85. f(x) = &r* – 2x² + 5x – 1; [0, 1 ] 86. f(x) = x* + &r – x² + 2; [-1, 0] A 87. f(x) = 2x³ + 6x? – &x + 2; [-5, –4] 88. f(x) = 3x – 10x + 9; [-3, –2] %3D 89. f(x) = x – xrt + 7.x – 7x2 – 18r + 18; [1.4, 1.5] 90. f(x) = x – 3x* – 2r³ + 6x² + x + 2; [1.7, 1.8]
85. f(x) = &r* – 2x² + 5x – 1; [0, 1 ] 86. f(x) = x* + &r – x² + 2; [-1, 0] A 87. f(x) = 2x³ + 6x? – &x + 2; [-5, –4] 88. f(x) = 3x – 10x + 9; [-3, –2] %3D 89. f(x) = x – xrt + 7.x – 7x2 – 18r + 18; [1.4, 1.5] 90. f(x) = x – 3x* – 2r³ + 6x² + x + 2; [1.7, 1.8]
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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In Problems 85–90, use the Intermediate Value Theorem to show that each function has a zero in the given interval. Approximate the zero
correct to two decimal places.
![85. f(x) = &r* – 2x² + 5x – 1; [0, 1 ]
86. f(x) = x* + &r – x² + 2; [-1, 0]
A 87. f(x) = 2x³ + 6x? – &x + 2; [-5, –4]
88. f(x) = 3x – 10x + 9; [-3, –2]
%3D
89. f(x) = x – xrt + 7.x – 7x2 – 18r + 18; [1.4, 1.5]
90. f(x) = x – 3x* – 2r³ + 6x² + x + 2; [1.7, 1.8]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff43ea5f9-57f6-46b2-b339-e72389a9c7b5%2Fcb9a6dff-8963-40e7-ad5b-8fff012d28a8%2Fouyq082_processed.png&w=3840&q=75)
Transcribed Image Text:85. f(x) = &r* – 2x² + 5x – 1; [0, 1 ]
86. f(x) = x* + &r – x² + 2; [-1, 0]
A 87. f(x) = 2x³ + 6x? – &x + 2; [-5, –4]
88. f(x) = 3x – 10x + 9; [-3, –2]
%3D
89. f(x) = x – xrt + 7.x – 7x2 – 18r + 18; [1.4, 1.5]
90. f(x) = x – 3x* – 2r³ + 6x² + x + 2; [1.7, 1.8]
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