
(a)
The precision of the given measurement number.
(a)

Answer to Problem 1P
The measurement number 4.27 psi is precise to nearest
Explanation of Solution
Definition used:
Precision of a measurement number is indicated by the place value of its right most significant digits.
Calculation:
The given measurement number is 4.27 psi.
The right most significant digit of 4.27 psi is “7”.
The place value of 7 in 4.27 psi is hundredth.
Hence by the above definition, the measurement number 4.27 psi is precise to nearest
(b)
The precision of the given measurement number.
(b)

Answer to Problem 1P
The measurement number 6758 psi is precise to nearest
Explanation of Solution
Definition used:
Precision of a measurement number is indicated by the place value of its right most significant digits.
Calculation:
The given measurement number is 6758 psi.
The right most significant digit of 6758 psi is “8”.
The place value of 8 in 6758 psi is once.
Hence by the above definition, the measurement number 6758 psi is precise to nearest
(c)
The precision of the given measurement number.
(c)

Answer to Problem 1P
The measurement number 350 psi is precise to nearest
Explanation of Solution
Definition used:
Precision of a measurement number is indicated by the place value of its right most significant digits.
Calculation:
The given measurement number is 350 psi.
The right most significant digit of 350 psi is “5”.
The place value of 5 in 350 psi is tens.
Hence by the above definition, the measurement number 350 psi is precise to nearest
(d)
The number of significant digits of the given measurement number.
(d)

Answer to Problem 1P
The number of significant digits of the given measurement number in 9.6 kg is
Explanation of Solution
Rule used:
To determine the number of significant digits, follow these rules:
Rule 1: “Digits other than zero are always significant.
Rule 2: A zero is significant when it:
(a) appears between two significant digits.
(b) Is at the right end of a decimal number.
(c) Is marked as significant with an overbar.
Rule 3: A zero is not significant when it
(a) Is at the right end of a whole number.
(b) Is at left end of a number.”
Calculation:
The given measurement number is 9.6 kg.
The number of digits other than zero in 9.6 kg is “2”.
Therefore by the rule 1, the number of significant digits of the given measurement number in 9.6 kg is
(e)
The number of significant digits of the given measurement number.
(e)

Answer to Problem 1P
The number of significant digits of the given measurement number in 458 kg is
Explanation of Solution
The given measurement number is 458 kg.
The number of digits other than zero in 458 kg is “3”.
Therefore by the rule 1 mentioned in the subpart (d) , the number of significant digits of the given measurement number in 458 kg is
(f)
The number of significant digits of the given measurement number.
(f)

Answer to Problem 1P
The number of significant digits of the given measurement number in 6000 kg is
Explanation of Solution
The given measurement number is 6000 kg.
The number of digits other than zero in 6000 kg is “1”.
Also note that the zeroes in the measurement number 6000 kg is not significant as they are to the right of a whole number.
Therefore by the rule 1 and 3 mentioned in the subpart (d) the number of significant digits of the given measurement number in 6000 kg is
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Mathematics for the Trades: A Guided Approach (10th Edition) - Standalone book
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