EBK OPERATIONS MANAGEMENT
14th Edition
ISBN: 9781260718447
Author: Stevenson
Publisher: MCG COURSE
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 4.S, Problem 4P
A product engineer has developed the following equation for the cost of a system component C = (10P)2, where C is the cost in dollars and P is the probability that the component will operate as expected. The system is composed of two identical components, both of which must operate for the system to operate. The engineer can spend $173 for the two components. To the nearest two decimal places, what is the largest component probability that can be achieved?
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
A product engineer has developed the following equation for the cost of a system component: C = (10P)2, where C is the cost in dollars and P is the probability that the component will operate as expected. The system is composed of 3 identical components, all of which must operate for the system to operate. The engineer can spend $254 for the 3 components. What is the largest component probability that can be achieved? (Do not round your intermediate calculations. Round your final answer to 4 decimal places.) Probability 0.8466
A product engineer has developed the following equation for the cost of a system component: C = (10P)2, where is the cost in dollars and Pis the probability that the component will operate as expected. The system is composed of two identical components, both of which must operate for the system to operate. The engineer can spend $173 for the two components. To the nearest two decimal places, what is the largest component probability that can be achieved?
A product engineer has developed the following equation for the cost of a system component: C = (10P) 2, where C is the cost in dollars and P is the probability that the component will operate as expected. The system is composed of two identical components, both of which must operate forthe system to operate. The engineer can spend $173 for the two components. To the nearest two decimal places, what is the largest component probability that can be achieved?
Chapter 4 Solutions
EBK OPERATIONS MANAGEMENT
Ch. 4.2 - Prob. 1.1RQCh. 4.2 - Prob. 1.2RQCh. 4.5 - Prob. 1.1RQCh. 4.5 - Prob. 1.2RQCh. 4.7 - Prob. 1.1RQCh. 4.7 - Prob. 1.2RQCh. 4.7 - Prob. 1.3RQCh. 4.8 - Prob. 1.1RQCh. 4.8 - Prob. 1.2RQCh. 4.11 - THE CHALLENGES OF MANAGING SERVICES Services can...
Ch. 4.11 - THE CHALLENGES OF MANAGING SERVICES Services can...Ch. 4.S - Prob. 1DRQCh. 4.S - Prob. 2DRQCh. 4.S - Prob. 3DRQCh. 4.S - Consider the following system: Determine the...Ch. 4.S - A product is composed of four parts. In order for...Ch. 4.S - A system consists of three identical components....Ch. 4.S - A product engineer has developed the following...Ch. 4.S - The guidance system of a ship is controlled by a...Ch. 4.S - One of the industrial robots designed by a leading...Ch. 4.S - A production line has three machines A, B, and C,...Ch. 4.S - Prob. 8PCh. 4.S - A Web server has five major components that must...Ch. 4.S - Repeat Problem 9 under the condition that one of...Ch. 4.S - Hoping to increase the chances of reaching a...Ch. 4.S - An electronic chess game has a useful life that is...Ch. 4.S - A manufacturer of programmable calculators is...Ch. 4.S - Lucky Lumen light bulbs have an expected life that...Ch. 4.S - Prob. 15PCh. 4.S - Prob. 16PCh. 4.S - Determine the availability for each of these...Ch. 4.S - Prob. 20PCh. 4.S - A manager must decide between two machines. The...Ch. 4.S - Prob. 22PCh. 4.S - Auto batteries have an average life of 2.7 years....Ch. 4 - Prob. 1DRQCh. 4 - Prob. 2DRQCh. 4 - Prob. 3DRQCh. 4 - Prob. 4DRQCh. 4 - Prob. 5DRQCh. 4 - Prob. 6DRQCh. 4 - Prob. 7DRQCh. 4 - Prob. 8DRQCh. 4 - a. What is meant by the term life cycle? b. Why...Ch. 4 - Prob. 10DRQCh. 4 - Prob. 11DRQCh. 4 - Prob. 12DRQCh. 4 - Prob. 13DRQCh. 4 - Explain what quality function development is and...Ch. 4 - Prob. 15DRQCh. 4 - Prob. 16DRQCh. 4 - Prob. 17DRQCh. 4 - Prob. 18DRQCh. 4 - Prob. 19DRQCh. 4 - Describe some of the trade-off that are...Ch. 4 - Prob. 2TSCh. 4 - Prob. 3TSCh. 4 - Prob. 1CTECh. 4 - Prob. 2CTECh. 4 - Prob. 3CTECh. 4 - Prob. 4CTECh. 4 - Prob. 5CTECh. 4 - Give two examples of unethical conduct involving...Ch. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prepare a service blueprint for each of these...Ch. 4 - Prepare a service blueprint for each of these post...Ch. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prepare a table similar to that shown in Problem...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, operations-management and related others by exploring similar questions and additional content below.Similar questions
- Consider a product that is "settled in." Its MTBF distribution has been found to be normal with a mean of 10,000 hours and a standard deviation of 100 hours. Answer the following questions: (a) Calculate the probability of a breakdown before 8,000 hours? (b) Calculate the probability of a breakdown before 9,000 hours? (c) Would you prefer a policy of “preventive maintenance” or a policy of “breakdown maintenance” on this product? Explain your choice.arrow_forwardA Florida lottery machine and printer at Store #8302 operates 360 days a year. If the machine does not work and breaks down, it costs the Florida Lottery Commission $2,160 per day. If store employees are trained to perform local tests on the machine each day plus the costs of machine repairpersons, these preventive maintenance costs average $850 per day. If preventive maintenance is performed daily, the probability the equipment fails is zero. The probability of store lottery machine breakdown is as follows. Number of Lottery Machine Breakdowns per Day 0 1 1/3 Probability of a breakdown What are the economics of the situation? Do not round intermediate calculations. Round your answers to the nearest dollar. The expected cost of a breakdown per day is $ The Florida Lottery Commission saves $ by performing preventive maintenance daily. 2 1/3 1/3 per yeararrow_forwardA system consists of three identical components. In order for the system to perform as intended, all of the components must perform. Each has the same probability of performance. If the system is to have a .92 probability of performing, what is the minimum probability of performing needed byeach of the individual components?arrow_forward
- A product design engineer must decide if a redundant component is cost justified in a certain system. The system in question has a critical component with a probability of 0.96 of operating. System failure would involve a cost of GH¢20,000. What is the probability that the system will fail? Probability of the system failing is Blank 1. Fill in the blank, read surrounding text.arrow_forwardA major television manufacturer has determined that its 40-inch LED televisions have a meanservice life that can be modeled by a normal distribution with a mean of six years and a standarddeviation of one-half year.a. What probability can you assign to service lives of at least (1) five years? (2) six years? (3)seven and one-half years?arrow_forwardA product is composed of four parts. In order for the product to function properly in a given situation, each of the parts must function. Two of the parts have a 0.96 probability of functioning, and two have a probability of 0.99. (Leave your answers in 4 decimal places).arrow_forward
- Determine the optimum preventive maintenance frequency for each of the pieces of equipment if breakdown time is normally distributed: (Round "Probability Ratio" to 4 decimal places, and all other answers to 2 decimal places. Negative values should be indicated by a minus sign.) Use Table. Equipment. A201 B400 C850 Equipment A201 B400 CB50 Equipment Average Time (days) between Breakdowns A201 B400 C850 20 30 45 Preventive Maintenance Cost Click here for the Excel Data File: $330 $230 $580 Probability Ratio Standard Deviation 3 Breakdown Cont $2,230 $3,530 $4,825 Interval (days)arrow_forward2. A product design engineer must decide if a redundant component is cost-justified in a certain system. The system in question has a critical component with a probability of 0.98 of operating. System failure would involve a cost of $20000. For a cost of $100 a switch could be added that would automatically transfer the system to the backup in the event of failure. Should the backup be added if the backup probability is also 0.98?arrow_forwardAt DataTech Solutions, the reliability of their server systems is a critical factor in maintaining smooth operations. The company knows that the probability of a server experiencing no downtime due to technical issues is 0.95. When a server is functioning smoothly, there is a 0.9 probability that the network performance is also optimal. However, if a server encounters technical problems, the probability of having optimal network performance drops to 0.3. A server is chosen at random for assessment, and its network performance is found to be optimal. What is the updated probability that the server is running without any technical issues?arrow_forward
- a factory that produces a small number of items per day. In about 30% of working days the factory produces 7 units of the product, in 45% of working days it produces 8 units, and the rest of working days it produces 9 units. After production is completed, each unit is thoroughly inspected. Each unit fails inspection with probability ??. If two or more units fail inspection on the same day, the factory closes for a week to re-calibrate equipment. Say the factory opens today after being closed for a week, write a mathematical expression to calculate the probability that the factory will remain open at least 30 days before closing again.arrow_forwardAssume that a company is considering buying a new piece of equipment for $240,000 that would have a useful life of five years and no salvage value. The equipment would generate the following estimated annual revenues and expenses: Commissions Insurance Revenues $ 112,400 Less operating expenses: $ 15,000 5,000 48,000 30,000 98,000 $ 14,400 Depreciation Maintenance Net operating income Click here to view Exhibit 12B-1 and Exhibit 12B-2, to determine the appropriate discount factor(s) using the tables provided. The internal rate of return for this investment is closest toarrow_forwardA typical retail transaction consists of several smaller steps, which can be considered components subject to failure. A list of such components might include: Let the eight probabilities of success be .92, .94, .99, .99, .98, .97,.95, and .96. What is the reliability of the system; that is, the probabilitythat there will be a satisfied customer? If you were the storemanager, what do you think should be an acceptable value forthis probability? Which components would be good candidatesfor backup, which for redesign?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Practical Management ScienceOperations ManagementISBN:9781337406659Author:WINSTON, Wayne L.Publisher:Cengage,
Practical Management Science
Operations Management
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:Cengage,
Process selection and facility layout; Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=wjxS79880MM;License: Standard YouTube License, CC-BY