(a) The pitch diameter of the spur gear.

Question

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Answer 1

Question

Chapter 48, Problem 63A

To determine

(a)

The pitch diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The pitch diameter is 25 mm.

Explanation of Solution

Given:

Module (m) = 2.5mm

Number of teeth = 10

Concept Used:

module=pitch diameternumber of teeth

Calculation:

module(m)=pitch diameter(D)number of teeth(N)pitch diameter=mNpitch diameter=2.5×10 mmpitch diameter=25 mm

Conclusion:

The pitch diameter is 25 mm.

To determine

(b)

The circular pitch of the spur gear.

Expert Solution

Answer to Problem 63A

The circular pitch is 7.854 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For spur gear,Circular pitch(PC)=3.1416×Pitch diameter(D)Number of teeth(N)

Calculation:

For spur gear,Circular pitch(PC)=3.1416DNPC=3.1416×2510PC=7.854 mm

Conclusion:

The circular pitch is 7.854 mm.

To determine

(c)

The outside diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The outside diameter is 30 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

Pitch(P)=Number of teeth(N)Pitch diameter(D)Outside diameter(Do)=N+2P

Calculation:

Pitch(P)=Number of teeth(N)Pitch diameter(D)P=1025P=0.4Outside diameter(Do)=N+2PDo=10+20.4Do=30 mm

Conclusion:

The outside diameter is 30 mm.

To determine

(d)

The addendum of the spur gear.

Expert Solution

Answer to Problem 63A

The addendum is 2.5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

addendum=0.3183×Circular pitch(PC)

Calculation:

addendum(a)=0.3183PCa=0.3183×7.854 mma=2.5 mm

Conclusion:

The addendum is 2.5 mm.

To determine

(e)

The working depth of the spur gear.

Expert Solution

Answer to Problem 63A

The working depth is 5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)

Calculation:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)WD=20.4WD=5 mm

Conclusion:

The working depth is 5 mm.

To determine

(f)

The tooth thickness of the spur gear.

Expert Solution

Answer to Problem 63A

The thickness of the tooth is 3.927 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)

Calculation:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)T=1.57080.4T=3.927 mm

Conclusion:

The thickness of the tooth is 3.927 mm.

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Answer 2

Question

Chapter 48, Problem 63A

To determine

(a)

The pitch diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The pitch diameter is 25 mm.

Explanation of Solution

Given:

Module (m) = 2.5mm

Number of teeth = 10

Concept Used:

module=pitch diameternumber of teeth

Calculation:

module(m)=pitch diameter(D)number of teeth(N)pitch diameter=mNpitch diameter=2.5×10 mmpitch diameter=25 mm

Conclusion:

The pitch diameter is 25 mm.

To determine

(b)

The circular pitch of the spur gear.

Expert Solution

Answer to Problem 63A

The circular pitch is 7.854 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For spur gear,Circular pitch(PC)=3.1416×Pitch diameter(D)Number of teeth(N)

Calculation:

For spur gear,Circular pitch(PC)=3.1416DNPC=3.1416×2510PC=7.854 mm

Conclusion:

The circular pitch is 7.854 mm.

To determine

(c)

The outside diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The outside diameter is 30 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

Pitch(P)=Number of teeth(N)Pitch diameter(D)Outside diameter(Do)=N+2P

Calculation:

Pitch(P)=Number of teeth(N)Pitch diameter(D)P=1025P=0.4Outside diameter(Do)=N+2PDo=10+20.4Do=30 mm

Conclusion:

The outside diameter is 30 mm.

To determine

(d)

The addendum of the spur gear.

Expert Solution

Answer to Problem 63A

The addendum is 2.5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

addendum=0.3183×Circular pitch(PC)

Calculation:

addendum(a)=0.3183PCa=0.3183×7.854 mma=2.5 mm

Conclusion:

The addendum is 2.5 mm.

To determine

(e)

The working depth of the spur gear.

Expert Solution

Answer to Problem 63A

The working depth is 5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)

Calculation:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)WD=20.4WD=5 mm

Conclusion:

The working depth is 5 mm.

To determine

(f)

The tooth thickness of the spur gear.

Expert Solution

Answer to Problem 63A

The thickness of the tooth is 3.927 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)

Calculation:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)T=1.57080.4T=3.927 mm

Conclusion:

The thickness of the tooth is 3.927 mm.

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Answer 3

Question

Chapter 48, Problem 63A

To determine

(a)

The pitch diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The pitch diameter is 25 mm.

Explanation of Solution

Given:

Module (m) = 2.5mm

Number of teeth = 10

Concept Used:

module=pitch diameternumber of teeth

Calculation:

module(m)=pitch diameter(D)number of teeth(N)pitch diameter=mNpitch diameter=2.5×10 mmpitch diameter=25 mm

Conclusion:

The pitch diameter is 25 mm.

To determine

(b)

The circular pitch of the spur gear.

Expert Solution

Answer to Problem 63A

The circular pitch is 7.854 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For spur gear,Circular pitch(PC)=3.1416×Pitch diameter(D)Number of teeth(N)

Calculation:

For spur gear,Circular pitch(PC)=3.1416DNPC=3.1416×2510PC=7.854 mm

Conclusion:

The circular pitch is 7.854 mm.

To determine

(c)

The outside diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The outside diameter is 30 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

Pitch(P)=Number of teeth(N)Pitch diameter(D)Outside diameter(Do)=N+2P

Calculation:

Pitch(P)=Number of teeth(N)Pitch diameter(D)P=1025P=0.4Outside diameter(Do)=N+2PDo=10+20.4Do=30 mm

Conclusion:

The outside diameter is 30 mm.

To determine

(d)

The addendum of the spur gear.

Expert Solution

Answer to Problem 63A

The addendum is 2.5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

addendum=0.3183×Circular pitch(PC)

Calculation:

addendum(a)=0.3183PCa=0.3183×7.854 mma=2.5 mm

Conclusion:

The addendum is 2.5 mm.

To determine

(e)

The working depth of the spur gear.

Expert Solution

Answer to Problem 63A

The working depth is 5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)

Calculation:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)WD=20.4WD=5 mm

Conclusion:

The working depth is 5 mm.

To determine

(f)

The tooth thickness of the spur gear.

Expert Solution

Answer to Problem 63A

The thickness of the tooth is 3.927 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)

Calculation:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)T=1.57080.4T=3.927 mm

Conclusion:

The thickness of the tooth is 3.927 mm.

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Answer 4

Question

Chapter 48, Problem 63A

To determine

(a)

The pitch diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The pitch diameter is 25 mm.

Explanation of Solution

Given:

Module (m) = 2.5mm

Number of teeth = 10

Concept Used:

module=pitch diameternumber of teeth

Calculation:

module(m)=pitch diameter(D)number of teeth(N)pitch diameter=mNpitch diameter=2.5×10 mmpitch diameter=25 mm

Conclusion:

The pitch diameter is 25 mm.

To determine

(b)

The circular pitch of the spur gear.

Expert Solution

Answer to Problem 63A

The circular pitch is 7.854 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For spur gear,Circular pitch(PC)=3.1416×Pitch diameter(D)Number of teeth(N)

Calculation:

For spur gear,Circular pitch(PC)=3.1416DNPC=3.1416×2510PC=7.854 mm

Conclusion:

The circular pitch is 7.854 mm.

To determine

(c)

The outside diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The outside diameter is 30 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

Pitch(P)=Number of teeth(N)Pitch diameter(D)Outside diameter(Do)=N+2P

Calculation:

Pitch(P)=Number of teeth(N)Pitch diameter(D)P=1025P=0.4Outside diameter(Do)=N+2PDo=10+20.4Do=30 mm

Conclusion:

The outside diameter is 30 mm.

To determine

(d)

The addendum of the spur gear.

Expert Solution

Answer to Problem 63A

The addendum is 2.5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

addendum=0.3183×Circular pitch(PC)

Calculation:

addendum(a)=0.3183PCa=0.3183×7.854 mma=2.5 mm

Conclusion:

The addendum is 2.5 mm.

To determine

(e)

The working depth of the spur gear.

Expert Solution

Answer to Problem 63A

The working depth is 5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)

Calculation:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)WD=20.4WD=5 mm

Conclusion:

The working depth is 5 mm.

To determine

(f)

The tooth thickness of the spur gear.

Expert Solution

Answer to Problem 63A

The thickness of the tooth is 3.927 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)

Calculation:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)T=1.57080.4T=3.927 mm

Conclusion:

The thickness of the tooth is 3.927 mm.

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Answer 5

Chapter 48, Problem 63A

To determine

(a)

The pitch diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The pitch diameter is 25 mm.

Explanation of Solution

Given:

Module (m) = 2.5mm

Number of teeth = 10

Concept Used:

module=pitch diameternumber of teeth

Calculation:

module(m)=pitch diameter(D)number of teeth(N)pitch diameter=mNpitch diameter=2.5×10 mmpitch diameter=25 mm

Conclusion:

The pitch diameter is 25 mm.

To determine

(b)

The circular pitch of the spur gear.

Expert Solution

Answer to Problem 63A

The circular pitch is 7.854 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For spur gear,Circular pitch(PC)=3.1416×Pitch diameter(D)Number of teeth(N)

Calculation:

For spur gear,Circular pitch(PC)=3.1416DNPC=3.1416×2510PC=7.854 mm

Conclusion:

The circular pitch is 7.854 mm.

To determine

(c)

The outside diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The outside diameter is 30 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

Pitch(P)=Number of teeth(N)Pitch diameter(D)Outside diameter(Do)=N+2P

Calculation:

Pitch(P)=Number of teeth(N)Pitch diameter(D)P=1025P=0.4Outside diameter(Do)=N+2PDo=10+20.4Do=30 mm

Conclusion:

The outside diameter is 30 mm.

To determine

(d)

The addendum of the spur gear.

Expert Solution

Answer to Problem 63A

The addendum is 2.5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

addendum=0.3183×Circular pitch(PC)

Calculation:

addendum(a)=0.3183PCa=0.3183×7.854 mma=2.5 mm

Conclusion:

The addendum is 2.5 mm.

To determine

(e)

The working depth of the spur gear.

Expert Solution

Answer to Problem 63A

The working depth is 5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)

Calculation:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)WD=20.4WD=5 mm

Conclusion:

The working depth is 5 mm.

To determine

(f)

The tooth thickness of the spur gear.

Expert Solution

Answer to Problem 63A

The thickness of the tooth is 3.927 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)

Calculation:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)T=1.57080.4T=3.927 mm

Conclusion:

The thickness of the tooth is 3.927 mm.

Answer 6

Chapter 48, Problem 63A

To determine

(a)

The pitch diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The pitch diameter is 25 mm.

Explanation of Solution

Given:

Module (m) = 2.5mm

Number of teeth = 10

Concept Used:

module=pitch diameternumber of teeth

Calculation:

module(m)=pitch diameter(D)number of teeth(N)pitch diameter=mNpitch diameter=2.5×10 mmpitch diameter=25 mm

Conclusion:

The pitch diameter is 25 mm.

Answer 7

Chapter 48, Problem 63A

To determine

(a)

The pitch diameter of the spur gear.

Answer 8

Expert Solution

Answer to Problem 63A

The pitch diameter is 25 mm.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given:

Module (m) = 2.5mm

Number of teeth = 10

Concept Used:

module=pitch diameternumber of teeth

Calculation:

module(m)=pitch diameter(D)number of teeth(N)pitch diameter=mNpitch diameter=2.5×10 mmpitch diameter=25 mm

Conclusion:

The pitch diameter is 25 mm.

Answer 13

To determine

(b)

The circular pitch of the spur gear.

Expert Solution

Answer to Problem 63A

The circular pitch is 7.854 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For spur gear,Circular pitch(PC)=3.1416×Pitch diameter(D)Number of teeth(N)

Calculation:

For spur gear,Circular pitch(PC)=3.1416DNPC=3.1416×2510PC=7.854 mm

Conclusion:

The circular pitch is 7.854 mm.

Answer 14

To determine

(b)

The circular pitch of the spur gear.

Answer 15

Expert Solution

Answer to Problem 63A

The circular pitch is 7.854 mm.

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For spur gear,Circular pitch(PC)=3.1416×Pitch diameter(D)Number of teeth(N)

Calculation:

For spur gear,Circular pitch(PC)=3.1416DNPC=3.1416×2510PC=7.854 mm

Conclusion:

The circular pitch is 7.854 mm.

Answer 20

To determine

(c)

The outside diameter of the spur gear.

Expert Solution

Answer to Problem 63A

The outside diameter is 30 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

Pitch(P)=Number of teeth(N)Pitch diameter(D)Outside diameter(Do)=N+2P

Calculation:

Pitch(P)=Number of teeth(N)Pitch diameter(D)P=1025P=0.4Outside diameter(Do)=N+2PDo=10+20.4Do=30 mm

Conclusion:

The outside diameter is 30 mm.

Answer 21

To determine

(c)

The outside diameter of the spur gear.

Answer 22

Expert Solution

Answer to Problem 63A

The outside diameter is 30 mm.

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

Pitch(P)=Number of teeth(N)Pitch diameter(D)Outside diameter(Do)=N+2P

Calculation:

Pitch(P)=Number of teeth(N)Pitch diameter(D)P=1025P=0.4Outside diameter(Do)=N+2PDo=10+20.4Do=30 mm

Conclusion:

The outside diameter is 30 mm.

Answer 27

To determine

(d)

The addendum of the spur gear.

Expert Solution

Answer to Problem 63A

The addendum is 2.5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

addendum=0.3183×Circular pitch(PC)

Calculation:

addendum(a)=0.3183PCa=0.3183×7.854 mma=2.5 mm

Conclusion:

The addendum is 2.5 mm.

Answer 28

To determine

(d)

The addendum of the spur gear.

Answer 29

Expert Solution

Answer to Problem 63A

The addendum is 2.5 mm.

Answer 30

Expert Solution

Answer 31

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

addendum=0.3183×Circular pitch(PC)

Calculation:

addendum(a)=0.3183PCa=0.3183×7.854 mma=2.5 mm

Conclusion:

The addendum is 2.5 mm.

Answer 34

To determine

(e)

The working depth of the spur gear.

Expert Solution

Answer to Problem 63A

The working depth is 5 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)

Calculation:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)WD=20.4WD=5 mm

Conclusion:

The working depth is 5 mm.

Answer 35

To determine

(e)

The working depth of the spur gear.

Answer 36

Expert Solution

Answer to Problem 63A

The working depth is 5 mm.

Answer 37

Expert Solution

Answer 38

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)

Calculation:

For a spur gear,Working depth(WD)=2.000Pitch of the gear(P)WD=20.4WD=5 mm

Conclusion:

The working depth is 5 mm.

Answer 41

To determine

(f)

The tooth thickness of the spur gear.

Expert Solution

Answer to Problem 63A

The thickness of the tooth is 3.927 mm.

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)

Calculation:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)T=1.57080.4T=3.927 mm

Conclusion:

The thickness of the tooth is 3.927 mm.

Answer 42

To determine

(f)

The tooth thickness of the spur gear.

Answer 43

Expert Solution

Answer to Problem 63A

The thickness of the tooth is 3.927 mm.

Answer 44

Expert Solution

Answer 45

Expert Solution

Answer 46

Expert Solution

Answer 47

Explanation of Solution

Given:

Module (m) = 2.5 mm

Number of teeth = 10

Concept Used:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)

Calculation:

For a spur gear,Thickness of a tooth(T)=1.5708Pitch of the gear(P)T=1.57080.4T=3.927 mm

Conclusion:

The thickness of the tooth is 3.927 mm.

Answer 48

Ch. 48 - Prob. 1A Ch. 48 - Prob. 2A Ch. 48 - Prob. 3A Ch. 48 - Prob. 4A Ch. 48 - Prob. 5A Ch. 48 - Read the setting on the following 0.001-inch...Ch. 48 - Prob. 7A Ch. 48 - Refer to the Decimal-Inch Spur Gears Table under...Ch. 48 - Prob. 9A Ch. 48 - Prob. 10A

(a) The pitch diameter of the spur gear.

Videos

(a)

The pitch diameter of the spur gear.

Answer to Problem 63A

Explanation of Solution

(b)

The circular pitch of the spur gear.

Answer to Problem 63A

Explanation of Solution

(c)

The outside diameter of the spur gear.

Answer to Problem 63A

Explanation of Solution

(d)

The addendum of the spur gear.

Answer to Problem 63A

Explanation of Solution

(e)

The working depth of the spur gear.

Answer to Problem 63A

Explanation of Solution

(f)

The tooth thickness of the spur gear.

Answer to Problem 63A

Explanation of Solution

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Chapter 48 Solutions

(a) The pitch diameter of the spur gear.

Videos

(a) The pitch diameter of the spur gear.

Answer to Problem 63A

Explanation of Solution

(b) The circular pitch of the spur gear.

Answer to Problem 63A

Explanation of Solution

(c) The outside diameter of the spur gear.

Answer to Problem 63A

Explanation of Solution

(d) The addendum of the spur gear.

Answer to Problem 63A

Explanation of Solution

(e) The working depth of the spur gear.

Answer to Problem 63A

Explanation of Solution

(f) The tooth thickness of the spur gear.

Answer to Problem 63A

Explanation of Solution

Want to see more full solutions like this?

Chapter 48 Solutions

(a)

The pitch diameter of the spur gear.

(b)

The circular pitch of the spur gear.

(c)

The outside diameter of the spur gear.

(d)

The addendum of the spur gear.

(e)

The working depth of the spur gear.

(f)

The tooth thickness of the spur gear.