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(a)
The pitch diameter of the spur gear.
Answer to Problem 63A
The pitch diameter is 25 mm.
Explanation of Solution
Given:
Module (m) = 2.5mm
Number of teeth = 10
Concept Used:
Calculation:
Conclusion:
The pitch diameter is 25 mm.
(b)
The circular pitch of the spur gear.
Answer to Problem 63A
The circular pitch is 7.854 mm.
Explanation of Solution
Given:
Module (m) = 2.5 mm
Number of teeth = 10
Concept Used:
Calculation:
Conclusion:
The circular pitch is 7.854 mm.
(c)
The outside diameter of the spur gear.
Answer to Problem 63A
The outside diameter is 30 mm.
Explanation of Solution
Given:
Module (m) = 2.5 mm
Number of teeth = 10
Concept Used:
Calculation:
Conclusion:
The outside diameter is 30 mm.
(d)
The addendum of the spur gear.
Answer to Problem 63A
The addendum is 2.5 mm.
Explanation of Solution
Given:
Module (m) = 2.5 mm
Number of teeth = 10
Concept Used:
Calculation:
Conclusion:
The addendum is 2.5 mm.
(e)
The working depth of the spur gear.
Answer to Problem 63A
The working depth is 5 mm.
Explanation of Solution
Given:
Module (m) = 2.5 mm
Number of teeth = 10
Concept Used:
Calculation:
Conclusion:
The working depth is 5 mm.
(f)
The tooth thickness of the spur gear.
Answer to Problem 63A
The thickness of the tooth is 3.927 mm.
Explanation of Solution
Given:
Module (m) = 2.5 mm
Number of teeth = 10
Concept Used:
Calculation:
Conclusion:
The thickness of the tooth is 3.927 mm.
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Chapter 48 Solutions
Mathematics For Machine Technology
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