Explanation Calculation: To find the position function, integrate the given velocity function. ∫ v ( t ) d t = ∫ 4 t + sin t d t s ( t ) = 4 ∫ t d t + ∫ sin t d t = 4 t 2 2 − cos t + C = 2 t 2 − cos t + C From the given initial condition, s ( t ) = 0 when t = 0

Calculus, Single Variable: Early Transcendentals (3rd Edition)

3rd Edition

ISBN: 9780134766850

Author: William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz

Publisher: PEARSON

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Chapter 4.9, Problem 96E

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To find: The position function whose velocity function is v(t)=4t+sint; s(0)=0.

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Chapter 4.9, Problem 95E

Chapter 4.9, Problem 97E

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Chapter 4 Solutions

Calculus, Single Variable: Early Transcendentals (3rd Edition)

Ch. 4.1 - Sketch the graph of a function that is continuous...Ch. 4.1 - Consider the function f(x) = x3. Where is the...Ch. 4.1 - Sketch the graph of a function that is continuous...Ch. 4.1 - Sketch the graph of a function that has an...Ch. 4.1 - What is a critical point of a function?Ch. 4.1 - Sketch the graph of a function f that has a local...Ch. 4.1 - Sketch the graph of a function f that has a local...Ch. 4.1 - Absolute maximum/minimum values Use the following...Ch. 4.1 - Prob. 12E Ch. 4.1 - Absolute maximum/minimum values Use the following...

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The position function whose velocity function is v ( t ) = 4 t + sin t ; s ( 0 ) = 0 .

Solution Summary: The author explains how to find the position function whose velocity function is v(t)=4t+mathrmsint;

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To find: The position function whose velocity function is v(t)=4t+sint; s(0)=0.

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Chapter 4 Solutions