Explanation It is given that, the third derivative is f ‴ ( t ) = e t + t − 4 . Integrate the function f ‴ ( t ) = e t + t − 4 as, ∫ ( e t + t − 4 ) d t = ∫ e t d t + ∫ t − 4 d t = e t + t − 4 + 1 − 4 + 1 + C = e t + t − 3 − 3 + C = e t − t − 3 3 + C Once again integrate e t − t − 3 3 + C as, ∫ ( e t − t − 3 3 + C ) d t = ∫ e t d t − 1 3 ∫ t − 3 d t + C ∫ d t = e t − 1 3 ( t − 3 + 1 − 3 + 1 ) +

Essential Calculus: Early Transcendentals

2nd Edition

ISBN: 9781133112280

Author: James Stewart

Publisher: Cengage Learning

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Chapter 4.7, Problem 22E

To determine

The antiderivative of the function given that f‴(t)=et+t−4.

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Chapter 4.7, Problem 21E

Chapter 4.7, Problem 23E

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Essential Calculus: Early Transcendentals

Ch. 4.1 - Explain the difference between an absolute minimum...Ch. 4.1 - Suppose f is a continuous function defined on a...Ch. 4.1 - For each of the numbers a, b, c, d, r, and s,...Ch. 4.1 - For each of the numbers a, b, c, d, r, and s,...Ch. 4.1 - Use the graph to state the absolute and local...Ch. 4.1 - Use the graph to state the absolute and local...Ch. 4.1 - Sketch the graph of a function f that is...Ch. 4.1 - 710 Sketch the graph of a function f that is...Ch. 4.1 - 710 Sketch the graph of a function f that is...Ch. 4.1 - 710 Sketch the graph of a function f that is...

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The antiderivative of the function given that f ‴ ( t ) = e t + t − 4 .

Solution Summary: The author explains the antiderivative of the function f′′′(t)=et

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The antiderivative of the function given that f‴(t)=et+t−4.

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Chapter 4 Solutions