AUTOMOTIVE TECHNOLOGY TECH MANUAL
7th Edition
ISBN: 9781337794220
Author: ERJAVEC
Publisher: CENGAGE L
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Chapter 49, Problem 7SA
In what direction must the bottom of a tire and wheel assembly be moved to add more positive camber?
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Chapter 49 Solutions
AUTOMOTIVE TECHNOLOGY TECH MANUAL
Ch. 49 - Define camber.Ch. 49 - What tire wear pattern will result from excessive...Ch. 49 - What can be caused by excessive negative caster?Ch. 49 - Describe the difference between toe-in and...Ch. 49 - Describe thrust angle and why it is important foi...Ch. 49 - What can cause incorrect toe-out-on-turns?Ch. 49 - In what direction must the bottom of a tire and...Ch. 49 - What is scrub radius and why is it important?Ch. 49 - Prob. 9SACh. 49 - Describe how caster adjustment may be used to com...
Ch. 49 - A 3-degree difference in the SAI angle on each...Ch. 49 - Prob. 12SACh. 49 - Which of the following is a good definition of...Ch. 49 - Unequal SAI angles on the left and right sides of...Ch. 49 - While driving straight, a FWD car pulls to the...Ch. 49 - Technician A says that negative caster provides...Ch. 49 - Technician A says that the purpose of the steering...Ch. 49 - Technician A says that the presence of a thrust...Ch. 49 - Technician A says that camber changes as the...Ch. 49 - Technician A says that caster can be adjusted on...Ch. 49 - Technician A says that on FWD vehicles, the front...Ch. 49 - Technician A says that if caster at both wheels is...Ch. 49 - While discussing front-wheel caster: Technician A...Ch. 49 - While performing a prealignment inspection:...Ch. 49 - While performing a prealignment inspection:...
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- Determine the moments of the force about the x and the a axes. O 4 m F = {-40i +20j + 10k} N 3 m 6 m aarrow_forward6. A part of the structure for a factory automation system is a beam that spans 30.0 in as shown in Figure P5-6. Loads are applied at two points, each 8.0 in from a support. The left load F₁ = 1800 lb remains constantly applied, while the right load F₂ = 1800 lb is applied and removed fre- quently as the machine cycles. Evaluate the beam at both B and C. A 8 in F₁ = 1800 lb 14 in F2 = 1800 lb 8 in D RA B C 4X2X1/4 Steel tube Beam cross section RDarrow_forward30. Repeat Problem 28, except using a shaft that is rotating and transmitting a torque of 150 N⚫m from the left bear- ing to the middle of the shaft. Also, there is a profile key- seat at the middle under the load.arrow_forward
- 28. The shaft shown in Figure P5-28 is supported by bear- ings at each end, which have bores of 20.0 mm. Design the shaft to carry the given load if it is steady and the shaft is stationary. Make the dimension a as large as pos- sible while keeping the stress safe. Determine the required d = 20mm D = ? R = ?| 5.4 kN d=20mm Length not to scale -a = ?- +а= a = ? + -125 mm- -250 mm- FIGURE P5-28 (Problems 28, 29, and 30)arrow_forward12. Compute the estimated actual endurance limit for SAE 4130 WQT 1300 steel bar with a rectangular cross sec- tion of 20.0 mm by 60 mm. It is to be machined and subjected to repeated and reversed bending stress. A reli- ability of 99% is desired.arrow_forward28. The shaft shown in Figure P5-28 is supported by bear- ings at each end, which have bores of 20.0 mm. Design the shaft to carry the given load if it is steady and the shaft is stationary. Make the dimension a as large as pos- sible while keeping the stress safe. Determine the required d = 20mm D = ? R = ?| 5.4 kN d=20mm Length not to scale -a = ?- +а= a = ? + -125 mm- -250 mm- FIGURE P5-28 (Problems 28, 29, and 30)arrow_forward
- 2. A strut in a space frame has a rectangular cross section of 10.0 mm by 30.0 mm. It sees a load that varies from a tensile force of 20.0 kN to a compressive force of 8.0 kN.arrow_forwardfind stress at Qarrow_forwardI had a theoretical question about attitude determination. In the attached images, I gave two axis and angles. The coefficient of the axes are the same and the angles are the same. The only difference is the vector basis. Lets say there is a rotation going from n hat to b hat. Then, you introduce a intermediate rotation s hat. So, I want to know if the DCM produced from both axis and angles will be the same or not. Does the vector basis affect the numerical value of the DCM? The DCM formula only cares about the coefficient of the axis and the angle. So, they should be the same right?arrow_forward
- 3-15. A small fixed tube is shaped in the form of a vertical helix of radius a and helix angle y, that is, the tube always makes an angle y with the horizontal. A particle of mass m slides down the tube under the action of gravity. If there is a coefficient of friction μ between the tube and the particle, what is the steady-state speed of the particle? Let y γ 30° and assume that µ < 1/√3.arrow_forwardThe plate is moving at 0.6 mm/s when the force applied to the plate is 4mN. If the surface area of the plate in contact with the liquid is 0.5 m^2, deterimine the approximate viscosity of the liquid, assuming that the velocity distribution is linear.arrow_forward3-9. Given that the force acting on a particle has the following components: Fx = −x + y, Fy = x − y + y², F₂ = 0. Solve for the potential energy V. -arrow_forward
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