The feet of a standing person of mass m exert a force equal to mg on the floor, and the floor exerts an equal and opposite force upwards on the feet, which we call the normal force. During the extension phase of a vertical jump (see page 145), the feet exert a force on the floor that is greater than mg, so the normal force is greater than mg. As you learned in Chapter 4, we can use this result and Newton’s second law to calculate the acceleration of the jumper: a = Fnet/m = (n - mg)/m.Using energy ideas, we know that work is performed on the jumper to give him or her kinetic energy. But the normal force can’t perform any work here, because the feet don’t undergo any displacement. How is energy transferred to the jumper?
The feet of a standing person of mass m exert a force equal to mg on the floor, and the floor exerts an equal and opposite force upwards on the feet, which we call the normal force. During the extension phase of a vertical jump (see page 145), the feet exert a force on the floor that is greater than mg, so the normal force is greater than mg. As you learned in Chapter 4, we can use this result and Newton’s second law to calculate the acceleration of the jumper: a = Fnet/m = (n - mg)/m.Using energy ideas, we know that work is performed on the jumper to give him or her kinetic energy. But the normal force can’t perform any work here, because the feet don’t undergo any displacement. How is energy transferred to the jumper?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The feet of a standing person of mass m exert a force equal to mg on the floor, and the floor exerts an equal and opposite force upwards on the feet, which we call the normal force. During the extension phase of a vertical jump (see page 145), the feet exert a force on the floor that is greater than mg, so the normal force is greater than mg. As you learned in Chapter 4, we can use this result and Newton’s second law to calculate the acceleration of the jumper: a = Fnet/m = (n - mg)/m.
Using energy ideas, we know that work is performed on the jumper to give him or her kinetic energy. But the normal force can’t perform any work here, because the feet don’t undergo any displacement. How is energy transferred to the jumper?
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