Explanation Given Information: The distance from the stop sign (in feet) t seconds after stepping on the breaks is given by the function, s ( t ) = 3 t 3 − 12 t 2 − 9 t + 54 By differentiation , s ( t ) = 3 t 3 − 12 t 2 − 9 t + 54 d s ( t ) d t = 9 t 2 − 24 t − 9 v ( t ) = 9 t 2 − 24 t − 9 ∫ 0 v v ( t ) d t = ∫ 0 4.6 ( 9 t 2 − 24 t − 9 ) d t ∫ 0 v v ( t ) d t = [ 9 t 3 3 ] 0 4

5th Edition

ISBN: 9781429241861

Author: Laura Taalman, Peter Kohn

Publisher: W. H. Freeman

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differentia…

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Chapter 4.6, Problem 4TF

To determine

To Find: the average velocity using the distance function and differentiating it.

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Chapter 4.6, Problem 3TF

Chapter 4.6, Problem 5TF

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Chapter 4 Solutions

Calculus

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the average velocity using the distance function and differentiating it.

Solution Summary: The author calculates the average velocity using the distance function and differentiating it. The distance from the stop sign (in feet) is given by the function.

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To Find: the average velocity using the distance function and differentiating it.

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Chapter 4 Solutions