a.
To calculate: We are asked to find the inequality for the given situation.
a.
Answer to Problem 11PT
8x+10y<=300
Explanation of Solution
Given information: Student ticket costs $8 per ticket and Adult ticket costs $10 per ticket.And the class can spend up to $300.
Calculation:
Let’s assign variable for the number of students as ‘x’ and number of adults as ‘y’.
So, x number student ticket costs 8x
y number of adult costs 10y.
They can not spend not more than $300.
So, we can set up inequality as 8x+10y = 300.
b.
To calculate: Is it possible for the entire class to go to the zoo?
b.
Answer to Problem 11PT
Yes! The entire class can go for zoo.
Explanation of Solution
Given information: There are 32 students in the class. There are 1 adult for each 8 students.
Calculation:
There are 1 adult for each 8 students.
There four 8 students that’s there are 32 students.
So, we need 4 teachers.
That’s for 32 students, there are 4 teachers.
Plug in x as 32 and y as 4 into the inequality and check.
8(32)+10(4) =300
256 +40 =300
296 =300
The inequality is true. It means entire class can go for zoo.
Chapter 5 Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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