The term used for the repeating back-and-forth motion, from the following options. spring. vibration. wave. pulse.

Question

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Answer 1

Question

Chapter 5, Problem 1AC

To determine

The term used for the repeating back-and-forth motion, from the following options.

spring.

vibration.

wave.

pulse.

Expert Solution & Answer

Answer to Problem 1AC

Solution:

Option (b) is correct.

Explanation of Solution

Reason for the correct options:

The term vibration is used for the motion of a particle which repeats itself. Hence, a back-and-forth motion that repeats itself is termed as a vibration.

Hence, option (b) is correct.

Reason for the incorrect options:

Option (a) is incorrect because spring itself does not create back-and-forth motion. When the spring is attached with a mass at its end and can compress or stretch, then the motion it creates is back-and-forth motion about its unstretched position. So, it is a wrong answer.

Option (c) is incorrect because the wave is an example of back-and-forth motion but in this case, the movement may or may not involve matter. It does not repeat itself. So, it is a wrong answer.

Option (d) is incorrect because the pulse is a type of non-sinusoidal wave. It is a type of back-and-forth motion, but it does not repeat itself. So, it is a wrong answer.

Hence, options (a), (c) and (d) are incorrect.

Conclusion:

The vibration is a repeating back-and-forth motion.

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Race car driver is cruising down the street at a constant speed of 28.9 m/s (~65 mph; he has a “lead” foot) when the traffic light in front of him turns red. a) If the driver’s reaction time is 160 ms, how far does he and his car travel down the road from the instant he sees the light change to the instant he begins to slow down? b) If the driver’s combined reaction and movement time is 750 ms, how far do he and his car travel down the road from the instant he sees the light change to the instant he slams on her brakes and car begins to slow down? Please answer parts a-B. Show all work. For each question draw a diagram to show the vector/s. Show all the step and provide units in the answers. Provide answer to 2 decimal places. DONT FORGET TO DRAW VECTORS! ONLY USE BASIC FORMULAS TAUGHT IN PHYSICS. distance = speed * time.

Race car driver is cruising down the street at a constant speed of 28.9 m/s (~65 mph; he has a “lead” foot) when the traffic light in front of him turns red. a) If the driver’s reaction time is 160 ms, how far does he and his car travel down the road from the instant he sees the light change to the instant he begins to slow down? b) If the driver’s combined reaction and movement time is 750 ms, how far do he and his car travel down the road from the instant he sees the light change to the instant he slams on her brakes and car begins to slow down? c) If the driver’s average rate of acceleration is -9.5 m/s2 as he slows down, how long does it take him to come to a stop (use information about his speed of 28.9 m/s but do NOT use his reaction and movement time in this computation)? Please answer parts a-c. Show all work. For each question draw a diagram to show the vector/s. Show all the step and provide units in the answers. Provide answer to 2 decimal places unless stated otherwise.…

How is it that part a is connected to part b? I can't seem to solve either part and don't see the connection between the two.

Answer 2

Question

Chapter 5, Problem 1AC

To determine

The term used for the repeating back-and-forth motion, from the following options.

spring.

vibration.

wave.

pulse.

Expert Solution & Answer

Answer to Problem 1AC

Solution:

Option (b) is correct.

Explanation of Solution

Reason for the correct options:

The term vibration is used for the motion of a particle which repeats itself. Hence, a back-and-forth motion that repeats itself is termed as a vibration.

Hence, option (b) is correct.

Reason for the incorrect options:

Option (a) is incorrect because spring itself does not create back-and-forth motion. When the spring is attached with a mass at its end and can compress or stretch, then the motion it creates is back-and-forth motion about its unstretched position. So, it is a wrong answer.

Option (c) is incorrect because the wave is an example of back-and-forth motion but in this case, the movement may or may not involve matter. It does not repeat itself. So, it is a wrong answer.

Option (d) is incorrect because the pulse is a type of non-sinusoidal wave. It is a type of back-and-forth motion, but it does not repeat itself. So, it is a wrong answer.

Hence, options (a), (c) and (d) are incorrect.

Conclusion:

The vibration is a repeating back-and-forth motion.

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Answer 3

Question

Chapter 5, Problem 1AC

To determine

The term used for the repeating back-and-forth motion, from the following options.

spring.

vibration.

wave.

pulse.

Expert Solution & Answer

Answer to Problem 1AC

Solution:

Option (b) is correct.

Explanation of Solution

Reason for the correct options:

The term vibration is used for the motion of a particle which repeats itself. Hence, a back-and-forth motion that repeats itself is termed as a vibration.

Hence, option (b) is correct.

Reason for the incorrect options:

Option (a) is incorrect because spring itself does not create back-and-forth motion. When the spring is attached with a mass at its end and can compress or stretch, then the motion it creates is back-and-forth motion about its unstretched position. So, it is a wrong answer.

Option (c) is incorrect because the wave is an example of back-and-forth motion but in this case, the movement may or may not involve matter. It does not repeat itself. So, it is a wrong answer.

Option (d) is incorrect because the pulse is a type of non-sinusoidal wave. It is a type of back-and-forth motion, but it does not repeat itself. So, it is a wrong answer.

Hence, options (a), (c) and (d) are incorrect.

Conclusion:

The vibration is a repeating back-and-forth motion.

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Answer 4

Question

Chapter 5, Problem 1AC

To determine

The term used for the repeating back-and-forth motion, from the following options.

spring.

vibration.

wave.

pulse.

Expert Solution & Answer

Answer to Problem 1AC

Solution:

Option (b) is correct.

Explanation of Solution

Reason for the correct options:

The term vibration is used for the motion of a particle which repeats itself. Hence, a back-and-forth motion that repeats itself is termed as a vibration.

Hence, option (b) is correct.

Reason for the incorrect options:

Option (a) is incorrect because spring itself does not create back-and-forth motion. When the spring is attached with a mass at its end and can compress or stretch, then the motion it creates is back-and-forth motion about its unstretched position. So, it is a wrong answer.

Option (c) is incorrect because the wave is an example of back-and-forth motion but in this case, the movement may or may not involve matter. It does not repeat itself. So, it is a wrong answer.

Option (d) is incorrect because the pulse is a type of non-sinusoidal wave. It is a type of back-and-forth motion, but it does not repeat itself. So, it is a wrong answer.

Hence, options (a), (c) and (d) are incorrect.

Conclusion:

The vibration is a repeating back-and-forth motion.

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Answer 5

Chapter 5, Problem 1AC

To determine

The term used for the repeating back-and-forth motion, from the following options.

spring.

vibration.

wave.

pulse.

Expert Solution & Answer

Answer to Problem 1AC

Solution:

Option (b) is correct.

Explanation of Solution

Reason for the correct options:

The term vibration is used for the motion of a particle which repeats itself. Hence, a back-and-forth motion that repeats itself is termed as a vibration.

Hence, option (b) is correct.

Reason for the incorrect options:

Option (a) is incorrect because spring itself does not create back-and-forth motion. When the spring is attached with a mass at its end and can compress or stretch, then the motion it creates is back-and-forth motion about its unstretched position. So, it is a wrong answer.

Option (c) is incorrect because the wave is an example of back-and-forth motion but in this case, the movement may or may not involve matter. It does not repeat itself. So, it is a wrong answer.

Option (d) is incorrect because the pulse is a type of non-sinusoidal wave. It is a type of back-and-forth motion, but it does not repeat itself. So, it is a wrong answer.

Hence, options (a), (c) and (d) are incorrect.

Conclusion:

The vibration is a repeating back-and-forth motion.

Answer 6

Chapter 5, Problem 1AC

To determine

The term used for the repeating back-and-forth motion, from the following options.

spring.

vibration.

wave.

pulse.

Expert Solution & Answer

Answer to Problem 1AC

Solution:

Option (b) is correct.

Explanation of Solution

Reason for the correct options:

The term vibration is used for the motion of a particle which repeats itself. Hence, a back-and-forth motion that repeats itself is termed as a vibration.

Hence, option (b) is correct.

Reason for the incorrect options:

Option (a) is incorrect because spring itself does not create back-and-forth motion. When the spring is attached with a mass at its end and can compress or stretch, then the motion it creates is back-and-forth motion about its unstretched position. So, it is a wrong answer.

Option (c) is incorrect because the wave is an example of back-and-forth motion but in this case, the movement may or may not involve matter. It does not repeat itself. So, it is a wrong answer.

Option (d) is incorrect because the pulse is a type of non-sinusoidal wave. It is a type of back-and-forth motion, but it does not repeat itself. So, it is a wrong answer.

Hence, options (a), (c) and (d) are incorrect.

Conclusion:

The vibration is a repeating back-and-forth motion.

Answer 7

Chapter 5, Problem 1AC

To determine

The term used for the repeating back-and-forth motion, from the following options.

spring.

vibration.

wave.

pulse.

Answer 8

Expert Solution & Answer

Answer to Problem 1AC

Solution:

Option (b) is correct.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Reason for the correct options:

The term vibration is used for the motion of a particle which repeats itself. Hence, a back-and-forth motion that repeats itself is termed as a vibration.

Hence, option (b) is correct.

Reason for the incorrect options:

Option (a) is incorrect because spring itself does not create back-and-forth motion. When the spring is attached with a mass at its end and can compress or stretch, then the motion it creates is back-and-forth motion about its unstretched position. So, it is a wrong answer.

Option (c) is incorrect because the wave is an example of back-and-forth motion but in this case, the movement may or may not involve matter. It does not repeat itself. So, it is a wrong answer.

Option (d) is incorrect because the pulse is a type of non-sinusoidal wave. It is a type of back-and-forth motion, but it does not repeat itself. So, it is a wrong answer.

Hence, options (a), (c) and (d) are incorrect.

Conclusion:

The vibration is a repeating back-and-forth motion.