180- 360 0 = 24-360 360=24° • a = 162° 1620-180-360 6=18-360 360=19 2=360= 18 12. Calcula las medida ternos del cuadrilá B X+5 x+10 A X+X+ Sx+6 5x=3 x=30 0 лаб • Cuadrilátero 120° 110° • α = 166° 40' 200=180-360 0 = 26-360 360=20 ひ=360 20 18 J 60° ⚫a=169° 42' 51.43" 169.4143180-340 0 = 10.29 54-360 360 10.2857 2=360 10.2857 @Sa

Please help I'm a working mom trying to help my son last minute (6th grader)! Need help with the blank ones and check the ones he got with full calculation so we can use it to study! Especially the mixed number fractions cause I'm rusty. Thanks in advance!

Answer 2

Question

Chapter 5, Problem 1RE

To determine

The solution of the provided system of equation by using any method of your choice and determine whether the system with no solution and system with infinitely many solution.

Expert Solution & Answer

Answer to Problem 1RE

The solution set is {−1,2}.

Explanation of Solution

Given information:

The provided system of equation is shown below:

{ 3x−y=−5 x+2y=3}(1)(2)

Formula used:

Solving Linear System by Substitution:

Step 1: Solve either of the equations for one variable in terms of the other. (If one of the equations is already in this form, we can skip this step).

Step 2: Substitute the expression found in step 1 into the other equation. This will result in an equation in one variable.

Step 3: Solve the equation containing one variable.

Step 4: Back-substitute the value found in step 3 into one of the original equations. Simplify and find the value of the remaining variable.

Step 5: Check the proposed solution in both of the system’s give equations.

Calculation:

First, solve one of the equation for any of the variable x or y. Since the coefficient of x in equation (2) is 1. So, its easy to solve for x in equation (2).

x=3−2y

Now, substitute the value of x in equation (1), we get

3(3−2y)−y=−59−6y−y=−5 (Distributive Property)9−7y=−59−7y−9=−5−9 (Subtract 9 from both sides)−7y=−14−7y−7=−14−7 (Divide both sides by -7)y=2

Substitute the value of y in equation (2), we get

x+2(2)=3x+4=3x=3−4x=−1

Now, we have to check the above solution.

Substitute the value of x=−1 and y=2 in an equation (1), we get

3(−1)−(2)=?−5−3−2=?−5−5=−5 (True)

Substitute the value of x=−1 and y=2 in an equation (2), we get

(−1)+2(2)=?3−1+4=?33=3 (True)

Therefore, the required solution set is {−1,2}.

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Answer 3

Question

Chapter 5, Problem 1RE

To determine

The solution of the provided system of equation by using any method of your choice and determine whether the system with no solution and system with infinitely many solution.

Expert Solution & Answer

Answer to Problem 1RE

The solution set is {−1,2}.

Explanation of Solution

Given information:

The provided system of equation is shown below:

{ 3x−y=−5 x+2y=3}(1)(2)

Formula used:

Solving Linear System by Substitution:

Step 1: Solve either of the equations for one variable in terms of the other. (If one of the equations is already in this form, we can skip this step).

Step 2: Substitute the expression found in step 1 into the other equation. This will result in an equation in one variable.

Step 3: Solve the equation containing one variable.

Step 4: Back-substitute the value found in step 3 into one of the original equations. Simplify and find the value of the remaining variable.

Step 5: Check the proposed solution in both of the system’s give equations.

Calculation:

First, solve one of the equation for any of the variable x or y. Since the coefficient of x in equation (2) is 1. So, its easy to solve for x in equation (2).

x=3−2y

Now, substitute the value of x in equation (1), we get

3(3−2y)−y=−59−6y−y=−5 (Distributive Property)9−7y=−59−7y−9=−5−9 (Subtract 9 from both sides)−7y=−14−7y−7=−14−7 (Divide both sides by -7)y=2

Substitute the value of y in equation (2), we get

x+2(2)=3x+4=3x=3−4x=−1

Now, we have to check the above solution.

Substitute the value of x=−1 and y=2 in an equation (1), we get

3(−1)−(2)=?−5−3−2=?−5−5=−5 (True)

Substitute the value of x=−1 and y=2 in an equation (2), we get

(−1)+2(2)=?3−1+4=?33=3 (True)

Therefore, the required solution set is {−1,2}.

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Answer 4

Question

Chapter 5, Problem 1RE

To determine

The solution of the provided system of equation by using any method of your choice and determine whether the system with no solution and system with infinitely many solution.

Expert Solution & Answer

Answer to Problem 1RE

The solution set is {−1,2}.

Explanation of Solution

Given information:

The provided system of equation is shown below:

{ 3x−y=−5 x+2y=3}(1)(2)

Formula used:

Solving Linear System by Substitution:

Step 1: Solve either of the equations for one variable in terms of the other. (If one of the equations is already in this form, we can skip this step).

Step 2: Substitute the expression found in step 1 into the other equation. This will result in an equation in one variable.

Step 3: Solve the equation containing one variable.

Step 4: Back-substitute the value found in step 3 into one of the original equations. Simplify and find the value of the remaining variable.

Step 5: Check the proposed solution in both of the system’s give equations.

Calculation:

First, solve one of the equation for any of the variable x or y. Since the coefficient of x in equation (2) is 1. So, its easy to solve for x in equation (2).

x=3−2y

Now, substitute the value of x in equation (1), we get

3(3−2y)−y=−59−6y−y=−5 (Distributive Property)9−7y=−59−7y−9=−5−9 (Subtract 9 from both sides)−7y=−14−7y−7=−14−7 (Divide both sides by -7)y=2

Substitute the value of y in equation (2), we get

x+2(2)=3x+4=3x=3−4x=−1

Now, we have to check the above solution.

Substitute the value of x=−1 and y=2 in an equation (1), we get

3(−1)−(2)=?−5−3−2=?−5−5=−5 (True)

Substitute the value of x=−1 and y=2 in an equation (2), we get

(−1)+2(2)=?3−1+4=?33=3 (True)

Therefore, the required solution set is {−1,2}.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 5, Problem 1RE

To determine

The solution of the provided system of equation by using any method of your choice and determine whether the system with no solution and system with infinitely many solution.

Expert Solution & Answer

Answer to Problem 1RE

The solution set is {−1,2}.

Explanation of Solution

Given information:

The provided system of equation is shown below:

{ 3x−y=−5 x+2y=3}(1)(2)

Formula used:

Solving Linear System by Substitution:

Step 1: Solve either of the equations for one variable in terms of the other. (If one of the equations is already in this form, we can skip this step).

Step 2: Substitute the expression found in step 1 into the other equation. This will result in an equation in one variable.

Step 3: Solve the equation containing one variable.

Step 4: Back-substitute the value found in step 3 into one of the original equations. Simplify and find the value of the remaining variable.

Step 5: Check the proposed solution in both of the system’s give equations.

Calculation:

First, solve one of the equation for any of the variable x or y. Since the coefficient of x in equation (2) is 1. So, its easy to solve for x in equation (2).

x=3−2y

Now, substitute the value of x in equation (1), we get

3(3−2y)−y=−59−6y−y=−5 (Distributive Property)9−7y=−59−7y−9=−5−9 (Subtract 9 from both sides)−7y=−14−7y−7=−14−7 (Divide both sides by -7)y=2

Substitute the value of y in equation (2), we get

x+2(2)=3x+4=3x=3−4x=−1

Now, we have to check the above solution.

Substitute the value of x=−1 and y=2 in an equation (1), we get

3(−1)−(2)=?−5−3−2=?−5−5=−5 (True)

Substitute the value of x=−1 and y=2 in an equation (2), we get

(−1)+2(2)=?3−1+4=?33=3 (True)

Therefore, the required solution set is {−1,2}.

Answer 6

Chapter 5, Problem 1RE

To determine

The solution of the provided system of equation by using any method of your choice and determine whether the system with no solution and system with infinitely many solution.

Expert Solution & Answer

Answer to Problem 1RE

The solution set is {−1,2}.

Explanation of Solution

Given information:

The provided system of equation is shown below:

{ 3x−y=−5 x+2y=3}(1)(2)

Formula used:

Solving Linear System by Substitution:

Step 1: Solve either of the equations for one variable in terms of the other. (If one of the equations is already in this form, we can skip this step).

Step 2: Substitute the expression found in step 1 into the other equation. This will result in an equation in one variable.

Step 3: Solve the equation containing one variable.

Step 4: Back-substitute the value found in step 3 into one of the original equations. Simplify and find the value of the remaining variable.

Step 5: Check the proposed solution in both of the system’s give equations.

Calculation:

First, solve one of the equation for any of the variable x or y. Since the coefficient of x in equation (2) is 1. So, its easy to solve for x in equation (2).

x=3−2y

Now, substitute the value of x in equation (1), we get

3(3−2y)−y=−59−6y−y=−5 (Distributive Property)9−7y=−59−7y−9=−5−9 (Subtract 9 from both sides)−7y=−14−7y−7=−14−7 (Divide both sides by -7)y=2

Substitute the value of y in equation (2), we get

x+2(2)=3x+4=3x=3−4x=−1

Now, we have to check the above solution.

Substitute the value of x=−1 and y=2 in an equation (1), we get

3(−1)−(2)=?−5−3−2=?−5−5=−5 (True)

Substitute the value of x=−1 and y=2 in an equation (2), we get

(−1)+2(2)=?3−1+4=?33=3 (True)

Therefore, the required solution set is {−1,2}.

Answer 7

Chapter 5, Problem 1RE

To determine

The solution of the provided system of equation by using any method of your choice and determine whether the system with no solution and system with infinitely many solution.

Answer 8

Expert Solution & Answer

Answer to Problem 1RE

The solution set is {−1,2}.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given information:

The provided system of equation is shown below:

{ 3x−y=−5 x+2y=3}(1)(2)

Formula used:

Solving Linear System by Substitution:

Step 1: Solve either of the equations for one variable in terms of the other. (If one of the equations is already in this form, we can skip this step).

Step 2: Substitute the expression found in step 1 into the other equation. This will result in an equation in one variable.

Step 3: Solve the equation containing one variable.

Step 4: Back-substitute the value found in step 3 into one of the original equations. Simplify and find the value of the remaining variable.

Step 5: Check the proposed solution in both of the system’s give equations.

Calculation:

First, solve one of the equation for any of the variable x or y. Since the coefficient of x in equation (2) is 1. So, its easy to solve for x in equation (2).

x=3−2y

Now, substitute the value of x in equation (1), we get

3(3−2y)−y=−59−6y−y=−5 (Distributive Property)9−7y=−59−7y−9=−5−9 (Subtract 9 from both sides)−7y=−14−7y−7=−14−7 (Divide both sides by -7)y=2