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Concept explainers
A cylindrical container of radius r and height L is partially filled with a liquid whose volume is V. If the container is rotated about its axis of symmetry with constant angular speed ω, then the container will induce a rotational motion in the liquid around the same axis. Eventually, the liquid will be rotating at the same angular speed as the container. The surface of the liquid will be convex, as indicated in the figure, because the centrifugal force on the liquid particles increases with the distance from the axis of the container. It can be shown that the surface of the liquid is a paraboloid of revolution generated by rotating the parabola
about the y-axis, where g is the acceleration due to gravity.
(a) Determine h as a function of ω.
(b) At what angular speed will the surface of the liquid touch the bottom? At what speed will it spill over the top?
(c) Suppose the radius of the container is 2 ft, the height is 7 ft, and the container and liquid are rotating at the same constant angular speed. The surface of the liquid is 5 ft below the top of the tank at the central axis and 4 ft below the top of the tank 1 ft out from the central axis.
(i) Determine the angular speed of the container and the volume of the fluid.
(ii) How far below the top of the tank is the liquid at the wall of the container?
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Chapter 5 Solutions
Single Variable Calculus
- This question builds on an earlier problem. The randomized numbers may have changed, but have your work for the previous problem available to help with this one. A 4-centimeter rod is attached at one end to a point A rotating counterclockwise on a wheel of radius 2 cm. The other end B is free to move back and forth along a horizontal bar that goes through the center of the wheel. At time t=0 the rod is situated as in the diagram at the left below. The wheel rotates counterclockwise at 1.5 rev/sec. At some point, the rod will be tangent to the circle as shown in the third picture. B A B at some instant, the piston will be tangent to the circle (a) Express the x and y coordinates of point A as functions of t: x= 2 cos(3πt) and y= 2 sin(3πt) (b) Write a formula for the slope of the tangent line to the circle at the point A at time t seconds: -cot (3πt) (c) Express the x-coordinate of the right end of the rod at point B as a function of t: 2 cos(3πt) +41/1 (d) Express the slope of the rod…arrow_forward4. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.5.024. Find the approximations Tη, Mn, and S, to the integral computer algebra system.) ASK YOUR TEACHER PRACTICE ANOTHER 4 39 √ dx for n = 6 and 12. Then compute the corresponding errors ET, EM, and Es. (Round your answers to six decimal places. You may wish to use the sum command on a n Tn Mn Sp 6 12 n ET EM Es 6 12 What observations can you make? In particular, what happens to the errors when n is doubled? As n is doubled, ET and EM are decreased by a factor of about Need Help? Read It ' and Es is decreased by a factor of aboutarrow_forward6. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.5.001. ASK YOUR TEACHER PRACTICE ANOTHER Let I = 4 f(x) dx, where f is the function whose graph is shown. = √ ² F(x 12 4 y f 1 2 (a) Use the graph to find L2, R2 and M2. 42 = R₂ = M₂ = 1 x 3 4arrow_forward
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- 2. The size of a claim is modelled by F(a, λ) with a fixed a a maximum likelihood estimate of A given a sample x with a sample mean x = 11 = 121. Give [5 Marks]arrow_forwardRobbie Bearing Word Problems Angles name: Jocelyn date: 1/18 8K 2. A Delta airplane and an SouthWest airplane take off from an airport at the same time. The bearing from the airport to the Delta plane is 23° and the bearing to the SouthWest plane is 152°. Two hours later the Delta plane is 1,103 miles from the airport and the SouthWest plane is 1,156 miles from the airport. What is the distance between the two planes? What is the bearing from the Delta plane to the SouthWest plane? What is the bearing to the Delta plane from the SouthWest plane? Delta y SW Angles ThreeFourthsMe MATH 2arrow_forwardFind the derivative of the function. m(t) = -4t (6t7 - 1)6arrow_forward
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