Algorithm complexity The complexity of a computer algorithm is the number of operations or steps the algorithm needs to complete its task assuming there are n pieces of input (for example, the number of steps needed to put n numbers in ascending order). Four algorithms for doing the same task have complexities of A: n 3/2 , B: n log 2 n , C: n (log 2 n ) 2 , and D: n log 2 n . Rank the algorithms in order of increasing efficiency for large values of n . Graph the complexities as they vary with n and comment on your observations.
Algorithm complexity The complexity of a computer algorithm is the number of operations or steps the algorithm needs to complete its task assuming there are n pieces of input (for example, the number of steps needed to put n numbers in ascending order). Four algorithms for doing the same task have complexities of A: n 3/2 , B: n log 2 n , C: n (log 2 n ) 2 , and D: n log 2 n . Rank the algorithms in order of increasing efficiency for large values of n . Graph the complexities as they vary with n and comment on your observations.
Solution Summary: The author explains the ranking order of the algorithms from least to most efficient is A, C, B, D.
Algorithm complexity The complexity of a computer algorithm is the number of operations or steps the algorithm needs to complete its task assuming there are n pieces of input (for example, the number of steps needed to put n numbers in ascending order). Four algorithms for doing the same task have complexities of A: n3/2, B: n log2n, C: n(log2n)2, and D:
n
log
2
n
. Rank the algorithms in order of increasing efficiency for large values of n. Graph the complexities as they vary with n and comment on your observations.
4c
Consider the function f(x) = 10x + 4x5 - 4x³- 1.
Enter the general antiderivative of f(x)
A tank contains 60 kg of salt and 2000 L of water. Pure water enters a tank at the rate 8 L/min. The
solution is mixed and drains from the tank at the rate 11 L/min.
Let y be the number of kg of salt in the tank after t minutes.
The differential equation for this situation would be:
dy
dt
y(0) =
Solve the initial value problem:
y= 0.05y + 5
y(0) = 100
y(t) =
Chapter 4 Solutions
Single Variable Calculus: Early Transcendentals (2nd Edition) - Standalone book
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